A 5.0kg mass is accelerated from rest at the bottom of the 4.0 m long

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In summary, the problem involves a 5.0kg mass being accelerated from rest on a 4.0 m long ramp by a falling 20.0kg mass over a frictionless pulley. The ramp is inclined at 30º from the horizontal and has a coefficient of kinetic friction of .26. The goal is to determine the acceleration of the 5.0 kg mass along the ramp and the tension in the rope during the acceleration. To solve this, a free body diagram is necessary and will provide a way to analyze the forces on the masses and find a solution using the equation F = ma.
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Homework Statement



A 5.0kg mass is accelerated from rest at the bottom of the 4.0 m long ramp by a falling 20.0kg mass suspended over a fictionless pulley. The ramp is inclined 30º ramp from the horizontal, and the coefficient of kinetic friction = .26.
a. Determine the acceleration of the 5.0 kg mass along the ramp.
b. Determine the tension in the rope during the acceleration on the 5.0 kg mass along the ramp.

Homework Equations



ma = mg - Ft for the lower block

The Attempt at a Solution



what do I do with the block on the inclined plane?
 
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  • #2
Hint: free body diagram.
 
  • #3
FBD is a necessity...
 
  • #4
You will have two of them - one for the block on the slope and one for the falling mass.
 
  • #5
As stated in the previous comments, a FBD is useful. With that you will be able to analyze all the forces acting on the masses and from there find the solution.

Remember F = ma!
--Without a doubt, the most important equation for mechanics--
 

FAQ: A 5.0kg mass is accelerated from rest at the bottom of the 4.0 m long

What is the acceleration of the 5.0kg mass?

The acceleration of the 5.0kg mass can be calculated using the equation a = F/m, where F is the net force acting on the mass and m is the mass itself. In this case, since the mass is accelerating from rest, the initial velocity is 0 and the final velocity can be calculated using the equation v^2 = u^2 + 2as, where u is the initial velocity (0), s is the distance (4.0m), and v is the final velocity. Once the final velocity is known, the acceleration can be calculated using the equation a = (v-u)/t, where t is the time taken for the mass to travel 4.0m.

How long does it take for the 5.0kg mass to travel 4.0m?

The time taken for the mass to travel 4.0m can be calculated using the equation t = √(2s/a), where s is the distance (4.0m) and a is the acceleration. Once the acceleration is known, the time can be calculated and will provide the answer to this question.

What is the net force acting on the 5.0kg mass?

The net force acting on the 5.0kg mass can be calculated using the equation F = ma, where m is the mass (5.0kg) and a is the acceleration. Once the acceleration is known, the net force can be calculated and will provide the answer to this question.

How does the acceleration of the 5.0kg mass change if the mass is increased?

The acceleration of the mass is directly proportional to the net force acting on it and inversely proportional to the mass itself. This means that if the mass is increased, the acceleration will decrease. This relationship can be represented by the equation a = F/m, where a is the acceleration, F is the net force, and m is the mass. Therefore, if the mass is increased, the acceleration will decrease and vice versa.

What is the final velocity of the 5.0kg mass after traveling 4.0m?

The final velocity of the 5.0kg mass can be calculated using the equation v^2 = u^2 + 2as, where u is the initial velocity (0), s is the distance (4.0m), and a is the acceleration. Once the acceleration is known, the final velocity can be calculated and will provide the answer to this question.

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