Zero's question at Yahoo Answers regarding interpolating to find a z-score

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In summary, Zero's question at Yahoo! Answers is asking for the z-score associated with an area of 2.37, but the table he consulted gives the z-score for an area of 2.38. To interpolate, he uses the ratio 2.38-2.37/0.4913-0.4911, and finds that the z-score is 0.491212.
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MarkFL
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Here is the question:

Z score approximation ?

How do you approximate a z score when you have something like 2.3756Additional Details: how do you interlope ?

Here is a link to the question:

Z score approximation ? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
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  • #2
Re: Zero's quastion at Yahoo! answers regarding interpolating to find a z-score

Hello Zero,

Consulting a table, we find that the $z$-score associated with an area of 2.37 is 0.4911 and for an area of 2.38 is 0.4913.

To interpolate, we may simply use the ratio:

\(\displaystyle \frac{2.38-2.37}{0.4913-0.4911}=\frac{2.3756-2.37}{\Delta z}\)

\(\displaystyle \frac{0.01}{0.0002}=\frac{0.0056}{\Delta z}\)

\(\displaystyle 50=\frac{7}{1250\Delta z}\)

\(\displaystyle \Delta z=\frac{7}{62500}=0.000112\)

And so, we may state:

\(\displaystyle z\approx0.4911+\Delta z=0.491212\)

Using numeric integration, we find:

\(\displaystyle z=\frac{1}{\sqrt{2\pi}}\int_0^{2.3756}e^{-\frac{x^2}{2}}\,dx\approx0.49124\)

To Zero and any other guests viewing this topic, I invite and encourage you to register and post any other normal distribution question in our http://www.mathhelpboards.com/f23/ forum.

Best Regards,

Mark.
 
  • #3
Re: Zero's quastion at Yahoo! answers regarding interpolating to find a z-score

MarkFL said:
Hello Zero,

Consulting a table, we find that the $z$-score associated with an area of 2.37 is 0.4911 and for an area of 2.38 is 0.4913.

To interpolate, we may simply use the ratio:

\(\displaystyle \frac{2.38-2.37}{0.4913-0.4911}=\frac{2.3756-2.37}{\Delta z}\)

\(\displaystyle \frac{0.01}{0.0002}=\frac{0.0056}{\Delta z}\)

\(\displaystyle 50=\frac{7}{1250\Delta z}\)

\(\displaystyle \Delta z=\frac{7}{62500}=0.000112\)

And so, we may state:

\(\displaystyle z\approx0.4911+\Delta z=0.491212\)

Using numeric integration, we find:

\(\displaystyle z=\frac{1}{\sqrt{2\pi}}\int_0^{2.3756}e^{-\frac{x^2}{2}}\,dx\approx0.49124\)

To Zero and any other guests viewing this topic, I invite and encourage you to register and post any other normal distribution question in our http://www.mathhelpboards.com/f23/ forum.

Best Regards,

Mark.

There is something wrong here, probabilities (areas) are in the range 0 to 1 and z scores can be any real number, here they look the other way around. (Which is what the integral at the end would be saying if the z on the left hand side were replaced with p and the variable of integration were z.)

.
 

Related to Zero's question at Yahoo Answers regarding interpolating to find a z-score

1. What is a z-score and why is it important?

A z-score is a statistical measurement that indicates how many standard deviations a data point is above or below the mean of a dataset. It is important because it allows for the comparison of data points from different distributions and can help identify outliers.

2. How do you calculate a z-score?

A z-score can be calculated by subtracting the mean of a dataset from a data point and then dividing by the standard deviation. This formula can be written as (x - μ) / σ, where x is the data point, μ is the mean, and σ is the standard deviation.

3. What is interpolation and how is it used to find a z-score?

Interpolation is a method of estimating unknown values based on known data points. In this case, it can be used to estimate the z-score of a data point that falls between two known z-scores. This is helpful when trying to calculate the z-score of a data point that does not have an exact value in the dataset.

4. What is the purpose of interpolating to find a z-score?

The purpose of interpolating to find a z-score is to accurately estimate the z-score of a data point that falls between two known z-scores. This can help with statistical analysis and identifying outliers in a dataset.

5. Can a z-score be negative?

Yes, a z-score can be negative if the data point is below the mean of the dataset. A negative z-score indicates that the data point is below the mean by a certain number of standard deviations.

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