Calculating Magnetic Field Between Coaxial Circular Coils

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To calculate the magnetic field halfway between two coaxial circular coils, each carrying 4.0 A, the total magnetic field must account for contributions from both coils. The initial calculation only considered the field from one coil at a distance of 20 cm, which is incorrect. The correct approach requires summing the magnetic fields from both coils at the midpoint, taking into account their vector directions. The formula used needs adjustment to reflect the contributions from both coils. Properly applying these principles will yield the correct magnetic field value.
Curious314
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Homework Statement


Two coaxial circular coils of radius R = 15 cm, each carrying 4.0 A in the same direction, are positioned a distance d = 20 cm apart, as shown in the figure. Calculate the magnitude of the magnetic field halfway between the coils along the line connecting their centers. (μ0 = 4π × 10-7 T ∙ m/A)
pregunta 7 dibujo.jpg


Homework Equations



eciacion pregunta 7.jpg


The Attempt at a Solution



so:

B= [(4*∏*10-7)(4.0)(0.152)]/[2*(0.152+0.22))3/2]

which is = 3.62 x 10-6

not near any of the options.
Is this a very wrong approach?

Thanks!
 
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Hi! :smile:

You are only considering the field due to one of the coil at a distance 20cm from its center. But you are asked the total magnetic field due to both, halfway from their centers! So fields from each of the loop will add. Remember to check the field direction due to each before adding, as it is a vector.
 
Thank you!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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