Statics is the branch of mechanics that is concerned with the analysis of (force and torque, or "moment") acting on physical systems that do not experience an acceleration (a=0), but rather, are in static equilibrium with their environment. The application of Newton's second law to a system gives:
F
=
m
a
.
{\displaystyle {\textbf {F}}=m{\textbf {a}}\,.}
Where bold font indicates a vector that has magnitude and direction.
F
{\displaystyle {\textbf {F}}}
is the total of the forces acting on the system,
m
{\displaystyle m}
is the mass of the system and
a
{\displaystyle {\textbf {a}}}
is the acceleration of the system. The summation of forces will give the direction and the magnitude of the acceleration and will be inversely proportional to the mass. The assumption of static equilibrium of
a
{\displaystyle {\textbf {a}}}
= 0 leads to:
F
=
0
.
{\displaystyle {\textbf {F}}=0\,.}
The summation of forces, one of which might be unknown, allows that unknown to be found. So when in static equilibrium, the acceleration of the system is zero and the system is either at rest, or its center of mass moves at constant velocity. Likewise the application of the assumption of zero acceleration to the summation of moments acting on the system leads to:
M
=
I
α
=
0
.
{\displaystyle {\textbf {M}}=I\alpha =0\,.}
Here,
M
{\displaystyle {\textbf {M}}}
is the summation of all moments acting on the system,
I
{\displaystyle I}
is the moment of inertia of the mass and
α
{\displaystyle \alpha }
= 0 the angular acceleration of the system, which when assumed to be zero leads to:
M
=
0
.
{\displaystyle {\textbf {M}}=0\,.}
The summation of moments, one of which might be unknown, allows that unknown to be found.
These two equations together, can be applied to solve for as many as two loads (forces and moments) acting on the system.
From Newton's first law, this implies that the net force and net torque on every part of the system is zero. The net forces equaling zero is known as the first condition for equilibrium, and the net torque equaling zero is known as the second condition for equilibrium. See statically indeterminate.
A physicist who does research in statics is called a statician.
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Homework Equations
n/a
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Homework Equations
The sum of the forces in the y-direction and x-direction are equal to 0.
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Homework Statement
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Homework Statement
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Homework Statement
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http://www.mypicx.com/uploadimg/1510974339_04192010_1.png
Homework Equations
The Attempt at a Solution
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Homework Equations
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The Attempt at a Solution
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Homework Equations...
Homework Statement
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Homework Equations
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The Attempt at a Solution
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Homework Equations
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Homework Statement
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Homework Equations
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Homework Statement
Homework Equations
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The Attempt at a Solution
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Here is the problem:
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Homework Statement
See figure.
Homework Equations
\sum F_{x} = 0
\sum F_{y} = 0
\sum M = 0
The Attempt at a Solution
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Homework Equations
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Homework Equations
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Homework Statement
See figure
Homework Equations
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The Attempt at a Solution
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The Attempt at a Solution
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Homework Statement
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http://img686.imageshack.us/img686/8831/45170185.jpg
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Homework Statement
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Homework Statement
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Homework Equations
Sum of moments about A=0:
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Homework Statement
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Homework Statement
In the attachment
Homework Equations
Sum of the forces in the X, Y, and Z
Sum of the Moments in the X, Y, and Z.
The Attempt at a Solution
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Two small spheres of 15 g each are suspended from a common point by threads of length 35 cm. Each thread makes an angle with the vertical of 20 degrees. Each sphere carries the same charge. Find the magnitude of this charge. Homework Equations
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Homework Statement
How come all thetas are equivalent?
Please take a look at this drawing http://tinypic.com/view.php?pic=2aahe3d&s=4
The Attempt at a Solution
By similar triangles?