Calculating Sag & Tension for 2 Wires: 5000 lbs Horizontal Tension

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To calculate the sag of two wires with different weights hanging between two supports, the initial wire's weight must be considered alongside the new heavier wire. The sag can still be approximated using the parabolic equation Sag = (W*L^2)/(8*T), where W is the total weight of both wires. The average weight per foot should be used to determine the new effective weight for the combined system. It's important to maintain the same horizontal tension of 5000 lbs while calculating the new sag. This approach allows for a more accurate representation of the combined system's behavior.
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I'm trying to figure out the sag of a wire hanging between two objects. If I string a wire between two structures and tension the wire 5000 lbs in the horizontal direction, I can estimate the shape of the wire to be parabolic and use the equation: Sag = (W*L^2)/(8*T), where W=Weight of wire, L=Span between two supports, and T=Horizontal Tension to calculate the sag. If now I add a much heavier wire to the first wire, how can I arrive at the new Sag and Tension for the two wire combination? I am assuming the same temperature for both installations (60 degrees F). The first wire is .65 lbs/ft; the second wire is 7.8 lbs/ft. I am trying to solve the problem without neglecting the initial wire's weight.
 

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Have a look at this

http://mathworld.wolfram.com/Catenary.html

If two different wires hang in the same curve they must be joined along their length, so you can pretend it's one wire with the average density (?)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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