- #36
Gonzolo
omin said:...constant force is exerted upon the clocks and therefore is an expression of energy.
This not how energy is defined in standard physics. When a rock is set on the ground, gravity exerts a force on the rock, the rock exerts a force on the earth, yet no energy is converted, because W = fd = f(0) = 0. For energy to be used, the rock has to move in the direction of the force. If you open a trap door under the rock, then there is energy conversion, because d will not be zero, the rock will move along the force (it will gain kinetic energy).
Imagine a spinning dumbell in space. Where is energy used? There are millions of forces between its atoms, yet it doesn't use energy at all. I don't see what you mean by "expression of energy". Any energy that is used to keep the clock in the air is to compensate for losses due to gravity (up and down oscillations, which we should ignore) and a bit for friction. In space, no energy would be needed to keep it going.
omin said:The speed (motion) is implied to be internal in the first clock, because the force upon the first clock must supply constant supply force for the second clock.
I don't see what you mean by "internal speed".
omin said:When I think of static force, it means the movement is not as apparent to my vision and I have to use deduction to find it, where kinetic force means I notice it visually and is axiomatic. I don't see the first clock moving as much as I see the first clock. I know the first clock isn't loosing it mass where force occurs, so it looses velocity outwardly to the second clock. This velocity travels to the string and then to the second clock. It is a wave of energy. I know this much.
Static forces means the forces are in equilibrium. Whereas Dynamic forces means their is movement along forces. You might call our system kinematic I suppose (not dynamic though), but in static and kinematic cases, there is no tranfer of energy. When something is already spinning (kinematic), centripetal force balances centrifugal force, but no force is along the motion.
omin said:What I don't know is if the wave of energy is building up toward the outside or if it's perfectly distributed.
There is no build up of energy, most was given in the beginning, whatever you add is to compensate for losses due to gravity (this should be ignored). There is more towards the outside though. A simpler system (without losses) is a spinning dumbell in space. You do not have to constanly supply energy to compensate losses in this case.
(mass)----(clock 1 = pivot)----(clock 2)
omin said:When a constant supply of energy is supplied to this circumstance, and we isolated all outside forces upon this system (for now), we may see this in a linear way, because all things will settle as constant. So we may apply the what you are calling linear logic to it.
If you do wish to supply constant energy (over what is need to compensate up and down oscillations), then it will be spinning faster and faster and faster and faster and this complicates things besides the point.
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