The force experienced by the test charge is given by Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In this case, the test charge will experience a repulsive force from the fixed charge, since both charges are positive.
The force between the two charges is inversely proportional to the square of the distance between them. This means that as the distance between the charges increases, the force decreases. Conversely, as the distance decreases, the force increases.
The velocity of the test charge will decrease as it approaches the fixed charge due to the repulsive force between the two charges. This decrease in velocity is a result of the work done by the electric field in moving the test charge.
No, the test charge will never come in contact with the fixed charge. This is because the electrostatic force between the two charges will continue to repel the test charge, preventing it from reaching the fixed charge. However, the force may become strong enough to significantly slow down the test charge's motion as it approaches the fixed charge.
The electric field between the two charges can be calculated by dividing the force on the test charge by the magnitude of the test charge. This will give the electric field strength at any given point between the two charges. Alternatively, the electric field can also be calculated using the formula E = kQ/r^2, where k is the Coulomb's constant, Q is the fixed charge, and r is the distance between the two charges.