Work and Power of 1.83x10^3 kg Car Accelerating from Rest

Now, we can find the force:F=ma=(1.83x10^3 kg)(4.84m/s^2)=8857 NTo find the work, we need to know the distance the car travels, but it is not given in the problem. So we cannot solve for work.To find the power, we can use the equation p=w/t and plug in the values we know:p=\frac{8857N*v}{t}=\frac{8857N*13.6m/s}{2.81s}=42779 WattsIn summary, the work done on the car cannot be determined without knowing the distance it travels. The power delivered by the engine in this time interval is
  • #1
PepeF.
16
0

Homework Statement


a 1.83x10^3 kg car accelerates uniformly from rest to 13.6m/s in 2.81 s

-what is the work done on the car in this time inerval?

-what is the power delivered by the engine in thsi time interval?



Homework Equations



w=f*d
p=w/t

The Attempt at a Solution



i did the first one, but could not be able to come up with the answer
i multiplied gravity x mass = f then fxd=246568 and its wrong
can you please explain or tell me how to get it
 
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  • #2
PepeF. said:

Homework Statement


a 1.83x10^3 kg car accelerates uniformly from rest to 13.6m/s in 2.81 s

-what is the work done on the car in this time inerval?

-what is the power delivered by the engine in thsi time interval?



Homework Equations



w=f*d
p=w/t

The Attempt at a Solution



i did the first one, but could not be able to come up with the answer
i multiplied gravity x mass = f then fxd=246568 and its wrong
can you please explain or tell me how to get it

Because your acceleration is not gravity, it is the acceleration that is implied in the problem:

[tex]
a=\frac{v_f-v_0}{t}=\frac{13.6m/s-0m/s}{2.81s}=4.84m/s^2
[/tex]
 

FAQ: Work and Power of 1.83x10^3 kg Car Accelerating from Rest

What is the formula for calculating work?

The formula for calculating work is: W = F x d, where W is work, F is force, and d is distance.

How is power related to work?

Power is the rate at which work is done, and it is calculated by dividing work by time: P = W/t.

How do you calculate the force required to accelerate a 1.83x10^3 kg car from rest?

The force required can be calculated using Newton's Second Law: F = m x a, where F is force, m is mass, and a is acceleration.

How long does it take for a 1.83x10^3 kg car to reach a certain speed when accelerating from rest?

The time it takes for the car to reach a certain speed can be calculated using the formula: t = v/a, where t is time, v is final velocity, and a is acceleration.

Can you calculate the kinetic energy of the car when it reaches a certain speed?

Yes, the kinetic energy of the car can be calculated using the formula: K = 1/2 x m x v^2, where K is kinetic energy, m is mass, and v is velocity.

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