In mathematics, the Laurent series of a complex function f(z) is a representation of that function as a power series which includes terms of negative degree. It may be used to express complex functions in cases where a Taylor series expansion cannot be applied. The Laurent series was named after and first published by Pierre Alphonse Laurent in 1843. Karl Weierstrass may have discovered it first in a paper written in 1841, but it was not published until after his death.The Laurent series for a complex function f(z) about a point c is given by
f
(
z
)
=
∑
n
=
−
∞
∞
a
n
(
z
−
c
)
n
,
{\displaystyle f(z)=\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n},}
where an and c are constants, with an defined by a line integral that generalizes Cauchy's integral formula:
a
n
=
1
2
π
i
∮
γ
f
(
z
)
(
z
−
c
)
n
+
1
d
z
.
{\displaystyle a_{n}={\frac {1}{2\pi i}}\oint _{\gamma }{\frac {f(z)}{(z-c)^{n+1}}}\,dz.}
The path of integration
γ
{\displaystyle \gamma }
is counterclockwise around a Jordan curve enclosing c and lying in an annulus A in which
f
(
z
)
{\displaystyle f(z)}
is holomorphic (analytic). The expansion for
f
(
z
)
{\displaystyle f(z)}
will then be valid anywhere inside the annulus. The annulus is shown in red in the figure on the right, along with an example of a suitable path of integration labeled
γ
{\displaystyle \gamma }
. If we take
γ
{\displaystyle \gamma }
to be a circle
|
z
−
c
|
=
ϱ
{\displaystyle |z-c|=\varrho }
, where
r
<
ϱ
<
R
{\displaystyle r<\varrho <R}
, this just amounts
to computing the complex Fourier coefficients of the restriction of
f
{\displaystyle f}
to
γ
{\displaystyle \gamma }
. The fact that these
integrals are unchanged by a deformation of the contour
γ
{\displaystyle \gamma }
is an immediate consequence of Green's theorem.
One may also obtain the Laurent series for a complex function f(z) at
z
=
∞
{\displaystyle z=\infty }
. However, this is the same as when
R
→
∞
{\displaystyle R\rightarrow \infty }
(see the example below).
In practice, the above integral formula may not offer the most practical method for computing the coefficients
a
n
{\displaystyle a_{n}}
for a given function
f
(
z
)
{\displaystyle f(z)}
; instead, one often pieces together the Laurent series by combining known Taylor expansions. Because the Laurent expansion of a function is unique whenever
it exists, any expression of this form that actually equals the given function
f
(
z
)
{\displaystyle f(z)}
in some annulus must actually be the Laurent expansion of
Homework Statement
Write TWO laurent series in powers of z that represent the function
f(z)= \frac{1}{z(1+z^2)}
In certain domains, and specify the domains
Homework Equations
Well that's my prob, not sure what the terms in the Laurent series are
The formula I'm looking at is...
I understand perfectly well how to do Taylor series, but I am foggy on these Laurent series. Say, we have something like,
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I think I need to use the taylor series expressions for sin(z) but otherwise, I am not sure what to...
Say we have the function:
\frac{1}{\left( z-1 \right)\left( z+2 \right)}
Using partial fractions,
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My question comes in on why and how these equations are manipulted for different regions.
Now for a)...
Homework Statement
Let D be a subset of C and D is open. Suppose a is in D and f:D\{a} -> C is analytic and injective. Prove the following statements:
a) f has in a, a non-essential singularity.
b) If f has a pole in a, then it is a pole of order 1.
c) If f has a removable singularity...
This is more of a general question than a specific question.
----------
Find the annulus of convergence for the Laurent series
\sum_{n=-\infty}^{-1} \left( \frac{z}{2} \right)^n + \sum_{n=0}^\infty \frac{z^n}{n!}
--------
I know what to do for the second series, but I am not sure about the...
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\mathbb{C}((t)) = \{t^{-n_0}\sum_{i=0}^{\infty}a_it^i\ :\ n_0 \in \mathbb{N}, a_i \in \mathbb{C}\}
What is its algebraic closure? My notes say that it is "close" to:
\bigcup _{m \in \mathbb{N}}\mathbb{C}((t))(t^{1/m})
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don't even know where to start on it
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Laurent series of the function f(z)=1/z^2 for |z-a|>|a| .a is not equal to zero...
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I need help with a problem from Complex Analysis. The directions say find the Laurent series that converges for 0<|z|<R and determine the precise region of convergence. The expression is : e^z/(z-z^2). I understand how to do the other 7 problems in this section but not this one. Can someone...
My question is about the coefficients of a complex laurent series. As far as I know, there are three kinds of series: those which converge in a finite circular region around the expansion point z0,(aka taylor series), those that converge in a ring shaped region between two circles centered at...