In physics, work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement. A force is said to do positive work if (when applied) it has a component in the direction of the displacement of the point of application. A force does negative work if it has a component opposite to the direction of the displacement at the point of application of the force.
For example, when a ball is held above the ground and then dropped, the work done by the gravitational force on the ball as it falls is equal to the weight of the ball (a force) multiplied by the distance to the ground (a displacement). When the force F is constant and the angle between the force and the displacement s is θ, then the work done is given by:
W
=
F
s
cos
θ
{\displaystyle W=Fs\cos {\theta }}
Work is a scalar quantity, so it has only magnitude and no direction. Work transfers energy from one place to another, or one form to another. The SI unit of work is the joule (J), the same unit as for energy.
Mainly I want to know the following thing: electrons when excited they tend to want to go back to ground state, right? One way is by photons, but how does that work? Accelerating charges creates EM waves, but in this case there was no acceleration, right? Or is the term accelerating only a way...
I was reviewing physics stuff and I've managed to confuse myself.
I was reading about work (principles of ohysics, serway&jewtt):
-work is an energy transfer
-if work is done on a system and W is positive, energy is transferred to the system; if W us negative, energy is transferred from the...
If someone could advise what I've done wrong it would be much appreciated. How have they eliminated the initial and final for y, and simplify only to y? Also, how did they simplify to a positive 2? What algebraic steps have I missed? Thanks for your help.
My book states that, '∑Finternal=0∑Finternal=0. But the work done by them may or may not be zero.
Why is this true?
Edit: How can the work ≠ 0 sometimes?
I have pasted the image below after copying it from my desktop. The image becomes visible in the Post Composer as soon as you paste it. It also works if you copy from another web page.
I assume that JavaScript is able to grab the data from the clipboard and create an IMG element on the fly, and...
Okay say I have an object with kinetic energy and it collides with a stationary object.
The moving object does work. Work means energy spent thru a force and distance right?
So my question is once the energy gets used, does the moving object stop becuase it has no energy. Or is it stopped...
Hi folks.
Hope everyone is having a good day.
My name is Niko and I'm a software engineer and I'm pretty bored. Well you know, nowadays majority of software engineers don't create search engines for Google. And even ML if you think about it is pretty boring and consist mostly of preparing data...
Okay, say we have two balls(equal mass and size), 1 and 2. #1 has kinetic energy and #2 is at a standstill, they collide. Ignore all friction, heat, sound losses etc..
Now I know that 1 exerts a force on 2, hence doing work, which in turn uses its kinetic energy up. Therefore, 2 speeds up...
If the gas in the fusion reactor was compressed as much as possible wouldn't that increase the efficiency of the reactor and therefore make nuclear fusion possible. It would significantly increase the chances of hydrogen atoms colliding with each other and therefore creating much more power.
Gravitational energy is the potential energy a physical object with mass has in relation to another massive object due to gravity, so, does an object outside a gravitational field have no gravitational potential energy?
For example, the Earth is 4.5 billion years old, so it's gravity stretches...
I tried to apply the chain rule
$$X_{ik} = \frac {\partial U}{\partial \xi_{ik}} = \frac {\partial U}{\partial x_{i}} \frac {\partial x_i}{\partial \xi_{ik}} = \frac {\partial U}{\partial x_{i}} $$
and I got the force x-component of the force acting on ##P_i## I guess.
but I do not know what...
Okay, I am confused about work and what it is. I know the formula, W=FDCos(theta), so putting it in math terms doesn't help. I am trying to get a layman's/physical understanding of it.
Everything I read says it is equal to energy, so then I think it must be energy right, has same units? But...
Being an old school Newtonian engineering type, I have a model of a polarising filter that generally works for day to day stuff like taking photos, explaining sun glasses etc..
But it is clearly wrong.
Given that opening remark, the 'A' index, and the forum subject area, I trust you will...
Hello all:
I am asking for your personal experience , did you were able to work normally with your PhD studies ? What kind of work ?
Is it easier with theoretical PhD or an experimental one ?
Best
H.B.
So I have honestly no idea what kind of force is acting on the objects in each case, nor if work is being done. I attempted to identify the force for ‘d’ and I wrote the following: “work is being done and forces acting on the book are balanced, the weight of the book acts downwards and the...
A strategy I use when learning is to consult multiple books. It is great most of the time, but occasionally I find that there seems to be a contradiction between different books. For example, when proving the conservation of mechanical energy theorem, Tipler & Mosca claim that the total work of...
Work done in moving a charge around the circular path is 0 because the distance between the charges remain the same so there is no potential difference and delta(V)=0 but I thinkk some torque or external force must be required to move the charge around the circula path
I calculated friction = 1N.But since force is more than maximum friction,therefore lower block will not move and a force of 0.5N will be applied to upper block.
Therefore its work done by friction will be W=0.5×6=3 J.
But answer given is 1 J.
Can anyone help.
I'm looking for a person (professional physicist), that can make a proper validation of my model, that uses MHD, to describe interactions between geomagnetic field and weather patterns. Can someone give me advice, how to turn a private research into official science, despite my lack of any...
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Won't work. I visit the website https://www.google.com/url?sa=t&source=web&rct=j&url=https://en.m.wikipedia.org/wiki/Phase-shift_oscillator&ved=2ahUKEwiV4Y-26OHiAhUClawKHQhACO8QFjANegQIChAG&usg=AOvVaw0YoHKumGz0Xl3fYKtIRdFa and copied the schematic I saw...
I thought work is 0 because force is applying perpendicular to the spring's moving direction. these pulses are transverse pulse since those have amplitude, and pulse is moving horizontal, which means applying force horizontally, but spring is moving vertical. So my conclusion is "because pulse...
I am unable to get the wien bridge
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I know V = q/c and W = Vq and dW = V dq. But why is Work in charging a capacitor W = integral of q/c dq?
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$$\sum F_x = T - w_x - f_k = ma_x $$
$$ T = mg\sin(\theta) + mg\cos(\theta)\mu_k + ma_x$$
$$ T = (9.8 \frac{m}{s^2}) \cdot (\sin(41^{\circ}) + \cos(41^{\circ})) + (75kg)\cdot(0.25\frac{m}{s^2}) $$
$$T = 672.91 N $$
Having found the tension force, I can find the work done by the person who's...
Hi all,
I just want to gain some perspective as I am sure there are people in the same boat or have been where I am.
I am in the home stretch of my Ph.D in Biomedical Engineering, I have manuscript published and a couple more in the pipeline. I work in big data and how to use it to come up...
Image from Griffith, ED, 4th ed
Wm is the work needed against the back emf. If the current is steady (meaning not changing w.r.t. time) then there is no back emf. Hence, Wm = 0. But, B due to steady current is not 0. So, R.H.S is not zero. Could anyone please resolve this inconsistency?
Dear Physics Forums people,
My problem lies in understanding how the following line integral, which represents work done by the gravitational force, was calculated
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I wish to understand what...
$$W = - \int _ { a } ^ { b } \vec { F } \cdot d \vec { r }$$
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In this formula why there is a negative sign in the formula? I am not asking the sign of the total...
Using (2) on (1) give ## dU = -dW##... (4)
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we know that if the applied force is in the direction of the displacement then work done is positive.But in case of bringing 2 opposite charges from infinite to a certain distance,the work done is negative even the force and the displacement of the charge is in the same direction.
From...
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Hello everyone. I've always wanted to be a scientist, and in recent years I've figured out that I want to be a physicist. What are of physics has been a little harder to figure out, since there are a lot of areas that interest me, however, recently I have been getting more and more excited about...
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A thought experiment. Two rigid, concentric rings, joined together by a series of lightweight elastic radial spokes. These rings and a heavy mass are approaching each other, such that in the frame of the rings, the mass is traveling along the central, perpendicular axis and will pass through the...
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$$T=\frac {\sinh(at)} {a}=\frac{ \sum_{n=0}^\infty...
a magnetic field has a magnitude at time t of 4.5x10^-5 T +(2.6x10^-6 T/sec)t. the field points in the positive z-direction.
a rectangular wire loop, which is 0.3 meters by 0.4 meters, lies in the xy-plane.
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Precursor : Sign conventions regarding Work by the system/on the system may even vary among Physics textbooks and among Chemistry textbooks and as a rule of thumb it is better to clearly mark out the convention used by the text being referred to specifically and remain consistent with it...
I came up with this formula.
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I want to understand very deeply the meaning of the work integral formula:
\int m\frac{d\bar{v}}{dt}d\bar{l}
It is not enough for me to know that it was defined in this way, I want to know why it was defined in this way.
To start, what is the physical meaning of m\frac{d\bar{v}}{dt}d\bar{l}...
So the equation for work is W = F * s
F = m * a, so W = m * a * s
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Here is a little thought experiment related to magnetism and a perplexing question regarding its physics. Suppose we have a long cylinder of transparent plastic, and we press fit and then cement a circular magnet in one end of the cylinder with its north pole oriented into the cylinder. We also...
Hey everyone!
This might be a bit of a dumb question, but I'm not familiar with much in the programming world. I know a few languages that I've learned on my own (online) or through a course in school (MATLAB). When it comes down to coding outside of MATLAB or a website, I'm not sure where to...
I already solved the first part, but according the my book, the answer isn't quite correct. This is what I did.
Finally, I ended up with ##a=\frac{F(r-R\cos\alpha)}{Rm(\gamma+1)}##. But according to my book, the answer is ##a=\frac{F(\cos\alpha-\frac{r}{R})}{m(1+\gamma)}##, what am I doing...