hi, I tried to take the covariant derivative of riemann tensor using christoffel symbols, but it is such a long equation that I have always been mixing up something. So, Could you share the entire solution, pdf file, or links with me? ((( I know this is the long way to derive the einstein...
This is (should be) a simple question, but I'm lost on a negative sign.
So you have ##D_m V_n = \partial_m V_n - \Gamma_{mn}^t V_t## with D_m the covariant derivative.
When trying to deduce the rule for a contravariant vector, however, apparently you end up with a plus sign on the gamma, and I'm...
In Carroll, the author states:
\nabla^{\mu}R_{\rho\mu}=\frac{1}{2} \nabla_{\rho}R
and he says "notice that, unlike the partial derivative, it makes sense to raise an index on the covariant derivative, due to metric compatibility."
I'm not seeing this very clearly :s
What's the reasoning...
Homework Statement
Given two vector fields ##W_ρ## and ##U^ρ## on the sphere (with ρ = θ, φ), calculate ##D_v W_ρ## and ##D_v U^ρ##. As a small check, show that ##(D_v W_ρ)U^ρ + W_ρ(D_v U^ρ) = ∂_v(W_ρU^ρ)##
Homework Equations
##D_vW_ρ = ∂_vW_ρ - \Gamma_{vρ}^σ W_σ##
##D_vU^ρ = ∂_vU^ρ +...
I'm working through Wald's "General Relativity" right now. My questions are actually about the math, but I figure that a few of you that frequent this part of the forums may have read this book and so will be in a good position to answer my questions. I have two questions:
1) Wald first defines...
I need to prove that $$D_\mu D_\nu \xi^\alpha = - R^\alpha_{\mu\nu\beta} \xi^\beta$$ where D is covariant derivative and R is Riemann tensor. ##\xi## is a Killing vector.
I have proved that $$D_\mu D_\nu \xi_\alpha = R_{\alpha\nu\mu\beta} \xi^\beta$$
I can't figure out a way to get the required...
1) I read different texts on Contravariant , Covariant vectors.
2) Contravariant - they say is like vector . Covariant is like gradient
From what I see they have those vector spaces because it eventually helps get scalar out of it if we multiply contravariant by covariant
Also Contravariant...
I have been reading Nakahara's book "Geometry, Topology & Physics" with the aim of teaching myself some differential geometry. Unfortunately I've gotten a little stuck on the notion of a connection and how it relates to the covariant derivative.
As I understand it a connection ##\nabla...
Using Ray D'Inverno's Introducing Einstein's Relativity. Ex 6.31 Pg 90.
I am trying to calculate the purely covariant Riemann Tensor, Rabcd, for the metric
gab=diag(ev,-eλ,-r2,-r2sin2θ)
where v=v(t,r) and λ=λ(t,r).
I have calculated the Christoffel Symbols and I am now attempting the...
What is the trace of a second rank tensor covariant in both indices?
For a tensor covariant in one index and contravariant in another ##T^i_j##, the trace is ##T^k_k## but what is the trace for ##T_{ij}## because ##T_{kk}## is not even a tensor?
I want ask another basic question related to this paper - http://www.tandfonline.com/doi/pdf/10.1080/16742834.2011.11446922
If I have basis vectors for a curvilinear coordinate system(Euclidean space) that are completely orthogonal to each other(basis vectors will change from point to point)...
Hi!
Let ##T^{ik}## be the stress-energy-tensor, and ##v_k## some future-pointing, time-like four vector.
How can I see that the object ##T^{ik}v_k## is future-pointing and not space-like?
Thank you for your help!
I know if the number of coordinates are same in both the old and new frame then A.B=A`.B` . But if the number of coordinates are not same in both old and new frame then A.B=0 means that both the vectors A and B are perpendicular. Why is it so that if the number of coordinates of both the frames...
I am still at the stage of trying to assimilate contravariant and covariant tensors, so my question probably has a simpler answer than I realize.
A covariant tensor is like a gradient, as its units increase when the coordinate units do. A contravariant tensor's components decrease when the...
I now study general relativity and have a few questions regarding the mathematical formulation:
1) What ist the relation between an connection and a covariant derivative?
Can you explain the exact difference?
2) One a lorentzian manifold, what ist the relation between the...
Homework Statement
Hi all, I currently have a modified Einstein-Hilbert action, with extra terms coming from some vector field A_\mu = (A_0(t),0,0,0), given by
\mathcal{L}_A = -\frac{1}{2} \nabla _\mu A_\nu \nabla ^\mu A ^\nu +\frac{1}{2} R_{\mu \nu} A^\mu A^\nu .
The resulting field...
I assume that all the fundamental physics known - as of today - can be reduced to quantum general covariant fields (including spacetime itself to be seen as a field of those...).
Now, sorry if my question is quite abstract and based on tomorrow's hypothetical new physics, but would it be against...
Urs Schreiber submitted a new PF Insights post
Higher Prequantum Geometry IV: The Covariant Phase Space - Transgressively
Continue reading the Original PF Insights Post.
Homework Statement
This is really 3 questions in one but I figure it can be grouped together:
1. The vector A = i xy + j (2y-z2) + k xz. is in rectangular coordinates (bold i,j,k denote unit vectors). Transform the vector to spherical coordinates in the unit vector basis.
2. Transform the...
Homework Statement
Consider the fermionic part of the QCD Lagrangian: $$\mathcal{L} = \bar\psi (\mathrm{i} {\not{\!\partial}} - m) \psi \; ,$$ where I used a matrix notation to supress all the colour indices (i.e., ##\psi## is understood to be a three-component vector in colour space whilst...
Hello all,
I'm trying to calculate a commutator of two covariant derivatives, as it was done in Caroll, on page 122. The problem is, I don't get the terms he does :-/
If ##\nabla_{\mu}, \nabla_{\nu}## denote two covariant derivatives and ##V^{\rho}## is a vector field, i need to compute...
I'm having trouble understanding those concepts in the title. Can someone explain those concepts in an easy to understand manner? Please don't refer me to a wikipedia page. I know some linear algebra and multi-variable calculus.
Thank you.
Homework Statement
Hi I am reviewing the following document on tensor:
https://www.grc.nasa.gov/www/k-12/Numbers/Math/documents/Tensors_TM2002211716.pdf
Homework Equations
In the middle of page 27, the author says:
Now, using the covariant representation, the expression $$\vec V=\vec V^*$$...
Homework Statement
So I've been trying to derive field strength tensor. What to do with the last 2 parts ? They obviously don't cancel (or do they?)
Homework EquationsThe Attempt at a Solution
[D_{\mu},D_{\nu}] = (\partial_{\mu} + A_{\mu})(\partial_{\nu} + A_{\nu}) - (\mu <-> \nu) =...
Hii!
Newton's law of gravity is ∇.(∇Φ) = 4πGρ.
A book on GR gives a suggestion to make it Lorentz covariant by using de' Alembertian operator on 'Φ' in the LHS of above equation instead of Laplacian. Then it explains that this won't work because we have to include in 'ρ' all the energy...
Hey all, I'm just starting into GR and learning about tensors. The idea of fully co/contravariant tensors makes sense to me, but I don't understand how a single tensor could have both covariant AND contravariant indices/components, since each component is represented by a number in each index...
I want to prove that differentiation with respec to covariant component gives a contravariant vector operator. I'm following Jackson's Classical Electrodynamics. In the first place he shows that differentiation with respecto to a contravariant component of the coordinate vector transforms as the...
Hi I am doing some exam revision for an EM class and I'm trying to understand a few things about this derivation. Specifically in equation 18.23 why do we not consider the derivative of the four velocity i.e ##\partial^{\alpha}U^\beta##
Then going from 18.23 to 18.25 why is...
I was reading through hobson and my notes where the covariant acts on contravariant and covariant tensors as
\nabla_\alpha V^\mu = \partial_\alpha V^\mu + \Gamma^\mu_{\alpha \gamma} V^\gamma
\nabla_\alpha V_\mu = \partial_\alpha V_\mu - \Gamma^\gamma_{\alpha \mu} V_\gamma
Why is there a minus...
Homework Statement
is this statement is true : ##\nabla_\mu \nabla_\nu \sqrt{g} \phi = \partial_\mu \sqrt{g} \partial_\nu \phi##
Homework EquationsThe Attempt at a Solution
well we know ##\nabla_\mu \sqrt{g} =0## so it moves back : ## \nabla_\mu \sqrt{g} \nabla_\nu \phi =\sqrt{g} \nabla_\mu...
I have been reading section 3.1 of Wald's GR book in which he introduces the notion of a covariant derivative. As I understand, this is introduced as the (partial) derivative operators \partial_{a} are dependent on the coordinate system one chooses and thus not naturally associated with the...
Hello,
I try to apprehend the notion of covariant derivative. In order to undertsand better, here is a figure on which we are searching for express the difference \vec{V} = \vec{V}(M') - \vec{V}(M) :
In order to evaluate this difference, we do a parallel transport of \vec{V}(M') at point...
As we can not meaningfully compare a vector at 2 points acted upon by this operator , because it does not take into account the change due to the coordinate system constantly changing, I conclude that the elementary differential operator must describe a change with respect to space-time,
How do...
Hey all, I've just started tensor analysis but do not understand why in contravarient uses 1 and covarient uses 2, could someone please explain these? Perhaps my understanding of the definitions is causing me to misunderstand why its written like this. Any help appreciated.
E.g - considering co variant differentiation,
The issue with the normal differentiation is it varies with coordinate system change.
Covariant differentiation fixes this as it is in tensor form and so is invariant under coordinate transformations.'If a tensor is zero in one coordinate system...
I am reading a notes about tensor when I came across this which the notes did not elaborate more on it. As a result I don't quite understand why.
Here it is : " Note that we mark the covariant basis vectors with an upper index and the contravariant basis vectors with a lower index. This may...
Not sure where to post this thread.
That being said, can someone explain to me simply what covariant and contravariant tensors are and how covariant and contravariant transformation works? My understanding of it from googling these two mathematical concepts is that when you change the basis of...
Homework Statement
Given that ##x_\mu x^\mu = y_\mu y^\mu## under a Lorentz transform (##x^\mu \rightarrow y^\mu##, ##x_\mu \rightarrow y_\mu##), and that ##x^\mu \rightarrow y^\mu = \Lambda^\mu{}_\nu x^\nu##, show that ##x_\mu \rightarrow y_\mu = \Lambda_\mu{}^\nu x_\nu##.
Homework Equations...
I am trying to reconcile the definition of contravariant and covariant
components of a vector between Special Relativity and General Relativity.
In GR I understand the difference is defined by the way that the vector
components transform under a change in coordinate systems.
In SR it seems...
Homework Statement
Show U^a \nabla_a U^b = 0
Homework Equations
U^a refers to 4-velocity so U^0 =\gamma and U^{1 - 3} = \gamma v^{1 - 3}
The Attempt at a Solution
I get as far as this:
U^a \nabla_a U^b = U^a ( \partial_a U^b + \Gamma^b_{c a} U^c)
And I think that the...
In Euclidean space, we may define covariant basis by the partial derivative of position vector with respect to each coordinates, i.e.
##∂R/(∂z^i )=z_i##
But in curved space (such as, the two dimensional space on a sphere) how can we define covariant basis 'intrinsicly'?(as we have no position...
I was trying to see what is the covariant derivative of a covector. I started with
$$ \nabla_\mu (U_\nu V^\nu) = \partial_\mu (U_\nu V^\nu) = (\partial_\mu U\nu) V^\nu + U_\nu (\partial_\mu V^\nu) $$ since the covariant derivative of a scalar is the partial derivative of the latter.
Then I...
I wondered if anyone had a good online reference on the covariant formulation of Maxwell's macroscopic equations and the other equations of classical electromagnetism?
The wikipedia article talks about constituitive equations in vacuum, which doesn't make a lot of sense to me since M and P...
Dear all,
I was reading this https://sites.google.com/site/generalrelativity101/appendix-c-the-covariant-derivative-of-the-ricci-tensor, and it said that if you take the covariant derivative of a tensor with respect to a superscript, then the partial derivative term has a MINUS sign. How? The...
Definition/Summary
Covariant derivative, D, is a coordinate-dependent adjustment to ordinary derivative which makes each partial derivative of each coordinate unit vector zero: D\hat{\mathbf{e}}_i/\partial x_j\ =\ 0
The adjustment is made by a linear operator known both as the connection...
Doing some problems in D'INVERNO GR textbook and I am stuck on taking the covariant derivation of a tensor twice. Please see the attached picture and please do inform me if something is not clear :smile:
Homework Statement
I need to calculate \square A_\mu + R_{\mu \nu} A^\nu if \square = \nabla_\alpha \nabla^\alpha , and is the covariant derivate
SEE THIS PDF arXiv:0807.2528v1 i want to get the equation (5) from (3)
Homework Equations
A^{i}_{{;}{\alpha}} =...