Calculating Work Required to Accelerate an Electron

  • Thread starter Thread starter AnnieD
  • Start date Start date
  • Tags Tags
    Electron Work
Click For Summary
The discussion centers on calculating the work required to accelerate an electron from rest to a speed of 1.6 x 10^8 m/s. Participants initially struggle with the lack of distance and time information needed for traditional calculations using force and work equations. They highlight the importance of using kinetic energy changes to find the work done, but several calculations yield different results, suggesting a possible error in the textbook answer. The conversation shifts to the necessity of considering relativistic effects, leading to the conclusion that the correct answer should be around 2.7 x 10^-18 J, as confirmed by multiple participants. Ultimately, the group agrees that the textbook may contain an error regarding the expected result.
AnnieD
Messages
24
Reaction score
0

Homework Statement



How much work is required to accelerate an electron from rest to 1.6 x 10 ^8m/s. (m= 9.1 x 10 ^ -31kg)?

The answer should be: 2.7 x 10 ^ -18


Homework Equations


a = Fnet/m
W = F x d
W = E


The Attempt at a Solution


I can't see a way to figure this problem out. It seems I need the distance, but I can't figure it out because I don't have a time to use to figure that out, or the acceleration rate. I tried rearranging a = Fnet/m .. but was again then stuck with the distance/time problem. Am I missing something?
 
Physics news on Phys.org
The total work done on an object is defined as the objects change in kinetic energy:

W_{TOT} = \Delta K

where \Delta K = 0.5mv^2_f - 0.5mv^2_0

All you have to figure out now is the electrons inital and final kinetic energies. Does that help?
 
You don't know the acceleration (for you are not given how long it takes to accelerate the electron to this speed - if it takes 1 second a=1.6 x 10^8 m/s^2 or if it takes 2 seconds a=0.8*10^8 m/s^2), and you don't know the distance so
W=F d and F = m a are not going to be too helpful.
Look more closely at your 3rd equation - what energy did the electron initially have? What energy does it have finally?
(Warning: This method should work but I got a different result to the one stated - though I am assuming it is in SI units)
 
Yes, forgot to mention that I also tried the W = delta E equation.
So E = Ek2 - Ek1
but the answer I ended up getting wasn't the right one.
I ended up with a final answer of 1.1648 x 10 ^ - 14
 
You may have copied the question wrongly... or the answer is wrong. I calculated and got 1.16 \times 10^{-14} J as well.
 
Last edited:
kudoushinichi88 said:
You may have copied the question wrongly... or the answer is wrong. I calculated and got 1.16 \times 10^{14} ms^{-1} as well.

I believe that should be 10^{-14} and in units of Joules.

It would be a good idea to double check your values, as kudoushinichi suggested. Text book authors have been know to make errors.
 
Oops... typed without thinking much... Sorry...
 
When the electron is moving with the velocity = 1.6*10^8 m/s we have to consider the relativistic mass and energy.
 
Oh I totally forgot about relativity... since I haven't really studied that in a formal class...

So we use the equation

E_k = (\gamma - 1)mc^2

right?

But then I plugged in the values and yielded 1.49 \times 10^{-14} J instead...
 
Last edited:
  • #10
Thanks everyone for your help! We've come to the conclusion (my physics teacher) that the book is wrong. The correct answer is the one others as well as myself mentioned earlier as the value. I don't know anything about relativity- it's only a gr.12 class, but thank you for trying nonetheless! Much appreciated. :)
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
879
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
5
Views
1K
  • · Replies 5 ·
Replies
5
Views
9K
Replies
10
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
9K
  • · Replies 7 ·
Replies
7
Views
11K