- #36
Jax Dax
- 17
- 0
Im not good at the quotes thing so I hope you don't mind a straight answer.
q1
agreed, but let's keep national grid and home grid separate otherwise the convo gets very confusing
We are talking about wind generators for home use, so let's stay within the house.
q2
every transformation of electrical current suffer hysterisis and eddy current losses, magnetic and resistance losses, approximate efficiency is 80 to 90% so the resultant loss is 10 to 20%. each time electricity flows through a transformer. (its why Edison lost the lighting contract, lol)
Also, why should the generator output be transformed like that? same reason we don't only make 4" nails.
-for example, if your house had 12v lights.
a multi wound generator operating 12/220v - 12v would provide lighting power at 0 losses (technicaly) it is rectified and feed into the batteries with 0 loss, the lights consume it with 0 loss, net effect is you have saved 0.6kW of power generated.
lets assume 1kW of power is used by the lights, 220v transformed to 12v inverted to 220v the 1kW is needed by the lights, the generator must supply 1.6kW @ 220v to have the 1kW output for the lights.
1.6 x 0.8 = 1.28kW to the batteries and 1.28 x 0.8 = 1.02kW supplied to the lights
from the equation you can see a bigger battery bank is needed to power the lights
q1
agreed, but let's keep national grid and home grid separate otherwise the convo gets very confusing
We are talking about wind generators for home use, so let's stay within the house.
q2
every transformation of electrical current suffer hysterisis and eddy current losses, magnetic and resistance losses, approximate efficiency is 80 to 90% so the resultant loss is 10 to 20%. each time electricity flows through a transformer. (its why Edison lost the lighting contract, lol)
Also, why should the generator output be transformed like that? same reason we don't only make 4" nails.
-for example, if your house had 12v lights.
a multi wound generator operating 12/220v - 12v would provide lighting power at 0 losses (technicaly) it is rectified and feed into the batteries with 0 loss, the lights consume it with 0 loss, net effect is you have saved 0.6kW of power generated.
lets assume 1kW of power is used by the lights, 220v transformed to 12v inverted to 220v the 1kW is needed by the lights, the generator must supply 1.6kW @ 220v to have the 1kW output for the lights.
1.6 x 0.8 = 1.28kW to the batteries and 1.28 x 0.8 = 1.02kW supplied to the lights
from the equation you can see a bigger battery bank is needed to power the lights