In calculus, the chain rule is a formula to compute the derivative of a composite function. That is, if f and g are differentiable functions, then the chain rule expresses the derivative of their composite f ∘ g — the function which maps x to
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{\displaystyle f(g(x))}
— in terms of the derivatives of f and g and the product of functions as follows:
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{\displaystyle (f\circ g)'=(f'\circ g)\cdot g'.}
Alternatively, by letting h = f ∘ g (equiv., h(x) = f(g(x)) for all x), one can also write the chain rule in Lagrange's notation, as follows:
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{\displaystyle h'(x)=f'(g(x))g'(x).}
The chain rule may also be rewritten in Leibniz's notation in the following way. If a variable z depends on the variable y, which itself depends on the variable x (i.e., y and z are dependent variables), then z, via the intermediate variable of y, depends on x as well. In which case, the chain rule states that:
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{\displaystyle {\frac {dz}{dx}}={\frac {dz}{dy}}\cdot {\frac {dy}{dx}}.}
More precisely, to indicate the point each derivative is evaluated at,
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{\displaystyle \left.{\frac {dz}{dx}}\right|_{x}=\left.{\frac {dz}{dy}}\right|_{y(x)}\cdot \left.{\frac {dy}{dx}}\right|_{x}}
.
The versions of the chain rule in the Lagrange and the Leibniz notation are equivalent, in the sense that if
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{\displaystyle z=f(y)}
and
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{\displaystyle y=g(x)}
, so that
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{\displaystyle z=f(g(x))=(f\circ g)(x)}
, then
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{\displaystyle \left.{\frac {dz}{dx}}\right|_{x}=(f\circ g)'(x)}
and
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{\displaystyle \left.{\frac {dz}{dy}}\right|_{y(x)}\cdot \left.{\frac {dy}{dx}}\right|_{x}=f'(y(x))g'(x)=f'(g(x))g'(x).}
Intuitively, the chain rule states that knowing the instantaneous rate of change of z relative to y and that of y relative to x allows one to calculate the instantaneous rate of change of z relative to x. As put by George F. Simmons: "if a car travels twice as fast as a bicycle and the bicycle is four times as fast as a walking man, then the car travels 2 × 4 = 8 times as fast as the man."In integration, the counterpart to the chain rule is the substitution rule.
Homework Statement
32) A stone dropped into a pond at time t=0 seconds causes a circular ripple that ravels out from the point of impact at 5 metres per second. At what rate (in square metres per second) is the area within the circle increasing when t=10?
Homework Equations
I need to use...
Homework Statement
Let (u,v)=\mathbf{f}(x,y,x)=(2x+y^3,xe^{5y-7z})
Compute D\mathbf{f}(x,y,z),\;\partial (u,v)/\partial(x,y),\;\partial (u,v)/\partial(y,z)\text{ and }\partial (u,v)/\partial(x,z)
Homework Equations
-chain rule
The Attempt at a Solution
well I can get...
Homework Statement
this is kinda funny I've been strugglnig with the proof for 3 hours straight today
long story short(<--sorry couldn't find the best way t o say this ) i made it to this statement
lim(x->a) g(x) if this is equal to g(x) then my proof is done
lim(x->a) f(a) if this is equal...
Hello,
I got problem again with chain rule and would like to have advice for this problem,
$\frac{\displaystyle r} {\displaystyle \sqrt{r^2+1}}$
is it product rule I shall also use because I have rewrite it as
$r(r^2+1)^{-0.5}$
Homework Statement
Consider the transformation \mathbf{x}=G(\mathbf{u}), \text{ where } \mathbf{x}=(x_1,x_2,x_3),\:\mathbf{u}=(u_1,u_2,u_3) given byx_1=u_1+u_3^2x_2=u_3-u_1^2x_3=u_1+u_2+u_3
I need to compute the derivative of this transformation, and then show that the transformation is...
Homework Statement
Find the derivative of the following
cos(e^-θ^2)
Homework Equations
cos=-sin
e^x=e^x
power rule
The Attempt at a Solution
So I have gotten this far: -sin(e^-θ^2) * ... but then i don't know where to go. Would I treat the -θ^2 as the next step inwards? My...
Homework Statement
Use chain rule to find the derivative of f(x)= sin(x)/(1+x^2)
Homework Equations
Chain Rule (f(g(x)))'*g'(x)
The Attempt at a Solution
y'(x)= cos (x)/(1+x^2)* (1-x^2)/((1+x^2)^2)
I just want to make sure I am doing it correctly and this would be acceptable as a final answer.
If f is a differntiable function, find the expression for derivatives of the following functions.
a) g(x)= x/ f(x)
b) h(x) [f(x^3)]^2
c) k(x)= sqrt (1 + [f(x)]^2)
First off, I am not even sure what they are asking. I am assuming that they want the derivative for each component of the...
Homework Statement
g:ℝ^{ 2 }\rightarrow ℝ is everywhere differentiable.
For all (x,y) and for all t: g\left( tx,ty \right) =tg\left( x,y \right) .
Prove g is linear (that there exist constants A, B such that for all (x,y): g\left( x,y \right) =Ax+By .
I think my solution is correct, but the...
Homework Statement
Please have a look at the picture attach, which shows the proof of the D'alembert's solution to the wave equation. If you can't open the open,
https://www.physicsforums.com/attachment.php?attachmentid=54937&stc=1&d=1358917223
click onto this...
Homework Statement
compute the gradient:
ln(z / (sqrt(x^2-y^2))
Homework Equations
∇=(∂/(∂x)) + ... for y and z
I just want to know how to do the first term with respect to x
The Attempt at a Solution
I am so rusty I don't know where to begin.
This guy relates the calculus chain rule to a popular mob movie. You should really check it out. This is one of the newer videos but people like the way this guy explains things. Here is the link:
Ghetto Dude Relates Calculus Chain Rule To "THE MOB" - YouTube
Air is being pumped into a spherical balloon at a rate of 5 cm3/min. Determine the rate at which the radius of the balloon is increasing when the diameter of the balloon is 20 cm.
So, to solve, I know HOW to do it, I just don't know WHY it's right.
\frac{dv}{dr}=4pi r^{2}...
Homework Statement
Show that:
\frac{dx^\nu}{d \lambda} \partial_\nu \frac{dx^\mu}{d \lambda} = \frac{d^2 x^\mu}{d \lambda^2}
The Attempt at a Solution
Well, I could simply cancel the dx^nu and get the desired result; that I do understand.
But what about actually looking at...
Homework Statement
As part of a problem I am doing I am asked to show uβ∂βuα = aα where u is 4 velocity and a refers to 4 acceleration. The way to do this is not immediately obvious to me, especially since the problem implies there should be a chain rule step involved which I am not seeing. I...
Homework Statement
If u=f(x,y) where x=escost and y=essint
show that d2u/dx2+d2u/dy2 = e-2s[d2u/ds2+d2u/dt2
Homework Equations
http://s11.postimage.org/sjwt1wkvl/Untitled.jpg
The Attempt at a Solution
ok i don't understand how they got to that
i don't know what d/ds is...
Homework Statement
Find the derivative of y = sin(πx)2
Homework Equations
Chain Rule: y' = f'(u) * u'
The Attempt at a Solution
(See attached image)
The answer according to the textbook is 2π2xcos(πx)2. What am I doing wrong here?
Homework Statement
Ok I have this general homogeneous function, which is a C^1 function:
f(tx,ty)=t^k f(x,y)
And then I have to show that this function satisfies this Euler equation:
x\frac{\partial f}{\partial x}(x,y)+y\frac{\partial f}{\partial y}(x,y)=k\cdot f(x,y)
Homework...
Hi all, I've got a Calculus III Question
Homework Statement
Find the derivative zs and zt, where z=sin(x)cos(2y)Homework Equations
x=s+t
y=s-t
The Attempt at a Solution
I had a go at the solution and this was what I ended up getting
for zs, I ended up getting (cosxcos2y)(1)-2sinxsin2y(1)...
Okay so, I am having trouble figuring out what exactly to do in implicit differentiation and usage of the chain rule. Like, I keep getting the wrong answer somehow. See, from what I understand you have to find the derivative of both sides then use the chain rule or something and then solve for...
Find the derivative of 101-x2.
1.) So, I used power rule to get: (1-x2)(10-x2).
2.) Then I did chain rule and multiplied my previous answer with (d/dx)(-x2).
3.) The answer I get is: (-2x)(1-x2)(10-x2).
When I use my calculator, the answer I get is: -20*ln(10)*10-x2. So, where does...
Homework Statement
I'm curious to know if I'm actually doing this correctly.
Suppose f(x,y) is a function where x = p(s,t) and y = g(s,t) so that w(s,t) = f(x,y).
Compute ws and then wst
Homework Equations
Chain Rule.
The Attempt at a Solution
So! Let's compute ws first. Whenever I use a...
Let g(t) = f(tx, ty).
Using the chain rule, we get g'(t) = (\frac{\partial f}{\partial x})(tx, ty) * x + (\frac{\partial f}{\partial y})(tx, ty) * y
this was actually part of a proof and what i don't understand is that why didn't they write (\frac{\partial f}{\partial (tx)}) and...
Evaluate partial derivative. chain rule??
I would like to represent the term identified in the image as (term 1)
in terms of those partial derviatives that are known. Unfortunatly I just can't seem to wrap my head around it at the moment. :bugeye:
A prod in the right direction would be...
Homework Statement
Given that f(x,y) = g(r,\theta), where x = r\cos\theta and y = r\sin\theta, find formulae for \frac{∂f}{∂x} and \frac{∂f}{∂y} expressed entirely in terms of r, \theta, \frac{∂g}{∂r} , \frac{∂g}{∂\theta} .
The Attempt at a Solution
I said \frac{∂f}{∂x} =...
Homework Statement
Parametrize the upper half of the unit circle by x = cos(t), y = sin(t), for 0\leq t \leq\pi
Let T = f(x,y) be the temperature at the point (x,y) on the upper half of the circle.
Suppose that:
\frac{\partial T}{\partial x} = 4x - 2y \frac{\partial T}{\partial y} = -2x +...
say you have a function f(x,y)
\nablaf= \partialf/\partialx + \partialf/\partialy
however when y is a function of x the situation is more complicated
first off \partialf/\partialx = \partialf/\partialx +(\partialf/\partialy) (\partialy/\partialx)
( i wrote partial of y to x in case y was...
ok stupid question probably-
take v(velocity) to be a function of x and x to be a function of t(time).
then dv/dt=vdv/dx that's cool
but in the hint in problem 2.12 classical mechanics by john r taylor he equates vdv/dx and 1/2(dv^2)/dx
that is- vdv/dx=1/2(dv^2)/dx
Could someone please...
Hi folks,
I don't know if my experience is at all common (and I would like some feedback on this if possible), but I can't seem to nail down the properties of euler's number in the context of chain rule problems.
Here is the nub of my difficulty:
1. $\text{If }f(x)=e^x \text{then }f'(x)=e^x$...
I have attached a pdf setting forth my question.
This is a write up of a lesson i just had on yourtutor, in which i think the tutor might have made an error: this is a direct quote from the whiteboard:
$Let g(x)=2x, f(y)=e^y\Rightarrow(fog)(x)=f(g(x))=f(2x)=e^{2x}$$\\Now...
Hi, I have been doing research in my spare time this summer on calculus proofs. I am working on a mathematics degree and I am working to understand calculus inside and out. It has been going really well but I have sort of hit a bump with the calc 1 chain rule. Here is my attempt:
lim h -> 0...
Can someone help me out with what I believe who.d be a straight chain rule application?
D/dx (dy/dx)^2
I would think, applying the chain rule, you get
2 (dy/dx) d/dx (dy/dx) = 2 (dy/dx) (d2y/dx2)
But, from the papers I checked, the (dy/dx) in the answer goes away, leaving just
2...
If h(x) = ax, g(x) = bx and f(x) = g(h(x)).
Wouldn't h'(x) = a? And g'(x) = b? And f'(x) = ab?
But the chain rule says f'(x) must equal h'(x)g'(h(x)), so that means f'(x) = ab(ax) = (a^2)bx.
Am I missing something obvious?
I have read a few sources regarding the chain rule, and a pervasive explanation that most of the sources share is this, which is way to sort of make sense of it:
"Regard du/dx as the rate of change of u with respect to x, dy/du as the rate of change of y with respect to u, and dy/dx as the...
1. Find the derivative of the function
2. \left(y= x sin\sqrt{x}\right)
3. I started using the product rule and then proceeded to use the chain rule, but I am wondering if I should have used the chain rule twice rather than starting with the product rule. Since I know that x is the...
I was reading over a textbook that stated the following, where y(s,t) = v(x(s,t),t)
\frac{\partial y}{\partial t} = \frac{\partial v}{\partial x}\frac{\partial x}{\partial t} + \frac{\partial v}{\partial t}
and
\frac{\partial^2y}{\partial t^2} = \frac{\partial^2 v}{\partial x^2}\left (...
Homework Statement
(x^{2}-x^{-1}+1)(x^{3}+2x-6)^{7}
Homework Equations
Chain Rule & Power RuleThe Attempt at a Solution
(x^{3}+2x-6)^{6}[(x^{3}+2x-6)(2x+x^{-2})+7(3x^{2}+2)(x^{2}-x^{-1}+1)]
This is the farthest I've gotten but when I do additional computation I do not arrive at the correct...
Homework Statement
s=\sqrt{(3x^2)+(6y^2)}
Homework Equations
None
The Attempt at a Solution
\stackrel{ds}{dt}=\stackrel{d}{dt}\sqrt{(3x^2)+(6y^2)}
\stackrel{3x}{\sqrt{(3x^2)+(6y^2)}}
The problem with that is its only d/dx if y is a set number. I don't know how to...
Any proof for the CHAIN RULE ??
Can somebody please show me the proof of the chain rule?? even though i have been applying that concept since i touch differentiation but i still have doubt and question on this concept!
Homework Statement
If x=yz and y=2sin(y+z), find dx/dy
Homework Equations
Chain rule
The Attempt at a Solution
From y = 2sin(y+z) we get
dz/dy= (1-2cos(y+z))/(2cos(y+z))
dz/dy=((1/2)sec(y+z) - 1)
dx/dy = ∂x/∂y + ∂x/∂z dz/dy
= z + y ((1/2)sec(y+z) - 1)
= z...
Homework Statement
Let x=ts^2 -1 and y=ln(s)-t
Use the chain rule for functions of two variables to determine ∂f/∂t at (s,t)=(1,1)
The Attempt at a Solution
y=ln(s)-t
∂f/∂t= ∂f/∂s X ∂s/∂t -1
t=x+1/s^2
∂t/∂s= -2(x+1)/s^3
∂s/∂t=s^3/-2(x+1)
∴ ∂f/∂t= s^2/-2(x+1)...
Homework Statement
Here is the problem:
http://dl.dropbox.com/u/64325990/MATH%20253/help.PNG
The Attempt at a Solution
http://dl.dropbox.com/u/64325990/Photobook/Photo%202012-05-24%209%2037%2028%20PM.jpg
This seems to be wrong... Since I have fx and fy which I cannot cancel out. Why...
Homework Statement
Here is the problem with the solution:
http://dl.dropbox.com/u/64325990/MATH%20253/Capture.PNG
What I don't understand is circled in red, how did they combine dxdy with dydx? Is it with Clairaut's theorem? If it is can someone explain how it works in this case because...
$${x = r \cos \theta}$$,
$${y = r \sin \theta}$$, $${r^2 = x^2 + y^2}$$ and $${\theta = \tmop{ \arctan} (y / x)}$$ (with some caveats for the last formula).
Suppose $${u = u (x, y)}$$.
Show that
$${\frac{\partial u}{\partial r} = \frac{\partial u}{\partial x} \cos \theta +...
Hi,
If I have the equation
y' = ax - by
where y = y(t) , x= x(t)
and y' = \frac{dy}{dt}
then what is
\frac {d}{dy} y' = \frac {d}{dy}(ax - by)
?
I think it would come out to
\frac {dy'}{dy} = a \frac {dx}{dt}\frac {dt}{dy} - b
Is that right? In general...
Homework Statement
I have vector R. I need to show the R dot dR/dt = 0 => 1/2 d/dt[R dot R]
Homework Equations
The Attempt at a Solution
I guess I've never really applied the chain rule to dot products and its throwing me off. How does one go from R.dR/dt=0 to 1/2 d/dt[R.R] = 0. I...