Angular Momentum: Rotating Object

AI Thread Summary
The discussion focuses on understanding the application of angular momentum in a textbook example, specifically the use of the cosine theta term in torque calculations. Participants clarify that the angle theta refers to the angle between the horizontal and the seesaw, affecting the moment arm calculation. It is explained that the cosine function is essential for determining the moment arm, which can be approached in multiple ways, including using the vector product of force and distance. The clarification helps the original poster grasp the concept better. The conversation emphasizes the importance of understanding angles in torque calculations.
Speedking96
Messages
104
Reaction score
0

Homework Statement



I'm trying to understand an example from my textbook about angular momentum. This is the example given:
upload_2014-12-11_16-18-1.png


For the part in red: I don't understand where the cosine theta term came from. When you're calculating the magnitudes of torques, don't you just use FRsin(theta)? If someone could clear that up for me, it would be great! Thank you.
upload_2014-12-11_16-18-1.png

upload_2014-12-11_16-18-1.png
 
Physics news on Phys.org
Speedking96 said:
I don't understand where the cosine theta term came from. When you're calculating the magnitudes of torques, don't you just use FRsin(theta)?
If the theta is the angle between the force vector and the distance vector, yes. But in the diagram, the angle between the vectors is the angle between the vertical and the seesaw. Theta is the angle between the horizontal and the seesaw.
 
Ok. I think I get it; the cosine is used to get the moment arm in this case, correct?
 
Speedking96 said:
Ok. I think I get it; the cosine is used to get the moment arm in this case, correct?
That's one way to look at it. There are at least 3 ways, leading to the same answer:
- distance cos (theta) = moment arm.
- force cos (theta) = component of force perpendicular to distance
- vector product of force and distance = force * distance * sin(90-theta)
 
  • Like
Likes Speedking96
Ok, I understand. Thank you very much.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top