12=1 (mod7)
22=4 (mod7)
32=2 (mod7)
42=2 (mod7)
52=4 (mod7)
62=1 (mod7)
72=0 (mod7)
Is it periodic {1,4,2,2,4,1,0} ? Now I know :-) It's periodic, so if I add any of these congruences together there will be some remainder. Remainder is zero if and only if I add congruences in form
(7k)2=0 (mod7)...