Picture below. Both bodies are made of same material but the body placed in water had 2.4 times greater mass. What is the relationship between buoyancy Force and gravitational force between body in water and body in air?I have no clue how to solve this.
I know that body with greater mass has 2.4...
Hello again!
I've found the capybara's EMA to be 0.71. Their mass to be 55kg. And their average speed to be ~3.0km/h.
I want to figure out how many capybaras it would take to overcome Friction * Normal force of ~125,000N. How would I go about doing that...
What is and how is the estimation of the ideal weight or force to push (bit being in) a driller down when drilling (stainless) steel to bore 3-9 mm hole?
I have tried finding the tension of the string through the equation
Net Force = T - mg = ma
but I am struggling with coming up with the correct acceleration. Is my net force equation correct?
m1 = 4 kg, m2 = 12 kg, m3 = 8 kg. k = 327 N/m for all three blocks. The elevator accelerates upwards at 3.8 m/s^2.
Net force of block one would be equal to force applied by top spring minus weight of system, since top spring is holding all 3 blocks.
F1 = 4*3.8= Fs,top - Wsystem = Fs,top -...
Note: I am self-studying Material and Energy balance courses and I haven't done fluid mechanics yet.
Case 1) Consider the manometer in the figure below. Levels on both sides of the manometer which are open to the atmosphere are equal.
If we analyse the forces acting on the left side of the...
Good morning,
I’m new to the forum, thank you in advance. I’m an Italian med student based in France.
I’m struggling to find an equation for a project that I am following.
I should measure the reactive force at the level of the gastrocnemius (shown in the figure, red arrow). I know the force...
Consider a merry-go-round (carousel) with a tube fixed radially on it. I use a pole to push a bowling ball slowly through the tube towards the center. (Slowly, so that the kinetic energy is negligible when the ball reaches the center. Also assume zero friction).
What happens to the work that I...
If F = 0 then a = 0. When the equation is written in the form F = m*a, it appears ok, that whatever the mass be, LHS and RHS of the equation are equal so no problem. But when the same equation is written in the form m = F/a, then m becomes undefined when F = 0 and a = 0. It occurs to me that...
Sorry for this beginner's question, but...if F=ma, then force is all about acceleration. But if vehicle A moving at constant velocity V hits a wall, and vehicle B moving at constant velocity greater than V hits the wall, then B hits the wall with greater momentum than A and does greater damage...
Hello All:
read a paper related to electromagnetic force and its applications in acceleration of charges particles , some thing came up in it , they drive a force applied on the particle called Faraday force = [1/2B]* [dB/dt]*m*v
B magnetic field , m mass of the particle , v the velocity of...
I tried using the distance between r2 and r1 and plugging them into the equation for i, j, k. >>
So for the force in the x direction it was k*(4E-6*4E-6)/(4-9)^2. The answer I got was wrong according to webassign. Can someone please tell me what I am missing?
I am struggling with part b of the question attached in the screenshot. For part a, I simply add the components of the given forces.
I tried calculating the moments using vector cross multiplication, but I don't know what to do after that or even if that step is useful.
How can I determine the downward force of the rod with the given cylinder pressure and mechanical linkage? Do I sum my moments about the pivot? I calculated M=950xCOS(75.732)x7.81 + (X)SIN(63.414)x9.4 which resulted in 1828lbs. I get 217 lbs which does not seem right.
My understanding is that the Net Force = Force Applied + Frictional Force. The net force is F=ma, so net force = 576N. Now 576N=450N + Frictional force, so frictional force has to be 126N.
My confusion is this:
1. Force is a vector, and the frictional force opposes the direction of motion...
so this is what the FBD is.... but to be fair, to me this one looks as if the normal force in the direction of the radial line, yet it isn't????
here in the solution, it's not along the radial line, whys that???
so I was wondering. there is this normal force on the can from the path. And there's this formula to find the angle between the radial line and the tangent or also between the normal force and either the radial or theta axis. the formula is ##\psi = r/dr/d\theta##. The thing is that here they...
I have found the work done for 100 N, 70 N and 30 N force, but I don't know how to find work for 100 N force that is acting downwards.
Force 70N:
W=F×d = 70 ×0=0 Nm (Force is perpendicular to the distance moved)
100 N force:
W=F×d=100×0.5=50 Nm
30N force:
30×-.5= -15Nm.
Please check whether...
Roughly, how much force does it take to make 1 mm surface bump of diameter 16 mm circle area out of 1 mm thick steel plate of far larger area (e.g. a muscled hand pounding it laid over the base with 16 mm dia. hole by M16 bolt medium is viable enough) ?
Hello everyone!
Events in my current webnovel have reached the limit of confidence in my physics reasoning, so I'm here to ask for confirmation of my estimates of what would happen from experimentation with force fields. While the setting is fantasy/magic based rather than superscience, I still...
Hi everyone,
I'm an electrical engineer working on making a linear model for a power take-off system. I've gotten inertial, friction, and hydraulic/electric components done, but what is really confusing me is the gas system; I haven't taken ANY thermodynamics. To simplify it, it is modeled as a...
I'm designing a pivot lift system to lift my movie projector up when not in use. I've designed the parts and begun 3D printing, but am concerned that the 3D print won't be strong enough, so I may bite the bullet and have the parts CNC machined. If I do that I want to be certain that I have the...
What have mistakes/wrong assumption have I made in solving this question?
I tried to solve the problem this way
N.B. I assume that the j hat direction is up.
When we throw a ball in a projectile motion, the ball follows a parabolic path due to gravity. And we see that earth moves in an elliptical path around the sun due the same force of gravity. So why two paths are different due to the same force?
Explain using the idea of central force
Currently I have 6 casters with a 90lb capacity, but I need this “table” (closest description to the shape) to hold over 500lbs. If I double up the wheels on the “legs” will that increase the weight capacity?
I just launched a 2.2kg model rocket that stands about 5 feet tall and has a airframe that is 4 inches in diameter. I am trying to find how much the impact force is when the rocket hits the ground at 16MPH.
Whats the best approach? Momentum? KE? or something else:)
thanks
I have attempted to use the law of conservation of momentum.
The Areas are the lengths marked with the red striped line times the length into the paper, and the Forces F1 and F_hydro are the hydrostatic pressure and hydrodynamic forces respectively (acting on the plate) (The x y components is...
For this part(b) of this problem, how is the magnitude of the total electric force zero?
I thought it would be:
If they asked for the total electric force, then I would have said zero because the two electric force vectors cancel.
Many thanks!
Greetings all,
I'm new here and hope I'm asking this in the correct thread. So, the question is; where you have a vacuum created by a "flow through" liquid witin a large diameter container exerting suction force upon a smaller diameter input tube submerged in a liquid, does the surface area of...
Hi guys,
I am struggling to find the answer on Google and at forums. I am experimenting with two sheets of aluminum foil that are separated by a thin plastic foil. In theorie they should be attracted to each other if I connect one foil to power and other to ground of a DC voltage source. I am...
Im prototyping a machine to lower liquid from a height using a chains and sprockets. Essentially liquid will fill at top, be lowered over a distance of 4.8 metres then emptied at bottom. The liquid needs to be lowered at a slow pace due to resistance on the output shaft, I am considering...
My answer : According to the question, the glass and the air inside it entered the water. Let's assume that the net force becomes zero at a moment, that is, the sum of the weight force and F is equal to the buoyancy force. By going down in the water, the gas volume decreases, so the buoyancy...
At the beginning, I just looked for the highest point in the graph, which is approximately 90 \frac m s^2.
Then I plugged it in the formula F = ma and got the force equaled to 0.045 N.
However, when I looked back, the graph is about the change in acceleration. So really, I'm dealing with...
I am looking for a formula that I can use to find out how high a steel rod or ball will jump up.
If I hit mass M with force F how high will it jump up. If there is a program that would be great.
every thing will be in pounds
So if ball or rod of 10 lbs is hit on the bottem with 14 lbs of force...
OK folks, I'm sure this will be easy for the brains in this forum, but I've always been curious as to how this is done. So if you have situation where you have a ladder leaning on a wall and a person is some way up the ladder. If you know the length of the ladder (3m), the angle the ladder is...
So i got some equations but i think i am missing something, my main doubt is what is the relation between dx / dt and v(o) [ here] . Workings in attachment
I've just come across the following line while studying (Young & Freedman) and found it amusing.
It sounds like a dirty family secret we discuss once and then should never mention again :biggrin:
My approach is to use the definition of the Force with ##\displaystyle F = \frac{dp}{dt} = \dot{m} v + m \dot{v}##. Since ##m(t)## decreases linearly, I should be able to set ##m(t) = M - \Phi t##, thus ##F = - \Phi v + (M - \Phi t) \dot{v}##, which gives ##\displaystyle v = -\frac{ F - (M -...
What I did was plug in the outer radius time the force into the torque and then the mass moment of inertia is equal to m*ro^2 so then I plugged in the mass times the radius of gyration squared into I and solved for a but this is not right.
I already solved for part a, setting the sum of the Torques of the arms and deltoid equal to 0 and subbing in values which lead to a tension force of 870N in the deltoid.
For part b, I remembered the law of static equilibrium, so the summation x and y components of all the forces in the system...
The contact force on 10 kg due to 20 kg is taken as Fc2
m1 = 30kg, m2 = 20kg, m3 = 10kg
F_A = Applied force
μ = 0.15
Net force = mass X acceleration
Fc2-Friction force = m3 X a, where a = F_A / (m1 +m2+ m3). Therefore the equation becomes
Fc2 = m3 F_A/(m1+m2+m3) + μN
= F_A/6 +15
I...
So far I have used methods of joints to determine the forces at point E, D, and C. However, there is also a pulley attached to point D and E which I included in the sum of forces, but I'm not sure if that's the correct way to apply them. Every force I've calculated so far has also been in...