If I draw the fbd then some force will accelerate the car in horizontal direction which I think does not effect the string in vertical direction. So same tension regardless of acceleration.
But we know it will increase. So what will be the correct physics behind it?
What would the forces acting only on a passenger in a car going at constant speed on a level surface be? Of course, there would be weight and the reactive force acting on any passenger, but is there a horizontal net force? Or are there just the forces acting on the car and there are no...
Some car lift service centers want to lift up the car by using the suspensions. I always told them to lift by the pinch weld jack points near the tires. Are there some suspension system where the service center can lift the entire car by via the suspensions. And are there some cars which they can't?
This is the problem,
This is the textbook solution ; i think the textbook solution is not correct!
My thought,
##S_{max}## will be given by $$\frac {dy}{dS}=0$$
$$\frac {dy}{dS}=\frac {-1}{400}S+\frac {1}{5}=0$$
$$S=80$$
It is maximum economy because ##y{''}<0##, i.e by use of the second...
This is one method to fix a tire with hole.
I'd like to understand what happens mechanically to the tire belts and plies when plug method was used to fix the hole. This is part of a tire.
Now imagine you push a tool into the hole (like in the video), would the belt and ply simply have...
In the solution manual, it says that:
the resultant of friction force is ##<= kmg##, hence $$m\sqrt{\omega_t^2 + (\frac {v^2} {R})^2} <= kmg$$
and from this equation, we will get $$v^2 <= R \sqrt{(kg)^2 -\omega_t^2}$$
which will make ##v_{max}^2= R \sqrt{(kg)^2 -\omega_t^2}##
Finally, they...
Find the question below;
For part (a), i used the graph to find ##t=22##
For part (b), i considered the points;
##(8,20)##, ##(13.333,20)## and ##(0,0)##
it follows that,
Area=##\sqrt {25.454(25.454-21.54)(25.454-24.036)(25.454-5.333)}##
##\sqrt {2842.58}##=##53.31##
There may...
Find the problem and the solution below;
Find my approach to the problem.
Considering the motion of the car;
##v=u+at##
##33.333= 26.6667+30a##
##a=0.2222##
Therefore it follows that,
##s##=## ut##+##\frac {1}{2}####at^2##
##s##=##(26.67 ×30 +(0.5×0.222×30^2)##
##s=900##metres
The distance...
This is a textbook problem (Mechanics).
Attached find the question and respective solution.
This is fine with me, i like trying different ways of solving math related problems. My approach is as shown below.
Using the graph sketch
It follows that,
##s##= ##(35×12)##+##\frac...
Here is the picture (THIS ISN"T A HOMEWORK QUESTION JUST WANT TO UNDERSTAND A CONCEPT)
I don't understand isn't the tire pushing forward not backward becuase of the friction, road is pushing back.
Where exactly have I gone wrong? I think it is the part where I assume that the person gains the deceleration of the car, but I have no other way to proceed in this case. Also please only use the equations that I have posted below, and it would help if you would not use the equation for...
For part 1, I got ## tan \alpha = 1/30 ##
##\alpha = 1.9^{\circ}##
##mgcos(1.9) = 10774N##
I'm a little thrown off by the second part. Are we supposed to assume that in the absence of friction, F = N and then substitute F = ma to solve for this?
Let imagine that car with constant 500HP accelerate but resistance forces don't exist (aero drag,internal friction in engine and transmision,tyer rolling resistance etc etc..)
neglect fuel loss over time..
From 0-100km/h take in 4sec and burn 200mL petrol
Will car accelerate from...
Im for some reason getting 1.58 s for time.
I found 1.75 m as the head start distance and then I do d=d so: 2.45t^2 = 1.75t^2 +1.75
but the answer for "a" should be 6.45s...
i calculated the time difference between each marker, and using the first equation, i solved for V1.
i then used this V1 as V2, time as the first marker (3.75) and used the second equation to solve for V1.
is this method correct? can somebody please verify?
Summary:: My back wheel spins when in the air, but won't when on the ground, help!
My car has two four inch wood wheels on the front and a 12 inch wood wheel on the back, they are securely attached to the axel and I have 1/2 inch ball bearings to connect the axel to the frame. My lever arm is...
Here's what I did so far.
The velocity of the first car is ##v = v_0 +at##
Frame of reference S = the road
Frame of reference S' = the second car
thus, v' is the speed of the first car in the frame of reference S' and v the speed in the frame of reference S.
Here's what make me doubt.
The...
I a car,why do you move back when the car accelerates forward. You move forward when the car accelerates backwards,You move right when the car turns left on a bent road, you move left when the car turns right on a bent road.
What actually makes you move in the opposite direction of the car.
In recent years, I found that many cars, I don't know if their headlamps are original or customized, the light is very bright or sharp, sometimes causing me to see temporary shadow in the eye like camera flash or even a little bit faint. In addition to yellow and white light there are also many...
I need to power a 350W thing inside the car. And I googled about it. What I learned was that there was a 100W fuse inside car lighter jacks so you can't run a 350W inverter. So I have some questions.
1. If you remove the 100W fuse and put a 400W fuse. Can the 350W power inverter sucked up the...
Hi, I'm working on a project to see if deliveries, pick ups, or both combined are better for the environment / more energy efficient / more time efficient. For example, (a) everyone collecting from a farm by bike, (b) vans bringing to supermarkets and then people collecting from supermarkets, or...
I'm looking for a way to keep a liquid under 50°C. This liquid has a thermal conductivity of .1396 and a specific heat of 2.054 both at 40°C. and a constant energy source submerged in it ranging from 16KW to 17.5KW.
I'm barely starting to read about this topic, according some forums, a car...
This looks like a physics question but it's not; it's an automotive question. Suppose you had a car at the top of a gently sloped hill, a 5% grade. You start it and put it in neutral or drive and it starts to roll down. You never place your foot on the brake or the accelerator and suppose the...
0=6-4.9(t^2)
0=-27,7t+Xo
From the first equation,
T= 1.10s
From the second equation,
(Xo/27,7)=t
0=6-4.9((Xo/27,7)^2)
We solve for Xo = 30,65
Now, we have
X=-27,7t+30,65
If t=1,10
Then , -27,7(1,10)+30,65=0,18 which is not equal to 0.
Which means the stone hits the ground first.
Is my answer...
I have several confusion about this question:
1) Since the sand spilling out downwards, it means that there is change in momentum in vertical direction (before the sand spills and after the sand spills) but no change in momentum in horizontal direction so no net force in horizontal direction...
I'm planning to build a 12 foot jon boat that will be car topped on our van. The rated loading on the roof racks is 165 lbs.
To weigh the finished boat, I plan to do the following:
Position the boat upside down in our carport.
Stand on a bathroom scale and lift the front of the boat. Write...
Hello, as you can see i am trying to understand conceptually how the tires during turning create a centripetal force. It was explained to me that as we turn the car tires, the tires similar to a ski or a wedge, now want to push the ground to the side and forward. If the ground was loose, this...
There once was a thread, a short thread, about a flying car.
https://www.physicsforums.com/threads/flying-car.413351/
Move forward 11 years, and a Flying car completes test flight between airports
https://www.bbc.com/news/technology-57651843
I wonder if they've tested in down draft, or...
Summary:: Question: a car of mass 800kg, 3600N driving force experiences resistive forces of 120v Accelerates from rest. Form equation and show max speed is 30 ms^-1, assuming driving force does not change.
my attempt at a solution -I can not see how to rectify it as I don’t think I did...
I solve the following problem, there is a particle of mass ## m_p ## and velocity ## \vec{v}_p ## which collide with sail installed on rail car with mass ## m_c ## resting in the frame of reference associated with it before the collision. The cart is fixed on straight rails for which the vector...
Hello. I am working on a physics project for a simulation title and have stumbled upon on an interesting challenge.
Below is the example from wind tunnel data of a Dodge Viper GTS sports car.
Wheelbase: 2,44m
Lift front axle: 54kg
Negative lift rear axle: 26kg
Can somebody please explain to...
just want check if i got this right. is there anything i can improve or add on this example i have?
Cause and why.
A cause could be bending or twisting of the prop shaft due to high torque. High torque causes high angle of twist and torsion. The high torque cause high shear stress...
Pressing the switch at (A) grounds the “U/T release request” pin of the ECU.
The “U tailgate O/P” pin at (B) then changes state and signals the FET G170.
The connector 586 pin 30 then goes high and powers the tailgate actuator at (C).
If you follow the third pin of the FET, it appears to go to...
I drive a 2019 Kia Stinger (purchased in June, 2019) with 22,000 miles on it. It's been having weak battery issues for a while, and I've ignored it but I really shouldn't, so now I'm trying to diagnose it to see if I need a new battery, new alternator or if there is a deeper electrical system...
BACKGROUND:
I'm thinking of building a flat bottom Jon boat. We don't have room for a boat trailer so I want to load the boat on top of our 2019 Honda Odyssey van. Without a trailer, the boat can be stored on a side against our hollow tile wall. The dimensions of the boat will be:
12 feet...
We know temperature is a measure of average kinetic energy of molecules/particles of a system. Now if a car starts to move, its velocity increases so does its kinetic energy. Therefore all the molecules are gaining velocity too. Shouldn't this increase the temperatre as average kinetic energy of...
[Mentor Note: Two threads with similar titles merged]
First calculate the equivalent force on the car from the max torque.
An average tire is 15 inch diameter = about .2 meter radius
Since T = F X R , F = T/R = 660/.2 = 3300 Newtons.
since F = M X A, A = F/M = 3300/2083 = 1.6 m/sec^2...
Hello, I'm trying to solve this problem but I'm confused with some things, is correct that in the system there are two input forces, the torque and u(t)? I assumed that the system has two free levels, which are the z displacement and theta (rotational movement), so the system has a linear...
My attic gets very hot even with the exhaust fan I installed. I would like to move than heat to my swimming pool. I currently have a FAFCO solar pool heater where the pool pump pumps water up onto my roof and thru the 12' long solar panel and down back into the pool. I would like to free up roof...
I want to calculate maximum gradient ability of my car in 1st gear to reach an estimation number.
The specification of the car is as follows:
Max torque = 155 nm @ 4250 RPM
Curb weight = 1200 kg
1st gear ratio = 3.454
Final Drive ratio = 4.52941
Tire radius = 0.298 (meter)
Acceleration force...
First I figured out the normal force being exerted on the car using the equation above.
Cos(40°)*(1050*9.8) = 7883N
Next, I tried to find out the horizontal component of the normal force by doing:
Cos(50) * 7883 = 5067N
I figured out the angle by using certain geometrical properties.
Next, I...
(I must confess I couldn't get far, owing mostly to the term "an average distance (of 12 cm) from the axis". Axis of the (peached coloured) wheel at the center with the arrow pointing down? Is the arrow the location of the "axis" of the wheel? Let me see.)
Objective : To find the oil pressure...
80km/h = 22.2 m/s
Through momentum: 1940(v_f) = 540 (22.2) + (1400)(-22.2) => v_f = -9.84 m/s
I figured the work that the energy lost in a collision is equal to the work done to crumple the cars. So W = K_i - Kf = [1/2 (540)(22.2)^2 + 1/2(1400)(-22.2)^2] - 1/2(1940)(-9.84)^ 2 = 384110 J
At...