Calculate the voltmeter reading for this circuit with 2 sources and 2 resistors

AI Thread Summary
The discussion revolves around calculating the voltmeter reading in a circuit with two sources and two resistors. Initial calculations suggest a reading of 8 V based on a current of 2 A, but a participant argues the correct reading should be 12 V. The calculations involve determining the currents returning to each cell and the total current entering the voltmeter. Ultimately, the consensus leans towards 8 V being the correct reading despite the differing opinions. The thread emphasizes the importance of the original poster doing the majority of the problem-solving work.
songoku
Messages
2,488
Reaction score
393
Homework Statement
Please see below
Relevant Equations
V = I.R
1685171477692.png


I find the current first, which is 2 A. Then the voltmeter reading would be 10 V - 1 x 2 = 8 V.

But the answer is 12 V.
I don't understand why it should be 10 + 1 x 2 = 12 V

Thanks
 
Physics news on Phys.org
I agree with your answer. It obviously cannot be more than 10V.
 
  • Like
Likes songoku and MatinSAR
Thank you very much haruspex
 
Yes, I agree, 8V is correct.
 
Current returning to cell A = x
Current returning to cell B = y
Current entering the voltmeter = z

10- 1*x=0
4- 2*y = 0
z = y + x

X=10
Y=2
Z=12

U=RI

1/R=1/1+1/2
1/R=1,5
R=2/3

U = (2/3)*12 = 8

The reading is 8 Volts.
 
  • Like
Likes Daniel Weng
Welcome to PF, @erpelkon

erpelkon said:
Current returning to cell A = x
Current returning to cell B = y
Current entering the voltmeter = z

10- 1*x=0
4- 2*y = 0
z = y + x

X=10
Y=2
Z=12

U=RI

1/R=1/1+1/2
1/R=1,5
R=2/3

U = (2/3)*12 = 8

The reading is 8 Volts.
It is okay to offer alternate solutions to old schoolwork threads where the OP has already solved the problem. Please just keep in mind that in active threads, the OP must do the bulk of the work. We cannot offer solutions to them until after they have solved their schoolwork problem. Thanks. :smile:
 
  • Like
Likes MatinSAR and erpelkon
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top