Homework Statement
See figure attached for problem statement, as well the solution.
Homework Equations
The Attempt at a Solution
I'm confused as to how he is writing these equations from the boundary conditions.
What I understand as the boundary condition for D is,
\hat{n}...
Homework Statement
If one were to consider a parallel plate capacitor with a distance d between them connected to a battery and a vacuum space between the plates. Will the integral form of Gauss' Law to any closed surface between the plates that does not cross either plate hold? If not, what...
Homework Statement
The negative plate of a charged, isolated parallel plate capacitor with a vacuum gap of width d and carrying a surface charge density s is uniformly irradiated with a short pulse of ultraviolet light whose photon energy is just enough to release a photoelectron at the...
Lets assume that there is a parallel plate capacitor connected across a supply of V volts. Then, there is charge redistribution between the plates such that finally the potential of positive plate wrt the negative plate is V volts. Let us assume air is the dielectric between the two plates. Now...
1. Homework Statement
PLEASE DO NOT DELETE THIS POST, MODS, IT MAY LOOK LIKE THE SAME QUESTION AS BEFORE, BUT IT IS NOT, IT IS A TOTALLY DIFFERENT PART TO THE QUESTION.
consider a parallel=plate capacitor with square plates of side L and distance d (<<L) between them, charged with charges...
Homework Statement
Find the E field of a parallel plate capacitor tilted at 45 degrees from vertical and moving at a speed v. each plate has plus or minus \sigma_0 for charge density.
The Attempt at a Solution
Well the E field in rest frame would be E= \frac{\sigma_0}{\epsilon_0}...
I've been thinking about this for a while, and I think people of PF will be able to answer it haha
In parallel plate capacitor, we charge the capacitor by connecting a power supply/battery. Then, after few minutes, the capacitor is fully charged with different signs, + and -. With that...
The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 × 10-3 m2, and the spacing between the plates is 6 × 10-3 m. There is...
Homework Statement
Two circular disks spaced 0.50 mm apart from a parallel-plate capacitor. Transferring 1.90 x 10^9 electrons from one disk to the other causes the electric field strength to be 1.90 x 10^5 N/C. What are the diameters of the disks (in cm)?
Homework Equations
E = Q /...
Homework Statement
A Parallel Plate Capacitor connected to a 12 V source is charged to 21 micro coulomb. If the capacitor is filled with an oil of dielectric constant 3, then the charge stored is ---
Homework Equations
The Attempt at a Solution
C = q / V, substituting the values i...
Homework Statement
Ok so when you have a parallel place capacitor with a charge +Q on one plate and -Q on the other, you can use Q = CV etc., My question is: what happens when the two charges differ - i.e. one plate is Q1, the other is Q2. What is the capacitance, potential difference etc...
Homework Statement
A parallel plate capacitor has a charge of 50pC
area = 10mm^2
dielectric material permittivity = 2.5
distance between plates = 0.5 mm
find the electric field
the potential difference between the 2 plates
the energy stored in the capacitor
Homework Equations...
Homework Statement
A parallel plate capacitor with plates of area A and separation d is imbedded in a large volume filled with a material with electric conductivity σ. Determine the total current I if the two capacitor plates are maintained at a potential difference Vo. Explain how such a...
Homework Statement
A parallel plate capacitor has rectangular plates measuring 44.0 cm by 30.0 cm, and can be charged to 1600 V maximum ΔV without electrical breakdown. The gap between the plates is fulled with mylar dielectric (κ=3.2). Find the thickness of the dielectric.Homework Equations...
Homework Statement
A 4.0-nF parallel plate capacitor with a sheet of Mylar (κ = 3.1) filling the space between the plates is charged to a potential difference of 120 V and is then disconnected. (The initial capacitance including the dielectric is 4.0 nF.)
(i) How much work is required to...
I'm building a parallel-plate capacitor for a capacitance sensing circuit. If I let the capacitor fully charge, and then pulled the plates apart by 5 cm, how would that change the capacitance? Is there a formula to figure that out?
I have tried this set of questions which is from i-vii, I believe I am going wrong at a certain stage, as at question vi, the voltage is clearly wrong, below is the questions and my attempt. Sorry for the long post, any help on pointing out where I have gone wrong would be much appreciated...
A parallel plate capacitor is defined of two circular plates with a radius of 12cm, it is separated by a dielectric sheet with a thickness of 2 microns (um) and relative permittivity of 6. It is charged with a potential difference of 110V.
The area of one plate I found is A=pie*R^2
=...
Homework Statement
A small object with a mass of 420 mg carries a charge of 30.0 nC and is suspended by a thread between the vertical plates of a parallel-plate capacitor. The plates are separated by 2.00 cm. If the thread makes an angle of 18.0° with the vertical, what is the potential...
In my high school calculus-based electricity class two students and I are trying to create a demo where we set up a parallel plate capacitor and have some dielectric material inside it that we can pull out slightly, and have it oscillate into and out of the capacitor.
Some ideas we have...
Homework Statement
d=10cm; U=180kV; er1=5; Ep1=50 kV/cm; Ep2=30 kV/cm; Ep=breakdown strength.
So you have a Parallel Plate Capacitor with two layers between the plates. One is air and it has the Ep2=30kV/cm, the other one has a Ep1=50 kV/cm and a relative permittivity of 5. The capacitor is...
Homework Statement
The plates of a large area parallel plate capacitor of area A are separated by a short
distance. The plates carry an equal but opposite charge \pm q.
(a) What is the electric field strength E(q,A) inside the capacitor?
(b) By how many percent does the electric field...
Homework Statement
The plates of a parallel plate capacitor measure 15cm x 15cm, and they are separated by 6cm. The capacitor is charged with a potential difference of 18V, then removed from the voltage source and kept isolated. A 15cm x 15cm x 3cm slab of dielectric material (k = 2.5) is...
Given: There are two parallel plates. The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 × 10-3 m2, and the spacing...
Homework Statement
Two parallel plates 0.700 cm apart are equally and oppositely charged. An electron is released from rest at the surface of the negative plate and simultaneously a proton is released from rest at the surface of the positive plate. How far from the negative plate is the...
Homework Statement
Two capacitors, identical except for the dielectric material between their plates, are connected in parallel. One has a material with a material with a dielectric constant of 2, while the other has a material with a dielectric constant of 3. What is the dielectric constant...
We have got a parallel plate capacitor . The distance between the plates is 2*h and each plate's dimensions are a,b . Between the plates there exists dielectric e1 in the volume 0<z<h and e2 in the volume h<z<2*h (out of the plates e0 ) , with e1,e2>>e0 . At z=h we place another plate with...
Homework Statement
A parallel plate capacitor is made of two circular disks. The distance between the disks is very small compared to their diameter. Initially, the disks are electrically neutral. After transferring 3.9x10^9 electrons from one disk to the other, the electric field...
A parallel plate capacitor of capacitance 10microfarads has the space between filled with material with
(dielectric constant k)= 4.0. The capacitor is charged to a potential difference of 2.0V . With the capacitor connected
to the battery the dielectric is removed.
1. The capacitance is F...
If the length and width of each plate of a parallel plate capacitor were doubled, and the spacing between the plates was also doubled, by what factor does the capacitance change?
I know that increasing the length and width of a plate increases its capacitance, and I thought that it was...
Homework Statement
Find the capacitance of the parallel plate capacitor with 2 dielectrics below. Given that the parallel plate capacitor has area A = WL and the separation between plates is d.
The Attempt at a Solution
My method is to use integration. First solve for two small...
Homework Statement
This is a question on a past paper of a second-year undergraduate physics paper.
A parallel plate capacitor is charged and the voltage increases at a rate of dV/dt. The plate radius is R and the distance between the plates is d.
(a) What is the electric field...
Assuming a Parallel Plate Capacitor of area A, separation distance d, plate charges \pm Q: and plate charge densities \pm\sigma:
In my textbook and in Wikipedia,
Electric Field of a charged plane with large or infinite area: \frac{\sigma}{\epsilon}
Electric Field between plates of...
Homework Statement
A square parallel plate capacitor with vertical plates of area A
and distance d, charged with a constant charge Q and is completely
filled with a dielectric material the same dimension as the gap between
the plates, with dielectric constant k and mass m. Assuming
the...
Hi evry1
I am trying to make a parallel plate capacitor , which am using to make a capacitive proximity sensor.
Question 1
I thought of making 2 plexiglass plates of dimension ( 90 X 50 X2.5 mm). An aluminium mesh is sandwiched between them. Now a positive voltage is supplied to...
Homework Statement
Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 1.8*10^9 electrons from one disk to the other causes the electric field strength to be 1.3* 10^5 N/C. What are the diameters of the disks?
Homework Equations
F=k(q1)(q2)/r^2...
I haven't figured it out yet, I find it way above my understanding of phyiscs
Suppose we have two circular parallel plates or radii r, both the same radius. They have a Voltage difference of V and they are separated a distance d. What would be the Electric Field in the whole space? Actually...
Homework Statement
An isolated parallel-plate capacitor (not connected to a battery) has a charge of Q=1.4x10^-5 C. The separation between the plates initially is d=1.2 mm, and for this separation the capacitance is 3.1x10^-11 F. Calculate the work that must be don to pull the plates apart...
Two parallel uniform charged circular conducting metal disks contains a charge of +Q and -Q on the inner surfaces, and little amounts of charge +q and -q on the outer surfaces. The detail is shown in the diagram.
Each plate has a radius R and thickness t. The separation of the plates is d...
A parallel plate capacitor is formed using a material whose dielectric constant is 3,00 and whose dielectric strength is 2x10^{8} V/m. The capacitance is 0,25x10^{-6}F and the capacitor must withstand a potential difference maximum of 4000V. Find the minimum area of the plates of the capacitor...
Homework Statement
When a certain air-filled parallel-plate ca-
pacitor is connected across a battery, it ac-
quires a charge (on each plate) of magnitude
214 μC. While the battery connection is
maintained, a dielectric slab is inserted into
the space between the capacitor plates and...
Homework Statement
A parallel-plate capacitor has plates of 10 cm^2 area separated by a 0.10mm layer of glass insulation with resistivity rho = 1.2x10^13 omega*m and dielectric constant k= 5.6. Because of the finite resistivity, current can leak through the insulation.
How do I Show...
Hello,
If I had a potential source (V) , a resistor R, and a parallel plate capacitor,
would the Electric field across the capacitor become
E = (V - IR)/L
L = distance between capacitor
or would the electric field simply become E = V/L
??
thank you!
Homework Statement
A Problem of Practical interest is to make a beam of electrons turn a 90 degree corner. This can be done wit ha parallel plate capacitor shown. An electric with kinetic energy of 3.0x10^-17J moves up through a small holes in the bottom plate of capacitor.
What is field...
Consider a parallel plate capacitor constructed from two circular metal plates of radius R. The plates are separated by a distance of 1.6mm
a. What radius must the plates have if the capacitence is 2.8 micro F?
b. if the separation between the plates is decreased, should the radius of the...
Homework Statement
A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V Volts. (C is the capacitance and U is the stored energy.) Give all correct answers concerning a parallel-plate capacitor charged by a...
Homework Statement
A parallel plate capacitor is changed to an electric potential of 334V by moving 3.78e16 electrons from one plate to the other. How much work is charging the capacitor?
Homework Equations
Delta V= Delta PE/ q
c=q/v
The Attempt at a Solution
Delta V= Delta PE/ q...
Homework Statement
I am doing a problem in my physics textbook where there is two concentric hollow spheres and the space between them is filled with a dielectric substance. The question asks for the electric energy in this space.
Homework Equations
The only given equation for the C of...
The cell membrane in a nerve cell has a thickness of 0.12 micrometers.
(a) Approximating the cell membrane as a parallel plate capacitor with a surface charge density of 5.9 x 10^(-6) C/m2, find the electric field within the membrane.
(b) If the thickness of the membrane were doubled, would...