Force and work on a shopping cart

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The discussion focuses on calculating the work done by a shopper pushing a cart with a force of 35.0 N at a 28.0° angle over a distance of 46.0 m. The correct approach involves using the formula W = Force * displacement, specifically considering the horizontal component of the force, which is 35*cos(28). A participant points out a potential calculator error in the initial calculation, noting that simply multiplying 35 by 46 yields an incorrect result. The conversation emphasizes the importance of including the trigonometric function in the calculation to determine the accurate work done. Accurate calculations are crucial for solving physics problems effectively.
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Homework Statement


A shopper in a supermarket pushes a cart with a force of 35.0 N directed at an angle of 28.0° downward from the horizontal. Find the work done by the shopper on the cart as he moves down an aisle 46.0 m long.

What's going on?

Homework Equations


W = Force * displacement

The Attempt at a Solution


I used the formula above to get
F=35(cos(28))46= 1610

I don't know how else to approach the problem
 

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I think your answer is correct. The vertical component of the force pushes the cart into the floor but there is no movement in that direction so it doesn't do any work. Only the 35*cos(28) component does work as you wrote.
 


According to my homework website, I'm wrong from 10%-100%. =(
 


Maybe they are wrong?

It happens.
 


Hi aaronb,

aaronb said:

Homework Statement


A shopper in a supermarket pushes a cart with a force of 35.0 N directed at an angle of 28.0° downward from the horizontal. Find the work done by the shopper on the cart as he moves down an aisle 46.0 m long.

What's going on?

Homework Equations


W = Force * displacement


The Attempt at a Solution


I used the formula above to get
F=35(cos(28))46= 1610

I believe you are making a calculator error here. When you did the calculation, you left out the trig function, because 35 x 46=1610.
 


You're right!
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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