Calculating Electric Field & Force: Q1 & Q2

AI Thread Summary
To find the position where the net electric field from charges Q1 and Q2 equals zero, one must consider the distances from each charge and their magnitudes. The negative charge Q1 (4.2 µC) and positive charge Q2 (1.4 µC) create opposing electric fields, and the balance point will be located closer to Q2 due to its smaller magnitude. For the second part, once the position is determined, the force on a +5.0 µC charge can be calculated using Coulomb's law, considering the electric fields from both Q1 and Q2 at that point. The calculations must be shown for clarity and to receive further assistance. Understanding the principles of electric fields and forces is crucial for solving these problems accurately.
laxwarrior
Messages
3
Reaction score
0
Electric Field Help Please!

Two charges are separated by 1.0 m. Q1 has a negative charge of 4.2 µC and Q2 has a positive charge of 1.4 µC. At what position is the net electric field that is produced by both Q1 and Q2 equal to zero?

2nd part: If a +5.0 µC charge is placed at this position, what force would act on it as a result of Q1 and Q2?
 
Physics news on Phys.org


You need to show your attempt at this question before you can get any help.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top