Why does changing an x-value affect the mean but not the variation?

  • Thread starter Thread starter bob4000
  • Start date Start date
  • Tags Tags
    Mean Variation
AI Thread Summary
Changing an x-value in a list affects the mean because the mean is the average of all values, while the variation, which measures the spread of those values, remains unaffected if all values are shifted equally. When only one value is altered, both the mean and the variance change due to the new distribution of values. The formula for the mean is the sum of all values divided by the number of values, while variance is calculated based on the squared differences from the mean. This distinction explains why the mean is sensitive to changes in individual values, whereas variation reflects the overall distribution. Understanding these mathematical principles clarifies the relationship between mean and variation in statistics.
bob4000
Messages
40
Reaction score
0
mathematically why does the mean change when an x-value is changed in a list, but the variation doesn't. if someone could show me a relevant formula which can satisfy this or any other info i would be very grateful for

thnak you
 
Physics news on Phys.org
If you change all the values on the list by the same amount, the mean changes with it, but the variance, which measures the fluctuations around the mean doesn't change. If you shift one value only, both the mean and the variance will change.
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...
Back
Top