MHB Convert £0.91 to UK Decimal Currency - Help Needed

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To convert £0.91 into the old UK currency system, it equates to 18 shillings and 2.4 pence. The calculation involves understanding that there were 240 old pence in a pound, leading to the conversion of 91 new pence to old pence. The discussion also touches on the simplification of currency systems, referencing practices in Canada and Europe. The conversation highlights the complexities of pre-decimal currency while suggesting modern alternatives. Ultimately, the conversion illustrates the historical differences in currency representation.
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Sir,
Would anyone be able to help me with converting the UK decimal currency amount of £0.91 to £ s d
Thank you in advance,
Regards,
P.N.
 
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In the pre-decimal currency of the UK, there were 12 old pence in one shilling and 20 shillings in one pound; thus there were 240 old pence in a pound. (Note that the symbol for the old (pre-decimal) penny is d whereas p is the symbol for the new (decimal) penny.)

If $x$ is the amount of old pence corresponding to 91 new pence, then
$$\frac x{240}\ =\ \frac{91}{100}$$
giving $x=0.91\times240=218.4$.

$218.4\ =\ 18\times20+2.4.$

Hence $£0.91\ \text{(decimal)}\ =\ £\mathrm{0\,\,18\,s\,\,2.4\,d}\ \text{(pre-decimal)}$.
 
EASIER if you do what we did here in Canada:
eliminate the **** penny!
 
Wilmer said:
EASIER if you do what we did here in Canada:
eliminate the **** penny!

Don't you have the problem that you don't know how many dollars there are in a dollar?
Easier if you do what we did here in Europe: only one Euro. :p
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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