Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification". When this number is less than one, it refers to a reduction in size, sometimes called minification or de-magnification.
Typically, magnification is related to scaling up visuals or images to be able to see more detail, increasing resolution, using microscope, printing techniques, or digital processing. In all cases, the magnification of the image does not change the perspective of the image.
Homework Statement
How do I find the relationship of magnification to the graph of "Object Distance vs. Image Distance" or the graph of "Inverse Object Distance vs. Inverse Image Distance" for data points collected from a light box and a convex lens?
Basically for the lab I used a light...
Using the mirror equation and the magnification equation, find the four properties of the image formed in a convex mirror with a radius of curvature of 1.5 m, if the object is 80cm from the mirror and is 0.25 m high.
my question: what do they mean by 4 properties?
I was wondering why the magnification of a telescope is not considered negative since it is inverted. I know it doesn't really matter much since all you are trying to do is get a larger image but the sign convention should still be followed I think. The book I am using is Giancoli Physics for...
Hey guys, I'm in panic mode right now and was just hoping if you guys knew a bit about magnification? Well basically i did a lab and in the lab we were supposed to observe and measure pollen tube length at 40x. My partner didn't follow this and measured the lengths at different magnifications. I...
A mirror is required with magnification 9.5 when an object is 14mm from the mirror
What is the focal length
My attempt:
M=v/u
9.5=v/14
v=133
1/f = (1/v)+(1/u)
1/f=(1/133)+(1/14)
f=12.67
Since no object is magnified when the created image is outside of 2f
this answer can't be...
If I have a converging lens, of focal length f, and magnification of the image m, where q is the distance of the image from the lens show that q = (1+m) f
m = - q/p
1/f = 1/p + 1/q
I just need to show that they are equal, but I am getting confused with the maths..
q= (1 - (q/p))...
Primary focus magnification?
Hello all:
My name is Miguel, from Buenos Aires.
I have a question... is it right in formal optics to name "magnification" the below formula or "focal distance equivalent" of a camera attached in primary focus (without telescope ocular and camera objetive, of...
Homework Statement
The object in Figure P23.50 is midway between the lens and the mirror. The mirror's radius of curvature is 20.4 cm, and the lens has a focal length of -16.9 cm.
http://www.webassign.net/sf5/p23_54.gif
Figure P23.50
A. Considering only the light that leaves the object...
Homework Statement
A small object of length dL is placed on the axis of a converging mirror of focal length f. The center of the object is a distance o from the mirror. Determine the length of the image and thus effective determine a longitudinal m' = dL'/dL for the lens.
Homework...
In my textbook when talking about magnification, said "You will notice that there is slightly greater magnification when the image is focussed at the near point of the eye [i.e 25cm] than when the eye is relaxed and the image is at infinity."
I assume they are talking about angular...
Question:
A lens produces a real image that is twice as large as the object and is located 15 cm from the lens. Find (a) the object distance and (b) the focal length of the
lens.
m = \frac{-i}{p}
So the image is twice as large so obviously m = 2 . The lens produces a real image that...
Hi,
I did a homework problem in which I was to show that a refracting telescope, modeled as a sequence of two thin lenses separated by a distance equal to the sum of their focal lengths, is capable of producing angular magnification. In my course we have been solving these questions in...
An object is moved along the central axis of a spherical mirror while the lateral magnification m of it is measured. Figure 34-32 gives m versus object distance p for a range of p. What is the magnification of the object when the object is 36 cm from the mirror?
I understand that m=-i/p but...
Question
An object is a distance of 23.4 cm from the center of a silvered spherical glass Christmas tree ornament which has a diameter of 5.70 cm.
A What is the position of its image?
B What is the magnification of its image?
I think the object can be treated as a convex mirror.
s...
Here is the problem I am working on:
Two lenses that are L = 38 cm apart are used to form an image, as shown in Figure 26-52. Lens 1 is diverging and has a focal length f1 = -7 cm; lens 2 is converging and has a focal length f2 = 16 cm.
[a] Determine the distance from lens 1 to the final...
Please help!
# A telescope has an objective of focal length 50 cm and an eye piece of focal length 5 cm. It is focused for distinct vision on a scale 200 cm away from the objective. What is the linear magnification of the telescope numerically? Also what is the magnifying power of the telescope...
I'm having problems with the following problem:
A person who has a near point of 25.0 cm is looking with unaided eyes at an object that is located at the near point. The object has an angular size of 0.012 rad. Then, holding a magnifying glass (f= 10.0 cm) next to her eye, she views the image...
Hello everyone, I seem to be getting all the mirrors right that where concave but now i have a convex one and it doesn't seem to be working when im' finding the image distance and magnification/properties.
Here is the problem:
Heres my work: both the i and the m where wrong, i also tried...
Assuming an object is emitting/reflecting a finite number of photons, then, there is a magnification procedure that will magnify the image of that object so much that the emitted photons will be so dispersed that the image will become unrecognizable. Do we know what this maximum is? How does it...
I have an object that is surrounded by air and sits a distance U=30 from a convex surface. The convex surface has a radius of R=5. The index of refraction of the refracting media is n=1.33. How do I determine the magnification of the object?
Hi; Could someone please help me with this question: A small insect is placed 5.37 cm from a +5.84 cm focal length lens. a) Calculate the position of the image. b) Calculate the angular magnification.
For part a I used the lens equation 1/f = 1/d object + 1/d image, and I the position of the...
I know that magnification of a single convex mirror is always positive (that is, greater than 0) based on f<0, but does the size of the magnification depend on the magnitude of the object distance?
Need Help With Lens!
An object is placed 10cm in front of a convex lens of focal length 20cm. Where is the image formed and what is its magnification??..Your solution should include an accurately drawn ray diagram?
Pleeez help me with this question?...im so stuck??
Thanks.
A concave spherical mirror can be used to project an image onto a sheet of paper, allowing the magnified image of an illuminated real object to be accurately traced. If you have a concave mirror with a focal length of 8.0 cm, where would you place a sheet of paper so that the image projected...
can anybody tell me how much maginfication it takes to see certain micro organisms such as e coli, tetanus, botulism etc. ? where can I find a suitable microscope that doesn't cost an arm and a leg?
What am I missing here?
A person looks at a gem using a converging lens with a focal length of 15.0 cm. The lens forms a virtual image 26.0 cm from the lens. Determine the magnification.
(1/p)+(1/q) = (1/f)
p=?
q=26 cm
f=15 cm
(1/15)-(1/26)= Ans^-1 = 35.5 cm (p)
Magnification=...
There is this house down the street which has one of those new, white plastic vinyl fences around the front yard.
This particular fence is constructed in such a way as the vertical members are the width of the spacing between members(about 2 inches or so)
More importantly, the top of the fence...
Hello, Faizan Here
Can anyone show ne how to derive the formula of specific heat capacity pls.? Also i need the derivation of the formula of magnification power of a lens? Thanks in advance to anyone who helps me.
problem 24. A person looks at a gem using a concverging lense with a focal length of 13.7 cm. The lense forms a virtual image 35.5 cm from the lense.
a) Find the magnifaction.
This is what I have done so far:
f=13.7 , q= -35.5
1/p+1/q=1/f
1/f-1/q=1/p...
Here is a true story for your consideration. I once worked with a guy who some years previously had taken a direct hit by lightning - right in the head. As you might imagine, I asked him what it was like. First, he spent about six months in the hospital. It put him in a coma among other things...