Wind Load Formula: Charles Hutton | A=Fsinx^1.84cos-1

AI Thread Summary
The discussion centers on understanding the wind load formula attributed to Charles Hutton, specifically A = Fsinx^1.84cos-1. Participants clarify that the formula should be interpreted with proper parentheses, leading to Pn = P*(sin theta)^[(1.842*cos theta) - 1]. There is also mention of experimental results that support the formula's application in wind load calculations. The importance of correct grouping in mathematical expressions is emphasized to avoid misinterpretation. Overall, the thread provides insights into the formula's structure and its experimental basis.
cuad
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I'm not sure where to post this, so please excuse me if this is misplaced. I need help understanding how the terms are grouped in this formula for A = pressure normal to the roof. If any of you are familiar with this formula or can link me to a source containing better expressed formulas like this one I'd appreciate your help. I'm posting a screen shot of the formula from a textbook I'm looking at. It looks something like:
A = Fsinx^1.84cos-1

Apparently it's a formula belonging to someone called Charles Hutton and it looks something more like Pn= P(sinx)^(1.842cosx-1) I just want to double check whether the exponent is really (1.842cosx-1) and not something like 1.842cos(x-1).

http://i33.tinypic.com/13z6fqt.jpg
 
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I have never heard of it, but there is another source I found that references it as well (it even talks about the experimental basis for the equation):

When attempting to bring the velocity up to 20
ft. per sec. or 13.6 miles per hour, the thread carrying
the weight broke. These experiments are recorded under
dates of July 24, 25, 31 and Aug. 11. The results ob-
tained were tabulated and the well known formula
Pn = P (sitfx) l -**co*x-i

http://www.archive.org/stream/sixmonographsonw00flemrich/sixmonographsonw00flemrich_djvu.txt
 
cuad: First, from other sources, we know your attached image in post 1 is missing parentheses around sin theta. Secondly, because addition and subtraction have a low precedence of arithmetic operations, unlike multiplication, we know addition and subtraction expressions can be passed to a function only if the addition or subtraction expression argument is enclosed in parentheses, such as cos(x - 1). Therefore, we know the formula is Pn = P*(sin theta)^[(1.842*cos theta) - 1].
 
Hi everyone. Thank you guys for clarifying that for me.
 
I have Mass A being pulled vertically. I have Mass B on an incline that is pulling Mass A. There is a 2:1 pulley between them. The math I'm using is: FA = MA / 2 = ? t-force MB * SIN(of the incline degree) = ? If MB is greater then FA, it pulls FA up as MB moves down the incline. BUT... If I reverse the 2:1 pulley. Then the math changes to... FA = MA * 2 = ? t-force MB * SIN(of the incline degree) = ? If FA is greater then MB, it pulls MB up the incline as FA moves down. It's confusing...
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