World Record Longest Home Run: Roy "Dizzy" Carlyle

  • Thread starter Thread starter Motorboar
  • Start date Start date
  • Tags Tags
    Home
AI Thread Summary
Roy "Dizzy" Carlyle holds the record for the longest home run, measuring 188 meters (618 feet) in a minor-league game. To calculate the initial speed required for this home run, the ball was hit at an angle of 40 degrees from a height of 0.9 meters. A participant initially calculated the speed as 32.97 m/s but later confirmed the correct initial speed is 43.1 m/s. The discussion included troubleshooting errors in calculations, particularly regarding the treatment of acceleration in the equations. Ultimately, the correct approach involves careful handling of the terms to isolate the initial speed accurately.
Motorboar
Messages
6
Reaction score
1

Homework Statement


According to the Guinness Book of World Records, the longest home run ever measured was hit by Roy "Dizzy" Carlyle in a minor-league game. The ball traveled 188m (618 ft.) before landing on the ground outside the ballpark.

Assuming that the ball's initial velocity was 40.0 degrees above the horizontal, and ignoring air resistance, what did the initial speed of the ball need to be to produce such a home run if the ball was hit at a point 0.900 m (3.00ft ) above ground level? Assume that the ground was perfectly flat.

How far would the ball be above a fence 3.00 m (10.0 ft) in height if the fence were 116 m (380ft ) from home plate?

Homework Equations


v0x=v0cos(40)
v0y=v0sin(40)
x-x0=v0xt
y-y0=v0yt+1/2at^2
ay=-o.81
y-y0=-0.9
ax=0
x-x0=188



The Attempt at a Solution


-0.9 =v0sin40t + 1/2(-9.81)t^2
t= 188/v0cos(40)
0 = (v0sin40)(188/v0cos(40))-(4.9)(188/v0cos(40))^2+0.9
graphed it on a calculator to avoid messy algebra and got the wrong answer of 32.97.
No Idea why this is wrong. Any ideas?
 
Physics news on Phys.org
Motorboar said:

Homework Statement


According to the Guinness Book of World Records, the longest home run ever measured was hit by Roy "Dizzy" Carlyle in a minor-league game. The ball traveled 188m (618 ft.) before landing on the ground outside the ballpark.

Assuming that the ball's initial velocity was 40.0 degrees above the horizontal, and ignoring air resistance, what did the initial speed of the ball need to be to produce such a home run if the ball was hit at a point 0.900 m (3.00ft ) above ground level? Assume that the ground was perfectly flat.

How far would the ball be above a fence 3.00 m (10.0 ft) in height if the fence were 116 m (380ft ) from home plate?

Homework Equations


v0x=v0cos(40)
v0y=v0sin(40)
x-x0=v0xt
y-y0=v0yt+1/2at^2
ay=-o.81
y-y0=-0.9
ax=0
x-x0=188



The Attempt at a Solution


-0.9 =v0sin40t + 1/2(-9.81)t^2
t= 188/v0cos(40)
0 = (v0sin40)(188/v0cos(40))-(4.9)(188/v0cos(40))^2+0.9
graphed it on a calculator to avoid messy algebra and got the wrong answer of 32.97.
No Idea why this is wrong. Any ideas?

I got 43.1 m/s... I just went with your numbers. I would try it again.
 
43.1 is the right answer. Did you graph it? I been working with the input for like 30 minutes, do you mind telling me how you plugged it in?
 
Motorboar said:
43.1 is the right answer. Did you graph it? I been working with the input for like 30 minutes, do you mind telling me how you plugged it in?

I just used your numbers. Maybe you squared the term for acceleration incorrectly?

-0.9 = sin40*(188/cos40) - 4.9*(188/Vo*cos40)^2

The Vo cancels out of the first term and the Vo in the second term gets squared so you eventually have to take the square root. It a bit of a pain as you said.
 
If I am not lazy and work it out by hand, I get it. Thanks for your help.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top