When we push an object on the surface, if I push hard enough such that it reach the maxium static friction of the object then it start moving with a constant speed and F_push = F_friction. But when I realease the object F_push immediately become zero remain only F_friction. Does the friction...
Friction happens because of adhesion between high points of the pertubrances of the two surfaces. The pertubrances deform. More the force between surfaces more deformation. Is the deformation elastic or inelastic? Will the surface of one body become smoother if pressed with hydraulic press?
Hello,
When we consider a block sitting on a surface, the gravitational force ##W## and the normal force ##F_N## are applied to the block. Both equal i magnitude and opposite in direction. We call the normal force the reaction force exerted by the surface on the block.
Now we consider the...
As can be seen below we have 3 ring magnets. The middel one floats in between the other two. We want to know how to calculate the air friction of the middle ring magnet if this rotates.
For a model, I am making I need to know the friction between a motor and a flywheel. The electric motor is on the side of the flywheel and the idea is when this motor turns the flywheel will start to rotate due to the friction between them. I however can not find a good way to calculate this...
For the box I understand it’s just normal and force of gravity as well as tension pulling them, it was declared to have no friction so it just points up down and right. It’ll be accelerating right.
The second person again has the normal force, gravity and the tension going to the left as a...
This is a homework problem of my grand daughter. The question is to find out the conditions of an object M on a slope with angle shown and applied force "F". I find there are 3 conditions, sliding up, sliding down and not moving. This is my work. I just want to get comments on my work:
At the...
Suppose a cylinder is launched on a horizontal frictional surface such that it has initial translational velocity v and zero angular velocity .the kinetic friction would be applied between the contact points of the cylinder and the surface, opposite to the direction of the translational motion...
Hi I'm just a student so this:
F = - mg - kv
(Being kv friction) doesn't sound intuitive. Looks like both are going in the same direction... I just don't get it. But that's what my book says (Symon mechanics) and my classmates are also using "-"kv .
Can someone explain me please? Shouldn't...
My assumption says,as A moves to the right,there will be kinetic friction acting on it to the left and equal and opposite friction will act on B to the right,so it should move to the right keeping the center of mass go on moving with velocity mv/(m + M) to the right as there is no net external...
Hi
I have been wondering what is the difference between resistance force and friction coefficient. While doing research online I could not find a clear answer. Maybe someone here will now:bow:
According to my current understanding
rolling friction
rolling friction is the static friction (parallel to the surface on which the object is moving) applied by the frictional surface (rough surface) on the contact point or contact area of the object whose v≠Rw(v is translational velocity and...
In pure rolling the of the sphere contact points of the sphere are at zero velocity,how is friction opposite to the motion of sphere being applied to these points?how the frictional force f is bieng applied to the sphere?
How will the friction work on a sphere which is purely rolling on a horizontal surface such that both the sphere and surface does not deform. The sphere at any time t will only have one point of contact, which would continuously changing as the sphere rolls. Will The friction be applied to the...
Consider a block sitting on top of a table.
When we push the block rightwards, static friction opposes its motion by acting leftwards on the block.
By Newton's 3rd Law, static friction should act rightwards on the table.
There is now a net rightwards force on the table. Why doesn't the table...
Consider an object, say a ball, rolling at a constant speed without slipping to the right on a horizontal surface. Let's consider the ideal case, so no deformation of ball or surface. For rolling without slipping to occur, there has to be friction (static friction as the point on the ball that...
I have no idea how to start this other than that I think that Fn is 17.64N and Fnet is 0. But I don't have the mew, so I am not sure how I am going to get the force of static friction.
Do I determine this from the friction coefficients?
Such that because mu_b > mu_a I know that it'll push on B because it has a bigger friction coefficient.
such that this has nothing to do with the mass of the blocks? or does it?
f.e. can I take it to be in an arbitrary direction and then...
A force is given to the center of the object so the object rolls to the right without slipping. I understand that to provide clockwise rotation the static force should be directed to the left.
But if the force F is located at the very top of the object, the static friction is directed to the...
I have drawn three free body diagrams, one for each box and then I applied Newton's Second Law after choosing a reference frame rotated clockwise by ##\alpha##, with ##x## pointing south-east and ##y## pointing north-east and I got:
##\begin{cases}m_{1x}: -T+m_1g\sin(\alpha)+F_{fr_{12}}=m_1...
so I haven't looked at the solution yet, but I know that a 100% the velocity needs to be bigger, but analytically, I get a - sign instead of a + sign as you'll see at the final square root.
So for the first 15meters of the motion all you should know is that ##v_1 = 10.458 m/s##.
for the 2nd...
Hello everyone!
I'm watching this Walter Lewin lecture and am at 5:58 part of the video
I'm wondering how there's a frictional torque applied to the cylinder, my reasoning is that the object has forward velocity, and on a perfect cylinder, the slope of the incline touches the cylinder at a...
Hello everyone!
I'm reading this book and trying to get a more concrete understanding of friction and it's relation to Newton's third law. So in the solution he writes$$D - f - F_R = m_ta_x$$Where D is the driving force of the truck, f is the frictional force of the box on the truck, and...
Hi there!
First of all, I do not have a clear homework statement or relevant equations to give but I still put this thread in here because it's related to school work and I've previously got a warning for not doing so.
I'm a french student who is going to start his second year after high school...
How is it possible that friction makes car turn? From what I know, frictional force is acting along to the direction of the wheel turns.
When the car turns, the direction of the frictional force now act opposite to the direction of the wheel turns!
I'm sure if you rotate the steering wheel to...
when a railroad engine wheel slips on a rail as it tries to move forward i can see sparks mostly going in the rear direction. while thinking about what might happen in other situations, such as a moving engine (being pushed by its massive 100 car load, perhaps), i came to a simplistic case that...
The figure illustrates the situation. The radii of the larger and smaller discs are 2R and R, respectively. Their masses are M and 2M, respectively (the largst disc has the smallest mass).
Also, m=5/4 M, where m is the mass of the suspended object. The pulley is "massless" (negligible moment...
This is a problem that was posted here in 2003 and is now closed for replies. This question can be found at https://www.physicsforums.com/threads/friction-problem.662/
The answer in that old post didn't seem clear to me probably because it was highly summarized. There was no mention of static...
Summary:: I'd like to check my understanding of standard problems where a billiard ball resting on a plane is hit horizontally at some height above its center
So the situation is that a ball of mass ##m## and radius ##r## is at rest on a horizontal surface. There is friction between the ball...
Hi so with this question, I am really confused. Even from the start. Like it doesn't tell us where the force is acting on. From top of block, middle of block etc? And I know how to determine the direction of moment for something on a pivot, not in this scenario though. The answer is A. They did...
Suppose you have a heavy body placed on a surface. We apply a horizontal force such that it is on the verge of moving (maximum static friction). We measure this force and note it down. Now we cut the body from the top and remove a thin layer and again do the same thing. We apply a force and...
Imagine a solid body big and heavy. It will have friction between it and the surface when tried to move. Somehow the cluster of molecules opposes the push.
When free these molecules stick on surface and can be moved by a mere blow of wind but when bonded into a solid body the structure of large...
Water is made up of loose molecules but a body like ice is bonded strongly into a shape.
Imagine a ice brick. It will have friction between it and the surface when tried to move. Now it slowly starts melting. The molecules of ice will start sticking on the surface.
Somehow the cluster of...
A ladder is leaning against a frictionless wall and the floor. The force F of the wall against the ladder is what is opposing static friction f at the floor. I don't understand how the force F causes the ladder to slide to the left on the floor unless opposed by friction force f. See picture below.
In a system, the net internal torque should be 0.
If we have two fly wheels, one spinning with angular velocity w, and the other at rest and the flywheel at rest is dropped onto the other flywheel, the two fly wheels reach the same angular velocity due to friction between the two wheels. I am...
Static friction is known to provide centripetal force when a car turns.
Assuming uniform circular motion, my questions are
1. Is the static friction of each wheel points toward the center of turning circle or it's the combined forces of all four wheels that has to point toward the center of...
When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 2.19 m/s. The mass stops a distance S2 = 2.1 m along the level part of the slide. The distance S1 = 1.18 m and the angle θ = 28.10°. Calculate the coefficient of kinetic friction for the mass on...
How long would a lever have to be for the weight on the effort arm to generate the equivalent energy of a single hydroelectric dam generator? State weight/force in kg.
My ponderings:
The weight could be anything, would be interesting to use water weight from a passive air water condenser in a...
I want to determine the normal flow depth in a perfectly horizontal circular conduit. The system characteristics are known (Internal pipe diameter, Mannings roughness, Discharge). However, I am not sure how to calculate the normal flow depth. When using Manning's equation one can find the normal...
So for the work done by the kinetic friction, the displacement along the incline is ##s## as given.
What I canNOT understand is why the displacement in the y-direction is used for the work done by gravity i.e. ##W = -mgh## where ##h## is the displacement in het y-direction. This instead of the...
Here's my list of variables and things to account for:
m=100kg
Wnc=5000J
Wfriction=-500J
-Kinetic energy will be doubled (though I don't know how that plays into it exactly)
-I don't think there's any PE because it's on level ground
My idea of what the equation might be:
Wnc +1/2mv^2initial =...
Could I please ask for help with the following:
Here's my diagram:
The forces at the hinge (green) are internal forces.
For the whole system resolving vertically gives:
R1 + R2 = 4W
and horizontally gives:
F1 = F2
For the rod of weight 3W only, taking moments about B gives:
F1 * L *...
The answer should be no change but we know ##F=ma##. In this eqn when acceleration increases mass decreases for same force. So why not here? If normal is doubled ##\mu## should be halved.
a) From impulse-momentum theorem I have: ##J=mv## so ##v=\frac{J}{m}## and since the ball doesn't slip ##v=\Omega b## so ##\Omega=\frac{J}{mb}## and ##\dot{\theta}=\frac{v}{a+b}=\frac{\Omega b}{a+b}##.
b) I considered the angular impulse: ##-J(a+b)=I_0 \Omega_0 \Rightarrow...
F.B.D Of first block
(I have shown only the horizontal Forces)
f1(max) = μ (1kg)(g) = 0.5 * 10 = 5N
F.B.D Of the second Block
f2(max) = μ (3kg)(g) = 15N
Now the string will become taut and the tension will start acting when f = t = 5N
But for 0<f<5N there will be no motion between the 1 kg...