Collision question involving velocity, Kinetic energy and conservation

In summary, a 50 gram steel ball moving at 2.0m.s^-1 on a frictionless horizontal surface collides with a stationary 20 gram ceramic ball, causing the ceramic ball to move off at a velocity of 2.5m.s^-1. After solving for the steel ball's velocity after the collision using the equation for conservation of momentum, it was determined to be 1m.s^-1. The kinetic energy of the balls before the collision was calculated to be 100 joules, and after the collision, it was 62.5 joules. Therefore, the kinetic energy was not conserved, and some energy was lost in the collision.
  • #1
selsunblue
4
0

Homework Statement


A 50 gram steel ball moving on a frictionless horizontal surface at 2.0m.s^-1 hits a stationary 20 gram ceramic ball. After the collision the ceramic ball moves off at a velocity of 2.5m.s^-1.
(i) Calculate the velocity of the steel ball after the collision.
(ii) Calculate the total kinetic energy of the balls before the collision and again after the collision.
(iii) From your results in part (ii) has the kinetic energy been conserved? If not, where has this energy gone?

Homework Equations



initial momentum = final momentum

The Attempt at a Solution


For the first sub-question I got initial momentum=50*2=100 and final momentum i got 50v+2.5(20)
equating these I got 100=50v+50 => v=1ms^-1

Would the 20 be correct in that calculation of final momentum?

initial KE = ½ * 50 * 2^2 = 100
Final KE = ½ * 50 * v^2 + ½ * m * 2.5^2
 
Last edited:
Physics news on Phys.org
  • #2
Where does "20" come from? It was not specified in the statement of the problem.
 
  • #3
voko said:
Where does "20" come from? It was not specified in the statement of the problem.

Oh It's the mass of the stationary ceramic ball, sorry about that, forgot to write it in I guess. Would it be 50 or 20 in this case?
 
  • #4
Then your solution for the steel's ball velocity after the collision is correct.
 
  • #5
Yes but it should be remembered that the units are not in standard units (joules) since you didn't make the conversion from grams to kilograms. The answers would have to be divided by 1000 to be in joules (it's a good habit to pay attention to units).
 
  • Like
Likes 1 person

FAQ: Collision question involving velocity, Kinetic energy and conservation

What is the difference between velocity and kinetic energy in a collision?

Velocity is a measure of an object's speed and direction, while kinetic energy is a measure of the object's energy of motion. In a collision, the velocity of the objects involved may change, while the total kinetic energy remains constant.

How does the conservation of momentum affect collisions?

The law of conservation of momentum states that the total momentum of a closed system remains constant. In a collision, the total momentum of the objects before and after the collision must be equal, regardless of any changes in velocity or kinetic energy.

What factors can influence the outcome of a collision?

The outcome of a collision can be influenced by the masses and velocities of the objects involved, as well as the angle and type of collision (elastic or inelastic). Other factors such as external forces or friction can also play a role.

How does kinetic energy relate to the force of impact in a collision?

Kinetic energy is directly proportional to the square of an object's velocity. Therefore, the greater the kinetic energy of an object, the greater the force of impact it can exert in a collision.

Can kinetic energy be converted into other forms of energy during a collision?

Yes, kinetic energy can be converted into other forms of energy during a collision, such as sound or heat. This is due to the principle of conservation of energy, which states that energy cannot be created or destroyed, but can only be transferred or transformed from one form to another.

Back
Top