The speed of the block after the nth collision is
$$ V_n=(2e)^n*v_0 $$
By conservation of energy the block travels a distance $$V_n^2/(2ug)$$ on the nth bounce. So the total distance is
$$ d=1/(2ug)∗(v_0^2+(2ev_0)^2...) $$
$$ d=1/(2ug)∗(v_0^2/(1−4e^2)) $$
$$ d=1/(2ug)∗(v_0^2∗M^2/(M^2−4m^2))...
1) By conservation of mechanical energy we have ##m_2gl(1-\cos(\alpha))+m_1gl=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2+m_1gl## and by conservation of linear momentum along the x-axis we have ##m_1v_1+m_2v_2=0## which gives us ##v_2=\sqrt{\frac{2m_1gl(1-\cos(\theta))}{m_1+m_2}}## and...
Please redirect me to the correct part of thr forum if this is the wrong place
When we lift up an object n then let it fall back, then potential energy - > kinetic energy
If I drop a magnet onto another magnet with like pole facing each other (that sits on the floor), the falling one maybe...
Electrons rotate around a nucleus for long periods of time. Where does the energy for this motion come from?
Ok, I realize that electrons don't actually rotate around the nucleus, like a tiny solar system. But if the electron is wave function, it's still constantly vibrating, constant...
The information I have are the following:
##p^\mu=(E, p, 0, 0)##
##p'^\mu=(E', p'\cos\beta, -p'\sin\beta,0)##
##k^\mu=\tilde{E}(1, \cos\alpha, \sin\alpha, 0)##
Where:
##E=\sqrt{M^2+p^2}##
##E'=\sqrt{m^2+p'^2}##
Using the conservation of the four-momentum
##p^\mu=p'^\mu+k^\mu##...
Hi all. I'm trying to prove energy conservation in a (maybe) uncommon way. I know there are different ways to do this, but it is asked me to prove it this way and I'm stucked at the end of the proof. I'm considering ##N## bodies moving in a gravitational potential, such that the energy is ##E =...
I was going to put this in the homework forums, but on second thoughts it's more conceptual so perhaps here is better. It's about problem 4, chapter 6 of Wald. Part (a) is fine, $$u^a \nabla_a u^b = \frac{\xi^a}{(-\xi^c \xi_c)^{1/2}} \left( \frac{\nabla_a \xi^b}{(-\xi^c \xi_c)^{1/2}} +...
I solved this problem easily using Newton's second law, but I had problems trying to use mechanical energy conservation to solve it.
How I solved using Newton's second law:
##\text{(part of the rope that is on the left)}\, m_1=x\rho g,\, \text{(part of the rope that is on the right)}\...
This is my understanding of the law of conservation of energy and the role non conservative forces factor into it. Could someone confirm if I have this right or explain where I am going wrong if I am? I would appreciate it.
With the law of conservation of mechanical energy, ΔKE+ΔPE=0. This...
The conservation of energy equation is basically GPE is converted to KE of block and KE of cylinder.
To get the correct answer, the KE of the cylinder is 1/2mv^2, where m is its mass and v is the velocity of its COM (which is the centre of cylinder).
However, I viewed the cylinder as rotating...
Suppose a rocket is moving at radial velocity vr and tangential velocity vt in the Sun's gravitational field. At some time, the rocket enters the gravitational field of Mars (with the above mentioned velocities), and gravitation effects due to the Sun can be ignored. After more time, the rocket...
So force on a current carrying wire = ILxB.
If I have a bunch of bar magnets making a uniform magnetic field of strength B, then a 1 meter long wire of 0 ohms carrying 1 Amp, the force on that wire is (1)(1)xB = 1B. If I let that force move the wire for a time T, let's assume the wire moved a...
Hi,
In my textbook it says that if you consider the electrostatic repulsive barrier that protons in the Sun need to overcome in order to get into the range of the strong nuclear force to fuse together then it fails to fully account for the measured power output of the Sun.
It says that the...
My book uses ##1/2m_1v_{1c}^2+1/2m_2v_{2c}^2=1/2m_1v_{1c}'^2+1/2m_2v_{2c}'^2## to show that the angles of deflection of the collision between two particles are the same in the centre of mass frame. However, I am doubtful that one can apply the conservation of energy to a "moving" system because...
I'm having trouble with this problem, I think I solved it but I don't know if what I did is right...
At first when the velocity is 0 and the spring is at its natural length, there's just gravitational potential energy, so $$E_i=mgh$$
And then, when the mass is released and then reaches its...
a) So far, I have equated Ek to Eg to solve for h. 1/2(m)(27)^2 = m(9.8)h. I haven't taken the angle into consideration. I'm not sure if I have to use the x or y component. I got my answer to be 37m but again I don't believe this is correct.
b) I did Ek = Eg + Ek. 1/2(m)(27)^2 = m(9.8)(3.5) +...
Hello.
I have a question about the law of energy conservation in GR.
As time is inhmogeneous, we don't have energy-momentum 4-vector which would be preserved during system's dynamical change. It is only possible to define 4-vector locally. And next, the problem regarding how to sum this vectors...
I think I have a rough idea about it, but I am not sure whether it is correct. At least I feel that my understanding is a bit vague. Here it is:
Globally (I mean across all worlds), the energy is conserved because the universal wavefunction evolves strictly according to Schrodinger equation...
(a) Using COE,
$$mgh = 0.5mv^2 + 0.5I\omega^2$$
I solved it, where $$\omega = 112 rad/s$$
(b) This is the part where I have question or problem.
I saw my course mate working and he start of with finding centripetal acceleration.
$$a_c = \frac{v^2}{r} = \frac{(r_0\omega)^2}{R_0}$$
Why isn't it...
Suppose that we shined a source of light on a wall with infinitismal small opening. As the opening is infinitismly small, only one ray of light will pass through the opening ( suppose it has an intensity ##I_0##) and this ray of light will diffract into an infinite number of light rays with the...
I can solve the equation for a damped oscillator with a forcing function.
I can then plot the Kinetic and Potential Energy.
They will be out of phase, of course (KE peaking when PE is zero, and vice versa)
And we know that when the input frequency is close to the natural frequency, the system...
The question seems similar to the one asked here,
https://www.physicsforums.com/threads/energy-in-everetts-many-worlds-interpretation.966266/
but since there didn't seem to be an answer I am asking it again in a slightly different form.
I was watching a youtube video where Sean Carroll...
Hello there,
I was trying to solve this problem. I have no problem with part A and C. But in part B, my guidebook arrived with different answer. Can anybody point out what my mistake is? I am using the same method as the elevator motor problem which states :
"A 650-kg elevator starts from rest...
m1 + m2 = 8
COE
0.5(m1)(u1)^2 + (m1)(g)(30) + 0.5(m2)(u2)^2 + (m2)(g)(30) = 0.5(m1)(v1)^2 + 0.5(m2)(v2)^2 + (m2)(g)(16)
Can you check if my eqn is correct? And can you advise what to do after this?
I wanted to do COLM but i don't know what is the initial part.
When A hits B,
COLM
mV = -mVa + 2mVb
V = 2Vb - Va
COKE
0.5mv^2 = 0.5mVa^2 + 0.5(2m)Vb^2
V^2 = Va^2 + 2Vb^2
When B hits C
COLM
2mVb=4mVc
Vc = 0.5Vb
COE
0.5(2m)Vb^2 = 0.5kx^2 +0.5(4m)Vc^2
sub Vc = 0.5b
mVb^2 = KX^2
After that I am stuck, cause i can't find V in terms of Vb only
There are two nonconservative forces in this situation, the work done by the person and the work done by friction - they are the only sources of work that change the total mechanical energy of the mass-Earth system.
The initial energy (assuming gravitational potential energy is initially 0) is...
Hi, there. I am reading the article Relativistic quantum optics: The relativistic invariance of the light-matter interaction models by Eduardo Martin-Martinez el al (2018).
Here he calculate the transition probability of a vacuum excitation for a detector.
Suppose there is a lab where the...
This problem was from the chapter on Work and Energy so, I thought of using the principle of conservation of mechanical energy. Clearly, the potential energy of the block decreases by mgh (assuming the block has mass m). This energy should have been converted to kinetic energy, but it clearly...
By solving conservation of energy, I was able to find the linear velocity which is
[10g(H-R-Rsin(theta))/7]^½ and by differentiating this with respect to "t", I arrived at the tangential acceleration value of -(5gcos(theta))/7 and found it to be in agreement with the solution provided in the...
My, supposedly rational thought is that if the pendulum will drop from a height higher than the top of the loop's height, by the law of conservation of energy, it'll have enough velocity to complete the loop.
The teacher's final result shows a different approach.
Am I right? Wrong? Thanks
Models like Vilenkin's tunnelling from nothing model described here:
https://www.sciencedirect.com/science/article/abs/pii/0370269382908668
claim the universe came from "nothing". It is claimed this doesn't violate any conservation laws because the negative energy of gravity and the positive...
This question is given as an exercise in my book. I can't figure out whether this is a poorly worded question or if I misunderstand. The answer I can come up with is that power is dissipated over the load so more power is needed to be supplied by the ac source. This seems too hand-wavy to me...
Although I am not too sure how to answer this quesion I have tried below.
I realize that an electromotive force is a supply voltage, the energy transferred per unit charge when one type of energy is converted into electrical energy. However, EMF is not actually a force. It is usually measured...
To my mind, there are two distinct approaches to energy problems that different authors tend to use, and I wondered whether either is more fundamental than the other. The first is variations on the work energy theorem, and the second consists of defining a system boundary and setting the change...
Change in KE = Change in thermal energy
0.5 * (6)* vblock^2 = 0.4 * 6 * 9.81* 0.1
vblock = 0.885
By Conservation of Momentum,
(0.05)(854) = (0.05)*vbu + (6)(0.885)I am not sure whether Change in KE = Change in thermal energy is true coz there should be a change in internal energy of the block...
I probably haven’t thought this through. A sideview of a closed container filled with air consisting of two vertical cylinders (with radius ##r_1## and ##r_2##) are connected by two horizontal tubes. The container is separated by a small and a large lid (red) that are circular and can move up...
Hello everyone,
someone could explain me please, why the work of the normals forces are 0 ?
He used with conservation energy equations.
How should I refer to the displacement point ?
Thx everyone !
Hi,
I have read over several threads already on this and have a few questions if someone could please answer that would be great:
1) The threads seem to suggest that energy is not conserved (or at least it isn't a requirement) on the scale of the universe. Why does it not have to be conserved...
So Earth and everything is spinning around at 1000mph at the equator. From our perspective we are at a standstill. But let's say a fighter jets flies east to West against Earth at same speed, so now relative to someone in space, the Earth spins but the plane is at a standstill.
Wouldn't that...
In classical mechanics, the energy of a system of particles (say with 2 particles) in an external field is given by
$$E=\frac{1}{2}m_1|\vec{v}_1|^2+\frac{1}{2}m_2|\vec{v}_2|^2+V(\vec{r}_1)+V(\vec{r}_2)+V'(|\vec{r}_2-\vec{r}_1|)$$
Where V is the potential energy of the external field, and V' is...
Suppose a bullet with high speed strike a wooden block and move together after collision. We know there is loss in total KE of bullet-wooden block system. The question is, if the part of the loss in KE of the bullet is transfer to heat energy, HOW to prove the CONSERVATION of ENERGY in this...
I'm all messed up on this problem. I see you can get the solution (74cm, as listed in the back of the book) by simply setting mgh=1/2kx^2, saying that h=x, and then adding 15 cm to that since that's the original length of the spring. This is the solved solution I was given. But now I think...
Unfortunetly, I found across the web only the case where there's no source, in which case ##\partial_\alpha T^{\alpha \beta} = 0##. I'm considering Minkowski space with Minkowski coordinates here.
When there's source, is it true that ##\partial_\alpha (T^{\alpha \beta}) = 0## or is it ##\int...
v1 = 0 m/s
v2 = 2.5 m/s
y1 - y2 = distance a quarter of the way around the bowl (since we're neglecting friction)
mass can be factored out, so it isn't needed, and some simplifying and the like gets this formula:
v22 = v12 + 2g(y1 - y2)
so 2.52 = 0 + 2(9.8)(y)
6.25 = 19.6y
y = 0.318877551 m *...
The arrow is following projectile motion to the target when released from an archer's bow.
v vertical = 10ms^-1 v horizontal = 50 ms^-1 resultant v = √2600
mass of arrow = 20*10^-3
I attempted to use F avg = mΔv/Δt to calcualte the average force where Δt = 5*10^-3 /...
This is more like a theoretical question of my own than actual homework.
Say there is a circuit with a current source and an inductor. There is a current ##i(t)=at## going through the inductor. We now place a new circuit with an inductor and a resistor next to it. The current ##i(t)## causes a...