- #386
Rasalhague
- 1,387
- 2
Doc Al said:No, just the opposite. (Assuming I understand what you mean by "input frame".)
In the so-called "time dilation" formula, you start with a time interval measured on a moving clock (the "input", I suppose) and use the formula to compute what the lab frame would measure for that time interval (the "output" of the formula). The "output" is always bigger than the "input".
The "lab frame" is the frame of the observer whose measurements we want to calculate; the "moving frame" is the frame in which the clock in question is at rest.
By input I mean the value you start with (what's given, known), and by output the value you want to calculate (what's unknown). But if your lab frame is what I was calling input frame (the frame in which the known value is a coordinate), and your moving frame what I was calling output frame, what happens when we have a question of the inverse type and want to calculate a smaller output, as in Michael Fowler's example? Well, we've seen what happens (output < input), but what would you call this operation, how would you labels the frames and values involved in that operation?
http://galileoandeinstein.physics.virginia.edu/lectures/time_dil.html
There the output is smaller than the input. Although he doesn't explicitly call this operation time dilation, he does refer to 1 / gamma as "the time dilation factor", even though multiplication by this number results in a smaller number. If making a number bigger is called dilating it, then I'd expect making a number smaller to be called contracting it, whatever that number represents. But here, and generally, the convention seems to be that whatever is done to a number is called dilation if the number happens to represent a portion of time, and whatever is done to a number is called contraction if the number happens to represent a portion of distance.
Doc Al said:For example, I observe a clock moving past me as it goes from position A to position B. My rest frame is the lab frame; my cohorts and I in our frame have measured the time interval (on our lab frame clocks, of course) for the clock to pass from A to B. Call that time interval ΔT. What time interval does the clock itself record (the "moving" frame, to us)? Call that time interval ΔT0. The time dilation formula relates those two time intervals: ΔT = gamma*ΔT0. This is just a precise statement of the loose phrase "moving clocks run slow".
Here you've reversed the labels you proposed above where you defined the movng clock as the input, and the lab as the output. Was that intentional? If distinguishing input from output isn't the defining feature of your labels lab and moving, what is? In this example, ΔT is lab time = input (what we're given). ΔT0 is moving clock time = output (what we want to calculate). The output will be smaller than the input, as in Michael Fowler's example (with positions A and B corresponding to C1 and C2). To solve the equation in the form you give it for ΔT0 we have to divide both sides by gamma. ΔT0 = ΔT / gamma. Since the number has been made smaller, it makes more sense to call what we did contraction than dilation. If this is the sense behind the motto "moving clocks run slow", then apparently it does refer to the operation of contracting (making smaller) a quantity, and matches the everyday idea that if a clock runs slow it will show a smaller number than it would otherwise, or than a clock relative to which which it's running slow.
Doc Al said:Where do you get the idea that "dilation" means anything other than it does in normal usage? To "dilate" means to expand--get bigger.
Apart from the convention I mentioned above, and your own use of the term "time dilation" in the example for an operation whose effect was to shrink a number, there seems to be a further ambiguity about the term, as applied to a measurement. Taylor and Wheeler in Spacetime Physics, you and Jesse all - unless I'm mistaken - take it to refer to the operation of making the number bigger (t' = t * gamma; using the prime symbol here simply to denote output value), that is increasing the quantity/number/amount of time units, whereas Matheinste in #383, and perhaps others, interpret it in the sense of the individual units getting bigger and therefore it taking less of them to fill up a specified interval. Thus Matheinste wrote:
"Is there perhaps some confusion here between number of ticks and duration between ticks. When we say that clocks moving relative to a given frame run slow when compared with that frame we mean that the moving clock ticks slower, that is the time between ticks is dilated ( longer or greater or bigger ). However the number of ticks will be decreased ( contracted, smaller , less in number), it records less time. I think the standard and accepted usage is that time dilates for a moving clock, that is the time between ticks is longer. I have never seen it used any other way."
I don't know if Matheinste would, on the basis of this, call t' = t / gamma time dilation, and t' = t * gamma time contraction. Wolfram Alpha, like Michael Fowler, treats both equations under the heading "time dilation". They use the term "moving time" for the (output of?) t' = t * gamma, and "stationary time" for t' = t / gamma. On the other hand, it seems that they reverse the meanings of moving and stationary for "length contraction", so as to maintain the traditional pairing t' = t * gamma and l' = l / gamma.
http://www01.wolframalpha.com/input/?i=time+dilation
Doc Al said:I'm familiar with that site. I don't see anything there that would contradict the usual usage of the term "time dilation".
Realize that the "time dilation" formula applies to time readings on a single moving clock. You cannot take a time interval measured in the moving frame using multiple clocks, blindly apply the time dilation formula, and expect it to to give the correct time interval measured in another frame*. When multiple clocks are involved you must also include the effects of clock desynchronization (the relativity of simultaneity). All of this is factored in automatically when you use the full Lorentz transformations.
*I suspect that this is at the root of your confusion.
Aren't the effects of desynchronisation all part and parcel of time dilation/contraction anyway, however we look at it, hence the symmetry between frames that you referred to in #370? The Taylor/Wheeler book begins with a visualisation of an orthogonal grid filling space, made of meter sticks with clocks at the vertices. Each frame is conceptualised as such a grid. So multiple clocks are implied in any measurement. The "time dilation" formula could be conceptualised as making one clock explicit and suppresses the rest. But in order to visualise the way the time shown by this clock relates to times that are shown by clocks moving relative to it, or the way it would relate to the time shown by a notional clock moving at some speed relative to it, if there was such a clock, I've been tending to explicitly imagine comparisons between two physical clocks. Part of my motivation was to make it more concrete. Part was because I feared it would be all to easy, as a beginner, to slip into thinking of one frame as privileged. But comparison between two clocks is made in plenty of the examples and explanations of "time dilation" that I've read: be they clocks with rotating hands, or light clocks or short-lived muons or identical twins. Of course, we don't need to picture all these clocks to make the calculation, and we could think of it in more abstract geometric terms: input = the proper time of some separation; output = the time component of that separation in some frame (or the other way around, in the case of time contraction).