- #1
find_the_fun
- 148
- 0
The question is solve, give transient term and interval of solution for \(\displaystyle x \frac{dy}{dx}-y = x^2 \sin{x}\) and the answer key has \(\displaystyle y=cx-x\cos{x}\) and \(\displaystyle (0, \infty)\). Why wouldn't the interval be \(\displaystyle (-\infty, \infty)\)?