Parallel plate Definition and 275 Threads

Two parallel uniform charged circular conducting metal disks contains a charge of +Q and -Q on the inner surfaces, and little amounts of charge +q and -q on the outer surfaces. The detail is shown in the diagram. Each plate has a radius R and thickness t. The separation of the plates is d...

A parallel plate capacitor is formed using a material whose dielectric constant is 3,00 and whose dielectric strength is 2x10^{8} V/m. The capacitance is 0,25x10^{-6}F and the capacitor must withstand a potential difference maximum of 4000V. Find the minimum area of the plates of the capacitor...

Homework Statement When a certain air-filled parallel-plate ca- pacitor is connected across a battery, it ac- quires a charge (on each plate) of magnitude 214 μC. While the battery connection is maintained, a dielectric slab is inserted into the space between the capacitor plates and...

Homework Statement A parallel-plate capacitor has plates of 10 cm^2 area separated by a 0.10mm layer of glass insulation with resistivity rho = 1.2x10^13 omega*m and dielectric constant k= 5.6. Because of the finite resistivity, current can leak through the insulation. How do I Show...

Homework Statement A dielectric of dielectric constant 3 fills three fourth of the space between the plates of a parallel plate capacitor. What percentage of the energy is stored in the dielectric? E(r) = 3, distance between plates = d, thickness (t) = (3/4) * d, C=capacitance of the...

Hello, If I had a potential source (V) , a resistor R, and a parallel plate capacitor, would the Electric field across the capacitor become E = (V - IR)/L L = distance between capacitor or would the electric field simply become E = V/L ?? thank you!

Homework Statement A Problem of Practical interest is to make a beam of electrons turn a 90 degree corner. This can be done wit ha parallel plate capacitor shown. An electric with kinetic energy of 3.0x10^-17J moves up through a small holes in the bottom plate of capacitor. What is field...

Consider a parallel plate capacitor constructed from two circular metal plates of radius R. The plates are separated by a distance of 1.6mm a. What radius must the plates have if the capacitence is 2.8 micro F? b. if the separation between the plates is decreased, should the radius of the...

Homework Statement A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V Volts. (C is the capacitance and U is the stored energy.) Give all correct answers concerning a parallel-plate capacitor charged by a...

A capacitor with capacitance of C = 8.5±1 μF has a potential difference of V = 4.5±0.4 Volts. What are the charge on the capacitor and the error in this value, in μC? To find charge I just use Q = C*V correct? And how do I calculate the error? Thank you!

Homework Statement A parallel plate capacitor is changed to an electric potential of 334V by moving 3.78e16 electrons from one plate to the other. How much work is charging the capacitor? Homework Equations Delta V= Delta PE/ q c=q/v The Attempt at a Solution Delta V= Delta PE/ q...

Homework Statement A parallel-plate capacitor has plates with an area of 410 cm^2 and an air-filled gap between the plates that is 2.00 mm thick. The capacitor is charged by a battery to 560 V and then is disconnected from the battery. a.How much energy is stored in the capacitor? b.The...

Homework Statement I am doing a problem in my physics textbook where there is two concentric hollow spheres and the space between them is filled with a dielectric substance. The question asks for the electric energy in this space. Homework Equations The only given equation for the C of...

electron and parallel plate question >:( Homework Statement The diagram below shows an electron entering the region between the parallel plates of a cathode ray tube. The electron has an initial velocity of 4.8x10^7 m/s horizontally and enters the exact middle point between the plates. The...

Homework Statement The preceding problem was an artificial model for the charging capacitor, designed to avoid complications associated with the current spreading out over the surface of the plates. For a more realistic model, imagine thin wires that connect to the centres of the plates (see...

Homework Statement A particle with a mass of 2.0 x10^-5 kg and a charge of +2.0 microColoumbs is released in a (parallel plate) uniform horizontal electric field of 12 N/C a) HOw far horizontally does the particle travel in 5.0 s? b) What is the horizontal component of its velocity at...

The cell membrane in a nerve cell has a thickness of 0.12 micrometers. (a) Approximating the cell membrane as a parallel plate capacitor with a surface charge density of 5.9 x 10^(-6) C/m2, find the electric field within the membrane. (b) If the thickness of the membrane were doubled, would...

A parallel plate capacitor is constructed such that there are two different dielectric materials in between the plates, each occupying half the space in between . Still this capacitor can be modeled as a simple parallel plate capacitor with same total area A, plate separation d, but with an...

Homework Statement Which statements are correct/incorrect for two oppositely charged, isolated parallel plates: (C=capacitance, U=stored energy, +Q and -Q = charge on the plates). Correct Incorrect When the distance is doubled, U is unchanged. Correct Incorrect Inserting a dielectric...

Homework Statement Professor Milly Coulomb finds it takes 3.0 J of work to drag, at constant speed, a -9.0 mC charge between the plates of a parallel plate capacitor. (a) What is the work done by the electrical force in taking the charge between the plates? (b) What is the potential...

Homework Statement 1.) Consider a parallel plate capacitor with plates of area 1.36 m2 whose plates are 1.24 cm apart. The gap between the plates is filled with air (assume that κair is unity) and the positive plate has a charge of 10.5 nC on it while the negative plate has a negative charge...

Homework Statement A parallel-plate air capacitor is made by using two plates 10 cm square, spaced 4.7 mm apart. It is connected to a 15 V battery. If the plates remain connected to the battery and the plates are pulled apart to a separation of 9.9 mm. What is the new capacitance? What is...

Homework Statement A parallel plate capacitor is used as a vibration sensor. The plates have an area of 100cm^2, the dieelectric is air, and the dist between the plates is given by d(t)=1+.01 sin(200 t) mm A constant voltage of 200 V is applied to the sensor. Determine the current...

Problem: The drawing shows an electron entering the lower left side of a parallel plate capacitor and exiting at the upper right side. The initial speed of the electron is 9.42 x 10^6 m/s. The capacitor is 2.00 cm long, and its plates are separated by 0.150 cm. Assume that the electric field...

1.) Consider a parallel plate capacitor with plates of area 1.36 m2 whose plates are 1.24 cm apart. The gap between the plates is filled with air (assume that κair is unity) and the positive plate has a charge of 10.5 nC on it while the negative plate has a negative charge of equal magnitude on...

I keep getting the questions wrong. I'm so frustrated. I'd appreciate it if anyone can tell me what's wrong. Which statements are correct/incorrect for two oppositely charged, isolated parallel plates (Isolated means that the charge stays constant ): (C=capacitance, U=stored energy, +Q and...

Homework Statement a parallel-plate capacitor (2 plates) is filled with titanium dioxide which has a dielectric constant of 80. the area of each plate is 1 cm^2. a) what must be the spacing between the plates if one wishes to make a 10^-10 farad capacitor? b) if the dielectric strength...

Homework Statement two parallel plates have equal and opposite charges of 0.01 coulombs. the electric field between the plates is 10^5 Newtons/coulomb and the separation between the plates is 2mm. what is the capacitance of the plates? Homework Equations capacitance C = Q/V where Q is charge...

A point charge of mass 0.0836 kg and charge q = +6.84 μC is suspended by a thread between the vertical parallel plates of a parallel-plate capacitor, as shown in the figure below. If the angle of deflection is θ = 22.3°, and the separation between the plates is d = 0.0221 m, what is the...

Homework Statement I encountered the following capacitor problem on a recent test and it has brought up a couple of questions about the voltage and electric field of parallel plates. In summary my questions are: 1) How is the electric field between parallel plates quantitatively related...

A parallel-plate capacitor with only air between the plates is charged by connecting it to a battery. The capacitor is then disconnected from the battery, without any of the charge leaving the plates. A.) A voltmeter reads 50.0 V when placed across the capacitor. When a dielectric is...

Hello hello, What is the b-field for a parallel plate capacitor if the current J was found to be in the z-direction? I am told it will be in the z-direction as well. How so? Thanks so much!

Hey, I am having some troubles with this question, the question asks me to calculate the capacitance of a parallel platecapacitor where the plates are separated by 3mm, and in between the are three layers of dielectric 1mm thick with different relative permitivities. Do I find the total by...

Homework Statement I've two parallel plate as in attachment. The electrode area is A, when voltage are supply to the electrode, electrostatic force will be generated. Homework Equations Here, I would like to find the solution or equation of the generated force in x or y direction...

https://www.physicsforums.com/showthread.php?t=62593 I'm not quite sure how to obtain acceleration even after reading the suggestions. Help? Thank you.

Homework Statement An isolated 5.60 microfarad parallel-plate capacitor has 4.90 mC of charge. An external force changes the distance between the electrodes until the capacitance is 2.00 microfarads.Homework Equations W = Fd c = Q/VThe Attempt at a Solution My first instinct was to solve to the...

Homework Statement A parallel plate capacitor with A=125 cm2 and d=1.25 mm is charged to a potential difference of 10.0 V. What is the charge density on each plate? Homework Equations V = \frac{{\sigma d}}{{\varepsilon _0 }}\,\,\,\, \Rightarrow \,\,\,\,V\varepsilon _0 = \sigma...

[SOLVED] Capacitor problem Problem: A parallel plate capacitor with adjustible plate separation d and adjustible area A is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V Volts. (C is the capacitance and U is the stored energy.) Give all correct answers...

[SOLVED]Dielectric help Homework Statement To make a parallel plate capacitor, you have available two flat plates of aluminum (area = 180 cm2), a sheet of paper (thickness = 0.10 mm, k= 3.5), a sheet of glass (thickness = 2.0 mm, . k= 7.0), and a slab of paraffin (thickness = 10.0 mm, k=...

Hi, I was just going through a question in my Physics textbook today. In calculating the electric field (E=sigma/epsilon0) ... sigma = charge density = q/Area ... they have used the area as pi*r^2, I can't understand why this was done? shouldn't the area of the parallel plate capacitor be...

Question: An electron with a velocity of 3.00x10^6m/s[horizontally] passes through two horizontal parallel plates, as in the attached diagram. The magnitude of the electric field between the plates is 120N/C. The plates are 4.0cm across. Edge effects are negligible. a) Calculate the vertical...

Hi all. I'm struggling to understand something about PP capacitors. Let's say there is no battery connected to a PP capacitor. Why does the potential (V) INCREASE when the plates are moved farther apart? - we know that: dv = -Ed (in a constant E) however as d increases, E...

2 infinite parallel plates separated by a distance s are at the potentials zero and V0. find the surface charge densities on the plates. I got the answer that it first calculate E and then as 1. x=o, Ex = σ / ε, then could know σ 2. x=s, Ex = - σ / ε ---> here's what I don't know. why...

I am having a really tough time providing an argument for myself over why the answer is true: The question: A parallel plate capacitor is attached to a battery that supplies a constant potential difference. While the battery is still attached, the parallel plates are separated a little...

Homework Statement A parallel plate air-filled capacitor is being charged as in figure. The circular plates have a radius of 4.0 cm, and at a particular instant the conduction current in the wires is .280 A. A. What is the displacement current density (jD) in the air space between the...

The problem is: Consider a parallel-plate capacitor with plates of area A and with separation d. Find F(V), the magnitude of the force each plate experiences due to the other plate as a function of V, the potential drop across the capacitor. Express your answer in terms of given quantities and...

A parallel-plate capacitor has an area of 4.77 cm2, and the plates are separated by 1.06 mm with air between them. It stores a charge of 403 pC. What is the potential difference across the plates of the capacitor? alright so i changed the area to .0477m^2. then i changed the distance between...

Homework Statement Use an integral form of the Gauss law to show how the magnitude of D inside the capacitor depends on the charge on the plates of a parallel plate capacitor and their area. Homework Equations Gauss \int{E.nda}=\frac{\rho}{\epsilon_{0}} \nabla.D=\rho where div...

I've recently started studying Laplace's equation and it's solution under various simple circumstances in electrostatics. I tried to solve the equation for a parallel plate condenser system, but I couldn't meet the boundary conditions. I had two plates, one placed on xz plane at y=0 (with...

Homework Statement A parallel-plate capacitor has plates with an area of 445 cm2 and an air-filled gap between the plates that is 1.51 mm thick. The capacitor is charged by a battery to 575 V and then is disconnected from the battery. There is 4.311536113 x 10 ^-5 J of energy stored in the...