a) On QP, the force is zero.
On PR, the force is directed inside the plane, and its magnitude is ##0.8IB##.
On QR, the force is direction out of the plane, and its magnitude is ##1IB\sin(\arctan(0.8/0.6))=0.8IB##.
b) ##0.8IB-0.8IB=0##.
d) It will rotate outside of the page.
c) I know that the...
PROBLEM
Here from the conservation of angular momentum I found angular velocity just before impact,
$$ H_1 = 0 $$
$$ H_2 = I_0\omega + mV_0d $$
$$ H_2 = 66\omega + 76.(1.2).(0.87)$$
$$ H_1 = H_2 $$
$$ \omega = 1.202 rad/s $$
But I couldn't solve it to find joint force.
Thanks in advance,
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a.)N cos θ=mg
N sin θ=mrw^2 sin θ
cos θ=g/rw^2
b.) My question is reaction force =N ? or =F=mg tanθ ?
If it is N then N=mg cosθ =mg^2/r w^2 or N=mg/cosθ =mrw^2 ?
Thank you
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Setup...
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force from part (b) / weight = 10.511N / 15kg = 0.701
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Hi!
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My solution: For the horizontal portion of the chain: let at any instant the length of chain inside the tube is x, and at that instant the chain in the tube is having a velocity v. Then, at any instant:
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