Completely Inelastic Collision

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In a completely inelastic collision, two objects of equal mass and initial speed move together at 1/3 of their initial speed after the collision. The problem involves analyzing the collision in two dimensions, which complicates the calculations. The final combined mass moves at a reduced speed, but the angle between the initial velocities needs to be determined. Despite attempts to solve for the angle, an initial calculation of 45 degrees was found to be incorrect. Further assistance is sought to clarify the correct approach and solution for finding the angle.
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After a completely inelastic collision, two objects of the same mass and same initial speed are found to move away together at 1/3 their initial speed. Find the angle between the initial velocities of the objects.

I think that this question is dealing with collisions in two dimensions. My textbook does not give any equations for completely inealstic collisions in two dimensions. Any help?
 
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It just means they stick together, so you have a final particle of 2*mass
 
I went through and ended up getting an answer of 45 degrees. But that ended up being wrong.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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