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mncyapntsi
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- Homework Statement
- An electron is moving in a straight line with a velocity of 4x10^5 m/s. It enters a region 5.0 cm long where it undergoes an acceleration of
6.0x10^12 along the same straight line. (a) What is the electron’s velocity when it
emerges from this region? b) How long does the electron take to cross the region?
- Relevant Equations
- vf^2 = vi^2 + 2a(xf-xi)
Hello!
I have done this problem :
vf^2 = (4.0x10^5)^2 + 2(6.0x10^12)(5x10^-3)
so vf= sqrt((4.0x10^5)^2 + 2(6.0x10^12)(5x10^-3))
I get vf = 4.7 x 10^5 m/s
However, the textbook solutions says vf = 8.7x10^5 m/s.
Where did I go wrong?
Thank you for any help! :)
I have done this problem :
vf^2 = (4.0x10^5)^2 + 2(6.0x10^12)(5x10^-3)
so vf= sqrt((4.0x10^5)^2 + 2(6.0x10^12)(5x10^-3))
I get vf = 4.7 x 10^5 m/s
However, the textbook solutions says vf = 8.7x10^5 m/s.
Where did I go wrong?
Thank you for any help! :)