A 5.0kg mass is accelerated from rest at the bottom of the 4.0 m long

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A 5.0 kg mass is accelerated up a 4.0 m ramp inclined at 30º by a falling 20.0 kg mass over a frictionless pulley, with a coefficient of kinetic friction of 0.26. To solve for the acceleration of the 5.0 kg mass, a free body diagram (FBD) is essential to analyze the forces acting on both masses. The equation ma = mg - Ft is crucial for determining the forces involved. The discussion emphasizes the importance of using FBDs to accurately calculate the acceleration and tension in the rope. Understanding these principles is vital for solving the problem effectively.
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Homework Statement



A 5.0kg mass is accelerated from rest at the bottom of the 4.0 m long ramp by a falling 20.0kg mass suspended over a fictionless pulley. The ramp is inclined 30º ramp from the horizontal, and the coefficient of kinetic friction = .26.
a. Determine the acceleration of the 5.0 kg mass along the ramp.
b. Determine the tension in the rope during the acceleration on the 5.0 kg mass along the ramp.

Homework Equations



ma = mg - Ft for the lower block

The Attempt at a Solution



what do I do with the block on the inclined plane?
 
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Hint: free body diagram.
 
FBD is a necessity...
 
You will have two of them - one for the block on the slope and one for the falling mass.
 
As stated in the previous comments, a FBD is useful. With that you will be able to analyze all the forces acting on the masses and from there find the solution.

Remember F = ma!
--Without a doubt, the most important equation for mechanics--
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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