- #1
nish95
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- Homework Statement
- See the solved example as shown in the image. I don't understand how can we write S(A)=2S(B) since integrating V(A)=2V(B) will give us an extra unknown constant and the work done by friction will depend on it.
- Relevant Equations
- Work-Energy theorem & constraint equations.
See the solved example as shown in the image. I don't understand how can we write S(A)=2S(B) since integrating V(A)=2V(B) will give us an extra unknown constant and the work done by friction will depend on it. I found the relation 2S(B) + S(A) = const. (somebody confirm if this is right?) so isn't it technically wrong to say that S(A)=2S(B)?
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