Calculate Stress & Strain of Marble Column - 1.5m^2, 2.5x10^4kg

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The stress in the marble column is calculated using the formula (25000 kg x 9.8 m/s²) / 1.5 m², resulting in a stress value. However, determining the strain is problematic due to the lack of information on the column's original length or Young's modulus. Strain is defined as the ratio of change in length to the original length or can be calculated using Young's modulus, neither of which are provided. Without these critical parameters, it is impossible to calculate the strain accurately. Therefore, additional data is necessary to solve for strain in this scenario.
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A marble column of cross-sectional area 1.5 m^2 supports a mass of 2.5×10^4 kg.



What is the stress within the column?
What is the strain?

I have already found the stress in the column by taking (25000kgx9.8 m/s^2)/1.5m^2
The problem is i have no clue how to find the strain given this information. I know strain is delta Y/ original length, or strain/youngs modulus.
 
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Without any information regarding its length or Young's modulus, you can't find the strain.
 
This was all that was given to me in the problem...does anyone have any clue.
 

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