Why Does Heat Come from the Air to Melt Ice in Water?

AI Thread Summary
Heat from the air is necessary to melt the ice cube in water at 0 degrees Celsius because heat flow requires a temperature difference; without it, the water and ice would stabilize at the same temperature, halting further melting. The surrounding air provides the necessary heat to facilitate this process. The discussion also touches on entropy changes, clarifying that the total entropy change of the universe should include contributions from the ice, water, and air, rather than just the ice and water. This highlights the interconnectedness of heat transfer and entropy in thermodynamic systems. Understanding these principles is crucial for grasping the dynamics of phase changes in thermal environments.
Chronos000
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Homework Statement



an ice cube is melted in water which is continuously stirred to be at a constant temperature of 0 degrees. the stirring is gentle enough so the work done is negligible.

my question is why in this case does the heat come from the air to melt the ice cube and not the water. why can't it be a bit of both or just the water.

also, for the total entropy change of the universe, wouldn't I just consider the S:ice + S:water = S:air?
 
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Chronos000 said:

Homework Statement



an ice cube is melted in water which is continuously stirred to be at a constant temperature of 0 degrees. the stirring is gentle enough so the work done is negligible.

my question is why in this case does the heat come from the air to melt the ice cube and not the water. why can't it be a bit of both or just the water.
Heat flow requires a temperature difference. Without heat flowing from the air to the water/ice, the water and the ice would reach and remain at the same temperature, 0C, and then there would be no further heat flow. So heat flow must occur from the surroundings to the water/ice.
also, for the total entropy change of the universe, wouldn't I just consider the S:ice + S:water = S:air?
The total entropy change is:

\Delta S_{universe} = \Delta S_{ice} + \Delta S_{water} + \Delta S_{air}

AM
 
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