Colombo's Law Gizmo - Force & Distance Equation

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The discussion focuses on deriving the equation that relates force (F) to distance (d) for two charged objects, with a determined constant value of 8500 N/m². The proposed equation is F = 8500/r², indicating a relationship where force is inversely proportional to the square of the distance between the charges. A graph of F versus 1/d² yielded a linear relationship, confirming that the slope corresponds to the constant value. The units of the constant were debated, clarifying that the slope should match the theoretical Coulomb's constant. The final equation reflects the proportional relationship between force and the inverse square of distance.
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Homework Statement


Write the equation that you determined from your results that shows the relationship between F and d for two charged objects.

Homework Equations

The Attempt at a Solution


I have determined a constant value that relates force to separation distance. The value is 8500 N/m^2
I'm assuming the equation is (8500 N/m^2)/r^2, where the 8500 N/m^2 is equal to the two charges and coloumb's constant multiplied together. and r is the distance between the two charges.
 
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Did you draw a F versus 1/d2 graph with your data?
 
First I drew F vs. 1/d graph which gave me a hyperbola and then my F vs. 1/d^2 graph gave me a linear line and i have calculated the slope of that linear line to be 8500 which has some percent error.
 
Yes, that shows that the relationship between F and 1/d2 is
linear or that there is a directly proportional relationship if the y-intercept
is close to zero Newton. The gradient is then the proportional constant,
which you determined as 8500. Have a careful look at its unit though.
The empirical equation (supply the units of your constant in the brackets)
is then
F = 8500 ( ) 1/d2 or r2
 
For it's units i get N/m^2 but when i actually multiply coulomb's constant and both q's together i get units of Nm^2 my slope should have the same units as the actual theoretical k.
 
The units of the independent variable is per meter square. So the units of the gradient will be N/m-2 which comes to Nm2
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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