- #71
Tom.G
Science Advisor
Gold Member
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At least for testing and measurement purposes you can get a relative measurement of the AVC at a lower impedance point.
On the schematic, look at the S-Meter pot, notice there is a 270K resistor going upward. The other end of the 270K is connected to 1Meg and 50K resistors.
The voltage at this junction of the 3 resistors will be approximately twice the AVC voltage; more importantly it is much lower impedance, about 50K.
This point may even be adequate for your final configuration by connecting a non-inverting op-amp stage to it as a buffer. The advantage of a non-inverting stage is that the input impedance is close to infinite, thereby not loading the AVC line.
There is very little filtering at this point so a low pass filter would be needed somewhere after the buffer to match the 15mS delay in the AVC.
Of course you could use the same approach of connecting a non-inverting op-amp buffer to the AVC line itself, with no additional delay/filtering needed (maybe).
Either way, you still need a Negative supply voltage that is more negative than the voltage you are measuring.
Cheers,
Tom
On the schematic, look at the S-Meter pot, notice there is a 270K resistor going upward. The other end of the 270K is connected to 1Meg and 50K resistors.
The voltage at this junction of the 3 resistors will be approximately twice the AVC voltage; more importantly it is much lower impedance, about 50K.
This point may even be adequate for your final configuration by connecting a non-inverting op-amp stage to it as a buffer. The advantage of a non-inverting stage is that the input impedance is close to infinite, thereby not loading the AVC line.
There is very little filtering at this point so a low pass filter would be needed somewhere after the buffer to match the 15mS delay in the AVC.
Of course you could use the same approach of connecting a non-inverting op-amp buffer to the AVC line itself, with no additional delay/filtering needed (maybe).
Either way, you still need a Negative supply voltage that is more negative than the voltage you are measuring.
Cheers,
Tom