Calculate Work Done by 12.6V Battery Supplying 2.0A for 10min

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To calculate the work done by a 12.6V battery supplying a 2.0A current for 10 minutes, the relevant equation is work (W) equals voltage (V) multiplied by charge (Q). The charge can be calculated using the formula Q = I * t, where I is the current and t is the time in seconds. In this case, the current is 2.0A and the time is 600 seconds (10 minutes). Thus, the total charge is 1200 coulombs, and the work done by the battery is W = 12.6V * 1200C, resulting in 15,120 joules. This calculation illustrates the relationship between voltage, current, and work done in electrical systems.
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Homework Statement



A 12.6 V battery supplies a 2.0 A current for 10 minutes. What is the work done by the battery during this process?

Homework Equations



I=q/t

The Attempt at a Solution



I'm really drawing a blank on how this connects to work.
 
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The work would be the same as the electrical energy the battery outputs.

What does the product of voltage and time give?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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