Can I Use a Lead Acid Charging Circuit After a Boost Converter for Solar Panels?

AI Thread Summary
Using a lead acid charging circuit after a boost converter for solar panels is feasible, but the output voltage must be adjusted to around 13.8V for effective charging. The discussion highlights that while the boost converter doubles the input voltage, it may be more efficient to connect solar panels in series to achieve the required voltage directly. Concerns are raised about the low current output in capacitor-based circuits compared to conventional inductor-based DC-DC converters, which typically provide higher current. The need for a switching buck converter is emphasized to maintain the necessary voltage for charging. Overall, optimizing the configuration of solar panels and the type of converter used is crucial for effective battery charging.
Hina Gohar
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I am working on simulation and calculation of solar charge controller for lead acid battery..I simulated two solar panel in parallel along with switched capacitor dc-dc boost converter which is basically voltage doubler and it is working properly but now I need 12V on output of this boost converter to fed battery and dc load of 40W total..this boost converter every time provide double of input voltage while I need 12V constant for lead acid 12V and 100AH battery.One lead acid charging circuit is given in Boylestad Electronic Devices book my question is that can I use this circuit after my boost converter instead of load resistance..
 

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Why do you voltage double parallel panels when you can simply use the panels in series?

To charge a 12V battery you will need closer to 13.8V with a negative temperature coefficient.

That 13.8V could be produced with a switching buck converter from two panels in series.
 
Baluncore said:
Why do you voltage double parallel panels when you can simply use the panels in series?

To charge a 12V battery you will need closer to 13.8V with a negative temperature coefficient.

That 13.8V could be produced with a switching buck converter from two panels in series.

In this circuit I have seen current is very low.What's the reason that in capacitor based circuit current is low while in conventional DC-DC converter current is high in which inductor used as main energy storage element.
 
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