- #36
russ_watters
Mentor
- 23,187
- 10,409
So perhaps we could see the initial question...? The wording of the initial question makes all the difference here.
russ_watters said:So perhaps we could see the initial question...? The wording of the initial question makes all the difference here.
A plane is standing on a runway that can move (some sort of band conveyer). The plane moves in one direction, while the conveyer moves in the opposite direction. This conveyer has a control system that tracks the plane speed and tunes the speed of the conveyer to be exactly the same (but in opposite direction).
The question is:
Will the plane take off or not? Will it be able to run up and take off?
brewnog said:Sorry, this is not right. The aeroplane's wheels are not powered, - the forward motion of an aeroplane on takeoff is produced by thrust from the engines. For these purposes, it makes no odds what speed the runway is moving relative to the plane, since the undercarriage wheels are free to spin at whatever speed they're being driven at.
mewmew said:No where in the question does it say the plane is stationary in respect to the earth.
Suppose you have an airplane on a runway that is a huge conveyor belt. The conveyor belt moves with the opposite velocity of the plane at all times, what happens when it tries to take off?
I hope you’re talking about some other forum web site, not double threading on this one.mewmew said:So on another forum we are in a huge argument
No this would be the same a stationary runway, the tangential speed of the tire in contact with the runway is always ZERO. The top of the tire would be moving forward at double the speed of the axle. Tires don’t leave skid marks on takeoff.Now, I think we have ...
one in which the runway moves with the opposite speed tangental to the outside of the tire.