In calculus, the chain rule is a formula to compute the derivative of a composite function. That is, if f and g are differentiable functions, then the chain rule expresses the derivative of their composite f ∘ g — the function which maps x to
f
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{\displaystyle f(g(x))}
— in terms of the derivatives of f and g and the product of functions as follows:
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{\displaystyle (f\circ g)'=(f'\circ g)\cdot g'.}
Alternatively, by letting h = f ∘ g (equiv., h(x) = f(g(x)) for all x), one can also write the chain rule in Lagrange's notation, as follows:
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{\displaystyle h'(x)=f'(g(x))g'(x).}
The chain rule may also be rewritten in Leibniz's notation in the following way. If a variable z depends on the variable y, which itself depends on the variable x (i.e., y and z are dependent variables), then z, via the intermediate variable of y, depends on x as well. In which case, the chain rule states that:
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{\displaystyle {\frac {dz}{dx}}={\frac {dz}{dy}}\cdot {\frac {dy}{dx}}.}
More precisely, to indicate the point each derivative is evaluated at,
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{\displaystyle \left.{\frac {dz}{dx}}\right|_{x}=\left.{\frac {dz}{dy}}\right|_{y(x)}\cdot \left.{\frac {dy}{dx}}\right|_{x}}
.
The versions of the chain rule in the Lagrange and the Leibniz notation are equivalent, in the sense that if
z
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{\displaystyle z=f(y)}
and
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{\displaystyle y=g(x)}
, so that
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{\displaystyle z=f(g(x))=(f\circ g)(x)}
, then
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{\displaystyle \left.{\frac {dz}{dx}}\right|_{x}=(f\circ g)'(x)}
and
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{\displaystyle \left.{\frac {dz}{dy}}\right|_{y(x)}\cdot \left.{\frac {dy}{dx}}\right|_{x}=f'(y(x))g'(x)=f'(g(x))g'(x).}
Intuitively, the chain rule states that knowing the instantaneous rate of change of z relative to y and that of y relative to x allows one to calculate the instantaneous rate of change of z relative to x. As put by George F. Simmons: "if a car travels twice as fast as a bicycle and the bicycle is four times as fast as a walking man, then the car travels 2 × 4 = 8 times as fast as the man."In integration, the counterpart to the chain rule is the substitution rule.
Homework Statement
Problem: Given C is the graph of the equation
2radical3 * sinpi(x)/3 =y^5+5y-3
Homework Equations
(1) Prove that as a set
C= {(x,y) Exists at all Real Numbers Squared | 2radical3 * sinpi(x)/3 =y^5+5y-3
is the graph of a function differentiable on all real...
Homework Statement
Suppose f is differentiable on \mathbb R and \alpha is a real number. Let G(x) = [f(x)]^a
Find the expression for G'(x)
Homework Equations
I'm pretty sure that I got this one right, but I really want to double check and make sure.
The Attempt at a Solution...
Homework Statement
If possible, please check my work for any large errors.
y = 10kl - √k - √l
k = (t/5) + 5
l = 5e^t/10
Evaluate at t = 0 using chain rule.
Homework Equations
y = 10kl - √k - √l
k = (t/5) + 5
l = 5e^t/10
The Attempt at a Solution
= ∂y/∂k * dk/dt + ∂y/∂l * dl/dt
= (10l -...
Homework Statement
I am confused because for each problem there is no equation and for one no intermediate variables.
Compute dy/dt when
a) y = f(t, t^2, t^3)
b) y = g(t, h(t), k(t^2))
Homework Equations
a) y = f(t, t^2, t^3)
b) y = g(t, h(t), k(t^2))
The Attempt at a...
Hello all,
I need some help with this chain rule problem.
\[F(x,y)=f\left (\frac{x-y}{x+y} \right )\]
It is known that:
f'(1)=20,f'(2)=30, f'(3)=40
and
\[f''(1)=5,f''(2)=6,f''(3))=7\]Find
\frac{\partial F}{\partial x}(2,-1)
and
\[\frac{\partial^2 F}{\partial x\partial y}\]The final...
I'm randomly having trouble applying the chain rule to functions (well, 1 function in particular), I was hoping someone could quickly walk me through this simple problem as I don't know where I've gone wrong. I've tried U substitution, chain/product rule, factoring answer...but I just can't see...
Differentiate the following by rule y=(2x2+4x)5
Is the chain rule the right rule to use?
dy/dx=dy/du*du/dx
Let U=2x2+4x
du/dx=4x+4
y=(u)5 → dy/du=5(u)4
dy/dx=5(u)4*4x+4
dy/dx=5(2x2+4x)4*4x+4
dy/dx= 30(2x2+4x)44x
dy/dx= 30(2x216x)4
I'm wondering if I am on the right...
Let $z:\mathbb{R}^2\to \mathbb{R}$ an function of kind $C^2(\mathbb{R}^2)$. What transforms the equation $2\dfrac{\partial^2 z}{\partial x^2}+\dfrac{\partial^2 z}{\partial x\partial y}-\dfrac{\partial^2 z}{\partial y^2}+\dfrac{\partial z}{\partial x}+\dfrac{\partial z}{\partial y}=0$ under the...
Hello,
I need to do this proof here:
I tried but didn't get what I wanted, so I was re-thinking the whole thing.
If I say u=y+ax and v=y-ax, should I do something like (dz/df)*(df/du)*(du/dx)+...?
Because I tried just with u and v (without f and g), and I got almost what I wanted, with a...
Hello all,
I have a problem with second derivatives and chain rule.
I am working on the question attached (sorry, my Latex editor wasn't working...)
I need to find F'(1) and F''(1). I managed to solve F'(1), but I can't figure out F''(1). In the second image attached, you can see the solution...
Hello everyone,
I am reading a proof of the chain rule given in this link: http://kruel.co/math/chainrule.pdf
Here is the portion I am troubled with:
"We know use these equations to rewrite f(g(x+h)). In particular, use the first equation to obtain
f(g(x+h)) = f(g(x) + [g'(x) + v]h)...
Hi fi you look at quesiotn 16b in the following link they try to find dE/dx.
they use the chain rule. the chain rule says dF/dt=dx/dt*dF/dx+dy/dt*dF/dy if F=f(x,y) and x=f(t) and y=f(t).
But in 16b they're trying to find dE/dx and as part of the use of the chain rule they try to find...
Hi, I’m a bit confused.
I am familiar with the chain rule: if y=f(g(t,x),h(t,x)) then dy/dt=dy/dg*dg/dt+dy/dh*dh/dt
To show that an equation is invariant under a galiliean transform, it’s partially necessary to show that the equation takes the same form both for x and for x’=x-v(T). So if you...
Hello everyone, first post here.
Homework Statement
Let f(x,y)=x2y+y2x , where x=sin2t
and y=cos2t.
Use the chain rule to compute df/dt
Homework Equations
f(x,y)=x2y+y2x
x=sin2t
y=cos2t
The Attempt at a Solution
This is pretty much the exact wording of the question...
I'm not entirely sure if this belongs in homework or elsewhere -- I'm self-teaching working through a basic calculus text, so it's not homework per se. In any case it's a simple differentiation problem wherein I am supposed to differentiate:
f(x) = x(3x-9)^3
f'(x) = 3x(3)(3x-9)^2 Applying...
How do I compute the following differentiation by chain rule?
\frac{d}{d\lambda}(\lambda^{-1}\phi(\lambda^{-1}x))
It is not a homework, but I can't figure out the exact way of getting the answer -\phi(x)-x^{s}\partial_{s}\phi(x)
Homework Statement
Let h(u,v) = f(a(u,v), b(u,v)), where a_u = b_v and a_v = -b_u.
Show that h_{uu} + h_{vv} = (f_{xx} + f_{yy}) (a^2_u + a^2_v).
Homework Equations
The Attempt at a Solution I suppose my first question is where the x's and y's come from. (I thought at first it...
Homework Statement
Show that any function of the form
##z = f(x + at) + g(x - at)##
is a solution to the wave equation
##\frac {\partial^2 z} {\partial t^2} = a^2 \frac {\partial^2 z} {\partial x^2}##
[Hint: Let u = x + at, v = x - at]
2. The attempt at a solution
My problem with this is...
Take \(U(\eta) = u(x - ct)\) and the wave equation \(u_{tt} - u_{xx} = \sin(u)\). Then making the transformation, we have
\[
(1 - c^2)U_{\eta\eta} = \sin(u).
\]
My question is the chain rule on the differential.
\[
U_{\eta} = \frac{\partial u}{\partial x} \frac{\partial x}{\partial\eta} +...
Homework Statement
Find the second derivative of $$9x^2+y^2=9$$
Homework Equations
Chain rule
The Attempt at a Solution
I find the first derivative first.
$$18x+2y\frac{dy}{dx}=0$$ $$\frac{dy}{dx}=-9\frac{x}{y}$$
I then find the second derivative...
Homework Statement
Find the derivative of $$y=cos(\frac{1-e^{2x}}{1+e^{2x}})$$
Homework Equations
Chain rule
The Attempt at a Solution
$$y=cosu$$ $$\frac{dy}{du}=-sinu$$
$$u=\frac{1-e^{2x}}{1+e^{2x}}$$ $$ \frac{du}{dx}=(1-e^{2x})(-(1+e^{2x})^{-2})+(1+e^{2x})^{-1}(-2e^{2x})$$...
Homework Statement
Find the derivative of y=cos(a3+x3)
Homework Equations
Chain rule
The Attempt at a Solution
y=cosu
\frac{dy}{du} = -sinu
u=a3+x3
\frac{du}{dx} = 3a2+3x2
\frac{dy}{dx} = -3sin(a3+x3)(a2+x2).
The answer is supposed to be -3x2sin(a3+x3). What did...
Homework Statement
Find the derivative of y=xe-kx
Homework Equations
Chain rule
The Attempt at a Solution
y = xeu
\frac{dy}{du} = xeu+eu
u = -kx
\frac{du}{dx} = -k
\frac{dy}{dx} = (xe-kx+e-kx)(-k)
= e-kx(x+1)(-k)
= e-kx(-kx-k)
The answer is e-kx(-kx+1)...
Hi, I have a test prep question regarding Chain Rule, please see the problem and my attempt below. I believe part A is okay but part B, I'm just confused, seems like there is a part missing from the question, or at least how I'm use to doing it.
Homework Statement
A. Let f(x, y) =...
If ##r## is a function of ## x,y##, then
\delta r= \frac{\partial r}{\partial x}\delta x + \frac{\partial r}{\partial y}\delta y
Means
Small change of r = ##\left[\frac{\partial r}{\partial x}\right]_{y=k}## X (Small change of x) + ##\left[\frac{\partial r}{\partial y}\right]_{x=k}## X...
Homework Statement
Solve d^2x/dt^2 = (3x^3)/2
when dx/dt = -8 and x = 4 when t = 0
2. The attempt at a solution
v = dx/dt dv/dx = d^2/dx^2
d^2x/dt^2 = v(dv/dx) = (3x^3)/2
v dv = (3x^3)/2 dx
integrating and using limits and you get :
v^2/2 -32 = (3x^4)/8 - 96 ...
Homework Statement
Solve (d^2x)/(dt^2) = 2x(9 + x^2) given that dx/dt = 9 when x = 0 and x = 3 when t = 0
Homework Equations
The Attempt at a Solution
v = dx/dt ...... dv/dx = d^2x/dt^2
dv/dx = v(dv/dx)
v(dv/dx) = 18x +2x^3
integrating and evaluating using...
It seems to me to follow from the definition of a partial derivative.
If f(x,y) = fx + fy, then what else can Δf be other than ∂f/∂x*Δx + ∂f/∂y*Δy? Then in the limiting case, the changes in f, x and y becomes differentials instead. All this seems to be given by the definitions themselves, is...
Hi! I do not understand the math used in the beginning of this video:
In example 1 (4 minutes in the video), why is it wrong to simply solve the problem like this:
\vec{V} = [x,-y] \Rightarrow \frac{d\vec{V}}{dt} = [\frac{dx}{dt},-\frac{dy}{dt}] = \vec{a} = [V_x,-V_y], where V_x and V_y are...
Hi everybody I'm trying to solve this equation
the text in shown picture basically asks to find meaning of Xo
By doing this
But it says my answer is wrong, can anyone tell me why, Thank you?(Also what is this equation called in English?)
Homework Statement
Take a constant p ≥ 1 and f(x, y) a function of two variables with continuous
first order partial derivatives. If, f(λx, λy) = (γ^p)f(x,y) for λ ε ℝ, prove that
x(∂f/∂x) + y(∂f/∂y) = pf
Homework Equations
x(∂f/∂x) + y(∂f/∂y) = pf
f(λx, λy) = (λ^p)f(x,y)The Attempt at a...
Hi all!
In questions having implicit functions,
this expression -> "d/dx y^2" often appears in the calculation process.
I use the chain rule to convert it to 2y x dy/dx
But why can the chain rule be used here?
I actually don't understand at all..
Any help is appreciated.
Thanks guys!
Hi,
I was trying to understand why the chain rule is needed to differentiate expressions implicitly.
I began by analyzing the equation used by most websites I visited:
e.g. x2+y2 = 10
After a lot of thinking, I got to a reasoning that satisfied me... Here it goes:
From my...
Homework Statement
question from early transcendentals (Edwards, penny) . chapter 12 partial differentiation
problem 38
1/R = 1/R1 + 1/R2 + 1/R3
R is resistance measured in Ω
R1 and R2 are 100Ω and increasing with 1Ω/s
R3 are 200Ω and decreasing with 2Ω/s
Is R increasing or...
I have a composite function f(g(x,y)).
When is it true that ∂f/∂g = (∂f/∂x)(∂x/∂g) + (∂f/∂y)(∂y/∂g)?
Does g have to be invertible with respect to x and y for this to be true?
Homework Statement
If f(x) = e^{3x^2+x} , find f'(2)Homework Equations
f'(x) = a^{g(x)}ln a g'(x)The Attempt at a Solution
f'(x) = (e^{3x^2+x})(ln e)(6x+1)
f'(2) = (e^{3(2)^2+2})(ln e)(6(2)+1)
= 2115812.288
I was checking online and I'm seeing a different answer, but this is EXACTLY how...
Hello,
Given is the function
f = f(a,b,t), where a=a(b) and b = b(t). Need to express first and second order derivatives.
\frac{\partial f}{\partial a} and \frac{\partial f}{\partial b} should be just that, nothing more to it here, correct?
But
\frac{df}{dt} = \frac{\partial...
Homework Statement
h(x) = f[g(x)]
h'(x) = f'[g(x)] * g'(x)
Homework Equations
h(x) = sin(-x)
The Attempt at a Solution
So, this one is pretty simple, except I just want to confirm something. When I do it it, it looks like this:
The derivative of sin = cos,
so you have...
Homework Statement
Use \frac{\partial z}{\partial r}=\cos\theta\frac{\partial z}{\partial x}+\sin\theta\frac{\partial z}{\partial y}
and \frac{\partial z}{\partial\theta}=-r\sin\theta\frac{\partial z}{\partial x}+r\cos\theta\frac{\partial z}{\partial y} to show that...
Homework Statement
Write out a tree (this will be a big tree) of dependencies and hence write down an expression for
∂z/∂rHomework Equations
z=k(x, y)=xy2, x=(w1)(w2)+w3, y=w4;
w1=t, w2=t2, w3=2t+1, w4=sin(t);
t=r2+2s2The Attempt at a Solution
This is the tree I drew and followed the...
Hello MHB,
I got one exempel that I don't get same result as my book.
Exempel: If z=f(x,y) has continuos second-order partial derivates and x=r^2+s^2 and y=2rs find \frac{d^2z}{dr^2}
So what I did before checking soulotion:
\frac{d^2z}{dr^2}=\frac{dz}{dr} \frac{d}{dr}
So I start with solving...
Exempel 6: If g(s, t) = f(s^2-t^2, t^2-s^2) and f is differentiable, show that g satisfies the equation
t\frac{dg}{ds}+s\frac{dg}{dt}=0
I always try solve it before I look 'soloution' so this is how we both did it. (remember this is a exempel in my book so they show how to solve it but they...