Average speed of earth in its orbit of sun

Click For Summary
The average speed of Earth in its orbit around the sun is calculated using the formula for circular motion, but there are discrepancies in the expected answer. The initial calculation yielded approximately 29,865.95 m/s, while the correct average speed is stated to be 28,886 m/s. Participants in the discussion noted that the time value used in the calculations might be inaccurate, leading to confusion. One contributor referenced Ramanujan's approximation for elliptical orbits, which resulted in a calculated speed of 29.7838 m/s, suggesting that the textbook answer could be incorrect. Overall, the conversation highlights the importance of accurate data and calculations in determining Earth's orbital speed.
bilbobaggins
Messages
12
Reaction score
0

Homework Statement


The Earth's orbit around the sun is very nearly circular, with an average radius of 1.5x10^11 m. What is the average speed of the Earth in orbit around sun.

Homework Equations



d/t= 2pi/t

The Attempt at a Solution



2pi*1.5x10^11/ 31556926
it comes out to be 29865.95
answer is supposed to be v=28,886 m/s
so can anyone tell me what i did wrong

31556926 is a year so that's why i used it in the equation
 
Last edited:
Physics news on Phys.org
Your t value is a little off. Can you explain how you got it?

Hmm, I get the same answer you do though.
 
Last edited:
hage567 said:
Your t value is a little off. Can you explain how you got it?

Hmm, I get the same answer you do though.

I used google to find t, lol.
 
Try calculating it yourself! I'm inclined to believe the book's answer is wrong.
 
The relevant data are
a=1.00000011 au
e=0.01671022
T=365.242190 days (tropical year)

Using Ramanujan's approximation of the circumference of an ellipse,

C=\pi a \left(3\left(1+\sqrt{1-e^2}\right)-\sqrt{\left(3+\sqrt{1-e^2}\right)\left(1+3\sqrt{1-e^2}\right)}\right)

the Earth's orbital velocity is 0.01720159 au/day, or 29.7838 m/s

From http://nssdc.gsfc.nasa.gov/planetary/factsheet/earthfact.html, the Earth's minimum orbital velocity is 29.29 km/s, larger than the supposedly correct answer. (In other words, the book is wrong.)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K