Creating a Target with 3 Photons in SR Propagating Sphere of Light

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In summary, the conversation discusses the propagation of a sphere of light created by a pinhead size event and how its symmetry is independent of the frame that created it. It also explores the idea of using three photons on the sphere to create a target and the behavior of the target during propagation of the photons. The conversation also touches on the concept of time dilation and length contraction in relation to the propagation of the sphere. The disagreement between the observers in the target frame and the moving frame regarding the symmetrical nature of the photon sphere is also mentioned.
  • #71
Hi DaleSpam
DaleSpam said:
It isn't a question of convenience, it is a question of knowledge. How do you know if a given target is stationary or moving. If there are two distant targets which are moving wrt each other how do you know which one (if any) to pick?
The Earth is used as far as I know as a stationary example so at .8c using it as a target it would be classed as background moving with respect to the aim point. If it was a frame of how I explain absolute rest then that would be background moving whilst sighting down the tube. I believe we are near a yes it is, no it isn't scenario but perhaps I can do better with another example.


Not unless you can think of some way of experimentally identifying a target which is at rest in the absolute rest frame. Unless you can do that you are merely talking of the target's rest frame, which is no more privileged than any other frame.

Well that is an interesting thought but it is also worth considering that over recent histry re Einstein, there were a series of experiments after his claims which proved him correct.
Perhaps the first step is to prove experimentally that it does not exist. I would be interested in steps in that direction but physics in all frames being the same (virtualy) ie Michelson
Morley?(spelling) With later experiments-- isn't there a minor consistent confirmation of variation. Sagnac perhaps is trying to tell us something- How close to a zero time photon emission are we-- Particle colider impact emissions. Interference paterns.

How about another example.
You are at .999c and you create a sphere of photons and your right angle tube is about 10ft long. As your tube photon exits you create another event at the start of the tube.
Now I understand you to point to the start of the tube when I ask you where did the photon start from. If that is so I would ask you to step outside ond view the complete picture.
We see the first event sphere having expanded in perfect symetry and we locate the center of the sphere,( where all the photon reciprocals cross.) Now we look at your second event or marker event where you tell me the first event started from. The second sphere is is not centered on the first. The tube start point is now way out close to the edge of the sphere at .999c.
If you are talking about a beam of light, that would be another story.
All photons on the sphere are either there or not. They have the ability to prove their existence by an exchange of energy. They have all traveled the same distance--- irrespective of the frame they have left. They all have their own heading--direction. They cannot be in two places at the same time. They cannot have scribed two headings in our view of the sphere. Dont you agree that on absolutely any frame speed and direction of a frame passing through the center of a sphere and creating an event at the center of the sphere, that every subsequent sphere is centered on the first because it is zero time generated.
Now what would you call the inertial marker point of the expanding spheres. I would call it absolute rest. There is absolutely no time dilation at that point. Absolute time would work for me.
All photons within all the spheres move at c from their respective events so consider the geometry which keeps the tube photon in a state of constant intersection at less than c which can only be measured at c by the frames clock which is absolutely speed variable and has no option but to measure c in its frame.
I still don't see any laws I have broken to date.
Il try to post the geometry.
 
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  • #72
Hi Dalespam
I hope this works

The hypotenuse photon has moved the same distance as any other photon in the sphere in both examples. The table intersection speed is less than c and so its clock must be dilated to always make that speed c. A slow photon must always be measured by a the slow clock at c. Invarience is fine for me.
All photons move at c but not the intersection speed
[PLAIN]http://http://i1190.photobucket.com/albums/z460/Tapapakanga/photon2.jpg
[PLAIN]http://http://i1190.photobucket.com/albums/z460/Tapapakanga/Photon.jpg
Drawn absolutely to scale and time dilation measured with a ruler to show it is so. Pythagarus is more precise of course.
 
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  • #73
Reff said:
The Earth is used as far as I know as a stationary example so at .8c using it as a target it would be classed as background moving with respect to the aim point. If it was a frame of how I explain absolute rest then that would be background moving whilst sighting down the tube.
Sorry, your wording is confusing. Are you saying that you are picking the Earth as your stationary target? If so then you are merely measuring speed relative to the earth. The idea of the Earth being an absolute rest frame has been dismissed since the days of Copernicus.

Reff said:
perhaps I can do better with another example.
There is no reason to go to another example when you have not addressed this key problem of how to determine if a target is stationary in the absolute rest frame.
 
  • #74
Reff said:
The hypotenuse photon has moved the same distance as any other photon in the sphere in both examples. The table intersection speed is less than c and so its clock must be dilated to always make that speed c. A slow photon must always be measured by a the slow clock at c. Invarience is fine for me.
All photons move at c but not the intersection speed
photon2.jpg

Photon.jpg

Drawn absolutely to scale and time dilation measured with a ruler to show it is so. Pythagarus is more precise of course.
Thanks for the drawing. This is exactly the geometry I had understood, so we can be sure that there is no misunderstanding of the geometry now.

So my previous objections all hold.
1) a sphere of photons centered on the origin in one frame is a sphere of photons centered on the origin for all frames.
2) the heading of each individual depends on the frame chosen, so the photon going down the moving right-angle tube is a 90º photon in the moving frame.
3) determining if a photon hits a distant target and drawing a line back from that distant target only determines your speed relative to that target.
4) there is no experimental way to determine if your target is stationary in the absolute rest frame.
 
  • #75
Firstly, I think you may have corrected a mistake re the posting of my geometry DaleSpam.
If so , thank you.

DaleSpam said:
Sorry, your wording is confusing. Are you saying that you are picking the Earth as your stationary target? If so then you are merely measuring speed relative to the earth. The idea of the Earth being an absolute rest frame has been dismissed since the days of Copernicus.
No I am not but I am using the Earth as the best of a set of bad examples re an unchallenged quote from Drakkith post 28
There is no absolute frame that we can say is at rest. To keep things simple we usually refer to the frame of the Earth as being at rest, but it is not.

There is no reason to go to another example when you have not addressed this key problem of how to determine if a target is stationary in the absolute rest frame
.

That is a little unfair ---But---no problem.
As I have said before. I observe the center of a zero time event and many other frames that pass through it also creating an event concentricaly to the first sphere. They all expand concentricaly to the first irrespective of the speed or direction of their frames, because they are all zero time events. This is the geometry I am interested in. This is the point of absolute rest. I now fabricate a frame of tubes as many as you wish- all pointing radialy away from the center of the frame. I place this frame over the events concentric center. It will be inertialialy located at that point. Observing the departing photons I see at least one in each tube move into the distance-- they will all remain in sight of their tubes. Now consider the background view. is it moving relative to the path of the photon- then it is moving relative to the absolute rest frame. If the background is not moving we could have one of three scenarios, One- it is moving towards us. Two it is moving away from us or three it is also at absolute rest. Time would resolve the first two eventualy. Do the same exercise with two initial events ten miles apart just for an example. A whole set of concentric expanding spheres at one end and a whole set of concentric spheres ten miles away. Mark each concentric point. The marks will stay 10 miles apart. They will never meet, because they are at absolute rest. Absolutely any frame able to cross the gap between the two, will be time dilated. At rest clocks must run faster than any other able to move to it. The key in all this, is to remain at the origin point of every single photon in all the spheres. All their photon headings return to that point.
In either of these two frames you can ask me where did all the photons originate from and to prove it, a fresh definitive event would also be proven to expand concentricaly with whichever example you chose.
I suppose it is fair you address this
There is no reason to go to another example when you have not addressed this key problem of how to determine if a target is stationary in the absolute rest frame.

What I am saying here is you have not addressed this key problem of how to determine the origin of the right angle photon in a moving frame. addressed by my next example. Are you really saying that a second event, created to determine the point of origin will be concentricly located on the first event. I believe a rabbit and a hat would be useful here.

You are at .999c and you create a sphere of photons and your right angle tube is about 10ft long. As your tube photon exits you create another event at the start of the tube.
Now I understand you to point to the start of the tube when I ask you where did the photon start from. If that is so I would ask you to step outside ond view the complete picture.
We see the first event sphere having expanded in perfect symetry and we locate the center of the sphere,( where all the photon reciprocals cross.) Now we look at your second event or marker event where you tell me the first event started from. The second sphere is is not centered on the first. The tube start point is now way out close to the edge of the sphere at .999c.
If you are talking about a beam of light, that would be another story, but we are not.
All photons on the sphere are either there or not. They have the ability to prove their existence by an exchange of energy. They have all traveled the same distance--- irrespective of the frame they have left. They all have their own heading--direction. They cannot be in two places at the same time. They cannot have scribed two headings in our view of the sphere. Dont you agree that on absolutely any frame speed and direction of a frame passing through the center of a sphere and creating an event at the center of the sphere, that every subsequent sphere is centered on the first because it is zero time generated.
Now what would you call the inertial marker point of the expanding spheres. I would call it absolute rest. There is absolutely no time dilation at that point. Absolute time and rest would work for me.
All photons within all the spheres move at c from their respective events so consider the geometry which keeps the tube photon in a state of constant "intersection" at less than c which can only be measured at c by the frames clock which is absolutely speed regulated and has no option but to measure c in its frame.
I still don't see any laws I have broken to date.
 
  • #76
Reff said:
No I am not but I am using the Earth as the best of a set of bad examples re an unchallenged quote from Drakkith post 28
So the question remains. How do you experimentally determine if your target is at absolute rest. If you cannot do that then you are merely measuring velocity relative to the target.

Reff said:
I observe the center of a zero time event and many other frames that pass through it also creating an event concentricaly to the first sphere. They all expand concentricaly to the first irrespective of the speed or direction of their frames, because they are all zero time events. This is the geometry I am interested in. This is the point of absolute rest.
See post 7 where I proved that this geometry is the same in every frame, so by this geometry every frame is absolute rest.
 
  • #77
H DaleSpam
DaleSpam said:
So the question remains. How do you experimentally determine if your target is at absolute rest. If you cannot do that then you are merely measuring velocity relative to the target.

See post 7 where I proved that this geometry is the same in every frame, so by this geometry every frame is absolute rest.

I believe we do have a major difference here and that is at rest being concentricaly located to a sphere of photons from a zero time event .When you say every frame is absolute rest you have changed the frame dependence to suit. Let me explain a little more.

I believe we have established that a sphere of photons from a zero time event is---Not frame dependent---
Now when I ask you where the right angle photon originated from in a moving frame, you then make it---- frame dependent---.

I believe you cannot have it both ways to suit.

If the r angle photon in a moving frame is --- not frame dependent--- Then it must have originated from the center of the sphere like all the others from the same event, which makes the right angle photon in conflict with the right angle in that it is in a state of constant intersection with that right angle and therefore that moving intersection is -- not moving at c-- but like all the the photons in the sphere, it is moving at c from its non frame dependent event.

Staying concentricaly located with the event, there is no intersecting trajectory photon therefore we have absolutely --no-- time dilation for that frame. It is absolute rest.

I still invite you to indicate where the r angle photon started from in a .999c frame by using a marker event when we know the photon sphere is not frame dependent. It is only a beam or pulse of light which is frame dependent.
I believe a previous post described present belief as "wierd but that's how it is" A rabbit and a hat sounds more like it.
 
  • #78
Reff said:
I believe we have established that a sphere of photons from a zero time event is---Not frame dependent---
It depends what you mean by this sentence. All frames agree that a sphere of photons centered on the origin in one frame is a sphere of photons centered on the origin in all frames. So that fact is not frame dependent.

However the spatial location of the origin at any [itex]t' \ne t \ne 0[/itex] is frame dependent. So, all frames agree that the sphere of photons centered on the origin is a sphere centered on the origin, but they disagree where the origin is except at [itex]t'=t=0[/itex], the zero-time event of the emission of the photons.

Reff said:
Now when I ask you where the right angle photon originated from in a moving frame, you then make it---- frame dependent---.

I believe you cannot have it both ways to suit.
Pay attention to what I actually said. I said that the direction something travels is frame dependent. The direction that something travels and the point that it travels from are two entirely different questions and may have two entirely different answers without changing the rules (the Lorentz transform).

Your complaint is like saying "you said 2+2=4 and now when I ask about 2+3 you say it is 5, you cannot change the rules to suit". Because you do not understand the math you see the answers as contradictory, when in fact they both follow directly from the math using the same set of rules.

Reff said:
I still invite you to indicate where the r angle photon started from in a .999c frame
And I still invite you to explain how to experimentally determine if the target is at absolute rest. You are clearly avoiding the question, so I think you realize now that there is no possible answer. There is no way to experimentally determine if the target is at absolute rest, so all you can do is measure your velocity relative to the target.

I am perfectly willing to address your question later, but, as I have already stated, I am not inclined to proceed on to the minor details of any other examples until we have resolved this central issue of the current example. Do you now agree that there is no way to experimentally determine if the target is at absolute rest?
 
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  • #79
DaleSpam said:
It depends what you mean by this sentence. All frames agree that a sphere of photons centered on the origin in one frame is a sphere of photons centered on the origin in all frames. So that fact is not frame dependent.
Perhaps a thought concerning the only constant in the universe being c and if we locate ourselves at the beginning of the creation of a sphere and study that constant and indeed stay concentricaly centered to the sphere. When I say not frame dependent I mean it does not matter what speed and direction the frame was moving when the sphere was created. I have stayed concentricaly centered on the propagation from its very beginning. all subsequent events concentricaly centered on that point are not frame dependent, who cares where the frames are in relationship to the spheres that are created from these moving frames. the spheres are not frame dependent.
I ask each frame observer if they measure c-- yes, I ask are there photons in your tubes, they say yes and I ask where did they start from---- and prove it by creating an event at your start point the moment your right angle tube has a photon exiting. As each observer creates that event on his frame to say " this is where the photons originated" I say no you have missed to almost every observer and point out that almost every marker event has missed the absolute or constant sphere. Each moving observer is saying the sphere propagation is dependent on where the event happened on his frame, so I am saying almost all the observers are using their frame to Drag the perfect symetry of a photon sphere around with them. Perhaps Copernicus would say "you have done it again." Observers are incorrectly saying they are the center of a the perfection of a sphere created by a constant. They are saying the sphere is frame dependent. I have mentioned "almost all" because there was one frame which stayed central to all the spheres at that point I call absolute rest. When a photon exited absolutely any tube on his frame and he complied by creating an event at the start of the tube, then this new event and any number of events at that same point on the frame, will expand concentricaly to all the others.

Pay attention to what I actually said
.
We both seem to suffer from that eh!

And I still invite you to explain how to experimentally determine if the target is at absolute rest. You are clearly avoiding the question, so I think you realize now that there is no possible answer. There is no way to experimentally determine if the target is at absolute rest, so all you can do is measure your velocity relative to the target I am perfectly willing to address your question later, but, as I have already stated, I am not inclined to proceed on to the minor details of any other examples until we have resolved this central issue of the current example. Do you now agree that there is no way to experimentally determine if the target is at absolute rest?
no!
Conversly-- Do you say that there is no way to experimentally determine that absolute rest noes not exist.

Ok let's have a go. I will say now though that it is unfair to ask me to design an experiment to determine absolute rest when during the course of history plenty has been said which was much later verified by experiments (including michelson Morley now trying to tell us something)
But let's begin with a frame and observer remaining centered on an expanding sphere of photons from a zero time event. He is thus inertial. Let us take six frames observers and clocks. They are going to do a fly past at .9c .( any substantial common figure will do.) Each frame is moving at 90 degrees to the others-- ie all directions relative to the sphere located frame. As they pass they synchronise clocks with the sphere clock as an instantaneous exchange of information and proceed for a distance from the spheres frame. Let's use a distance of a long piece of string, say 300 000km. As each frame reaches the end of the piece of string, it exhanges instant clock information with messenger frames which return to the sphere located frame. If I am right then the period of time elapsed in each non concentric frame will be the same and it will be. If you are correct and there is variation I will purchase a rabbit.
I can perhaps do better than that with more than ten minutes to think about it.
 
  • #80
Reff said:
I have stayed concentricaly centered on the propagation from its very beginning.
So have the observers at rest in every other frame.

Reff said:
As each observer creates that event on his frame to say " this is where the photons originated" I say no you have missed to almost every observer and point out that almost every marker event has missed the absolute or constant sphere.
And how do you determine which sphere is the absolute or constant sphere? Each observer in each frame has the same result from the same experiment. What experimentally distinguishes the absolute or constant sphere from every other sphere?

Reff said:
But let's begin with a frame and observer remaining centered on an expanding sphere of photons from a zero time event. He is thus inertial. Let us take six frames observers and clocks. They are going to do a fly past at .9c .( any substantial common figure will do.) Each frame is moving at 90 degrees to the others-- ie all directions relative to the sphere located frame. As they pass they synchronise clocks with the sphere clock as an instantaneous exchange of information and proceed for a distance from the spheres frame. Let's use a distance of a long piece of string, say 300 000km. As each frame reaches the end of the piece of string, it exhanges instant clock information with messenger frames which return to the sphere located frame. If I am right then the period of time elapsed in each non concentric frame will be the same and it will be.
If you perform this same experiment in any frame you will get the same result. This experiment does not distinguish one frame from another. You still have not described a way to experimentally determine if your target is at absolute rest.
 
  • #81
Look Reff, the laws of physics are invariant under the Lorentz transform, and the Lorentz transform is derived from the principle of relativity. So it is simply not possible to make an experiment which will detect an absolute rest frame using the known laws of physics.

I believe that your problem is that you are unfamiliar with the Lorentz transform. You have not actually worked enough physics "homework" style problems involving the Lorentz transform. Because of that you don't have a good understanding about how physics will work in other frames besides the one that you draw.

You are chasing after ghosts. The laws of physics don't do what you want them to do. All that you have left is to hope that future discoveries will lead to new laws of physics that are not Lorentz symmetric.
 
  • #82
DaleSpam said:
Look Reff, the laws of physics are invariant under the Lorentz transform, and the Lorentz transform is derived from the principle of relativity. So it is simply not possible to make an experiment which will detect an absolute rest frame using the known laws of physics.

I believe that your problem is that you are unfamiliar with the Lorentz transform. You have not actually worked enough physics "homework" style problems involving the Lorentz transform. Because of that you don't have a good understanding about how physics will work in other frames besides the one that you draw.

You are chasing after ghosts. The laws of physics don't do what you want them to do. All that you have left is to hope that future discoveries will lead to new laws of physics that are not Lorentz symmetric.

Hi DaleSpam
There is only one constant in this universe and that is c
Using that constant and forming a perfect sphere of photons which can announce their presence by an exchange of energy. The sphere does exist.
All frames forming further spheres at a point concentricaly located on the first can be anywhere within their own spheres.
The propagation of the spheres are not dependent in any way on the speed and direction of the frames.
I have aknowledged Lorentz invarience and also frame contraction but as to the position of the frames within the spheres, who cares about Lorentz. It is purely frame related.
You have still not answered where a .999c frame is in its own circle of propagation of say 300 000km. I am sure you would say as that frames observer that you are at the center of the sphere. Staying with the bigger picture of the sphere, and anouncing your presence by a further event from your frame would prove that you are not anywhere near the center of the sphere and can no longer find your rabbit.
Every single moving frame observer within its own sphere will say they are at the center but just using our universal constant of c we know otherwise, so what has Lorentz to do with that.
How is Lorentz going to reposition your .999c frame to suit your position at the center. Copernicus would be turning in his grave.
 
  • #83
Reff said:
Hi DaleSpam
There is only one constant in this universe and that is c
Using that constant and forming a perfect sphere of photons which can announce their presence by an exchange of energy. The sphere does exist.
All frames forming further spheres at a point concentricaly located on the first can be anywhere within their own spheres.
The propagation of the spheres are not dependent in any way on the speed and direction of the frames.
I have aknowledged Lorentz invarience and also frame contraction but as to the position of the frames within the spheres, who cares about Lorentz. It is purely frame related.
You have still not answered where a .999c frame is in its own circle of propagation of say 300 000km. I am sure you would say as that frames observer that you are at the center of the sphere. Staying with the bigger picture of the sphere, and anouncing your presence by a further event from your frame would prove that you are not anywhere near the center of the sphere and can no longer find your rabbit.
Every single moving frame observer within its own sphere will say they are at the center but just using our universal constant of c we know otherwise, so what has Lorentz to do with that.
How is Lorentz going to reposition your .999c frame to suit your position at the center. Copernicus would be turning in his grave.
Reff, I already answered your question about how two observers, one stationary in an absolute ether rest state and another one traveling at 0.5c, would both think that they are in the center of an expanding sphere of light. Please go back to post #32, watch the animations and understand what I'm presenting there. I don't talk about Lorentz Transformation--that should make you happy. And remember, this is all done from an absolute ether rest state--no frames at all. You previously indicated that you needed more time to digest them. Please take the time now. And then please ask questions if you don't understand or if you don't agree.

By the way, I could have done similar animations for 0.999c but you don't have a screen large enough and with enough resolution for the animation to make any sense. And you wouldn't have the patience to watch those animations, as they take a very long time.
 
  • #84
Reff said:
Using that constant and forming a perfect sphere of photons which can announce their presence by an exchange of energy. The sphere does exist.
Certainly, that is not in dispute.

Reff said:
The propagation of the spheres are not dependent in any way on the speed and direction of the frames.
Nor is that.

Reff said:
I have aknowledged Lorentz invarience
If you actually understood Lorentz invariance then we wouldn't be having this conversation. Lorentz invariance is completely incompatible with an experimentally detectable absolute rest frame. For you to claim that you acknowledge Lorentz invariance is logically incompatible with the rest of your posts in this thread.

Reff said:
You have still not answered where a .999c frame is in its own circle of propagation of say 300 000km.
True, and although you still have not provided an experimental way to determine if your target is at absolute rest, you did at least make a sincere effort. So I will respond to that in a moment.

Reff said:
How is Lorentz going to reposition your .999c frame to suit your position at the center. Copernicus would be turning in his grave.
Actually, I think that Copernicus would be very comfortable with the principle of relativity and its logical implications.
 
  • #85
ghwellsjr said:
Reff, I already answered your question about how two observers, one stationary in an absolute ether rest state and another one traveling at 0.5c, would both think that they are in the center of an expanding sphere of light. Please go back to post #32, watch the animations and understand what I'm presenting there. I don't talk about Lorentz Transformation--that should make you happy. And remember, this is all done from an absolute ether rest state--no frames at all. You previously indicated that you needed more time to digest them. Please take the time now. And then please ask questions if you don't understand or if you don't agree.

By the way, I could have done similar animations for 0.999c but you don't have a screen large enough and with enough resolution for the animation to make any sense. And you wouldn't have the patience to watch those animations, as they take a very long time.
Hi ghwellsjr and DaleSpam
Thanks for replys and patience. I have looked at your animations once ghwellsjr and partly absorbed them so I owe you some comment in that respect, so I will be having another look to see if I can fully understand.
Thanks DaleSpam I will be back.
 
  • #86
Reff said:
You are at .999c and you create a sphere of photons and your right angle tube is about 10ft long. As your tube photon exits you create another event at the start of the tube.
Now I understand you to point to the start of the tube when I ask you where did the photon start from. If that is so I would ask you to step outside ond view the complete picture.
We see the first event sphere having expanded in perfect symetry and we locate the center of the sphere,( where all the photon reciprocals cross.) Now we look at your second event or marker event where you tell me the first event started from. The second sphere is is not centered on the first. The tube start point is now way out close to the edge of the sphere at .999c.
I will use units where c=1, and the standard Lorentz transform: http://en.wikipedia.org/wiki/Lorent...ormation_for_frames_in_standard_configuration

In the first frame
There is a moving tube (A) whose worldline is:
[tex]\left( t, -\frac{999}{1000}t, L, 0 \right)[/tex]
and a stationary tube (B) whose worldline is:
[tex]\left( t, 0, L, 0 \right)[/tex]
There is the sphere of light when the ends of the tubes are together
[tex]t^2=x^2+y^2+z^2[/tex]
There is a sphere of light which emanates at t=10 from B
[tex](t-10)^2=x^2+y^2+z^2[/tex]
And there is a sphere of light which emanates at t=223.663 from A
[tex]\left(t-\frac{10000}{\sqrt{1999}} \right)^2= \left(x+\frac{9990}{\sqrt{1999}} \right)^2+y^2+z^2[/tex]

Then by the Lorentz transform, in the second frame
B is a moving tube whose worldline is:
[tex]\left( t', \frac{999}{1000}t', L, 0 \right)[/tex]
and A is a stationary tube whose worldline is:
[tex]\left( t', 0, L, 0 \right)[/tex]
There is the sphere of light when the ends of the tubes are together
[tex]t'^2=x'^2+y'^2+z'^2[/tex]
There is a sphere of light which emanates at t'=10 from A
[tex](t'-10)^2=x'^2+y'^2+z'^2[/tex]
And there is a sphere of light which emanates at t'=223.663 from B
[tex]\left(t'-\frac{10000}{\sqrt{1999}} \right)^2= \left(x'-\frac{9990}{\sqrt{1999}} \right)^2+y'^2+z'^2[/tex]

So the results are the same in each frame. There is no experimental difference between the frame where one tube is stationary and the frame where the other is stationary.
 
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  • #87
=ghwellsjr;3442077]Reff, I already answered your question about how two observers, one stationary in an absolute ether rest state and another one traveling at 0.5c, would both think that they are in the center of an expanding sphere of light. Please go back to post #32, watch the animations and understand what I'm presenting there. I don't talk about Lorentz Transformation--that should make you happy. And remember, this is all done from an absolute ether rest state--no frames at all. You previously indicated that you needed more time to digest them. Please take the time now. And then please ask questions if you don't understand or if you don't agree.
Hi ghwellsjr
Yes neat little animations. Yes I understand how any moving frame observer would believe he was at the center of propagation by watching your animations. The third animation I found especialy inreresting. Look, for the moment could you just retain an open mind and consider a minor variation to to the third animation, purely using a logic which you would no doubt correct if it broke any laws.
Just for a moment could we go to your first animation. Would it be reasonable to mentaly mark the path of a few photons starting from the man and finishing at the mirrors, just simply the radius from the man to the sphere. I presume you are ok that they mark the path of the only constant in the universe--c
Now can we use the third animation and use both stick men and the blue sphere. I am interested in the propagation of the blue sphere.Both men were together at the moment of the event and propagation progressed independently of both men but the first--green man remained concentricaly centered on the sphere,
Start the animation and watch to the point where the red man receives the return reflection and determines he is the center of the blue sphere. If red man creates a marker event right then, can we see a red man assymetry to the blue sphere.
As a moving man, red man is progressing from left to right and is following a left to right track of a photon from his event which coincided with the green man. He is moving at .5c and so he will be half way along that c radius track.
He has a table, the surface of which is flat face to the direction of travel and we can simply indicate this by dropping a line from his head verticaly down and off the screen. This line representing the edge of the table moving with the red man.
Now go back to the original blue sphere event. It is adjacent to the edge of the table.
Now propagate the sphere slightly and move red man and his table. now scribe the path of a photon to what is now an intersecting line between the sphere and the table. Now propagate a little more and extend the radius line, it will intersect the sphere again. repeat the exercise in increments as many times as you wish. It is always the same photon on the end of the radius and on the surface of the table. During propagation and frame movement, that individual photon will complete a full table crossing of the moving frame table. Its speed is always the universal constant of c, like all the other photons on the spheres radius. Now consider the photon on the end of that one radius on the surface of the table is only in an intersecting state and while it moves at c on the radius just like any other radius in the sphere the intersection progress is less than c
I hope you can follow that.
Do you use an animation programme.
Your green man s tabletop crossing photon is not a table top intersecting photon so it crosses the table at c the absolute. Can you see there is no time dilation for him. Simply, a frame at c is fully time dilated-- there is no crossing photon. A table with your green man is fully at an absolute undilated time because his tabletop crossing photon must cross at c.
You might be able to relate this to my geometry.
Like your red man, any amount of frames creating a sphere from the green man will leave a concentric sphere based on the green man.
The green man must be inertial and in a time related state, so what would you call that state. I would call it absolute rest. Is there a faster clock than green mans anywhere.
 
  • #88
Reff, how do you think things are in the red man's frame?
 
  • #89
Reff said:
ghwellsjr said:
Reff, I already answered your question about how two observers, one stationary in an absolute ether rest state and another one traveling at 0.5c, would both think that they are in the center of an expanding sphere of light. Please go back to post #32, watch the animations and understand what I'm presenting there. I don't talk about Lorentz Transformation--that should make you happy. And remember, this is all done from an absolute ether rest state--no frames at all. You previously indicated that you needed more time to digest them. Please take the time now. And then please ask questions if you don't understand or if you don't agree.

By the way, I could have done similar animations for 0.999c but you don't have a screen large enough and with enough resolution for the animation to make any sense. And you wouldn't have the patience to watch those animations, as they take a very long time.
Hi ghwellsjr
Yes neat little animations. Yes I understand how any moving frame observer would believe he was at the center of propagation by watching your animations. The third animation I found especialy inreresting. Look, for the moment could you just retain an open mind and consider a minor variation to to the third animation, purely using a logic which you would no doubt correct if it broke any laws.
Just for a moment could we go to your first animation. Would it be reasonable to mentaly mark the path of a few photons starting from the man and finishing at the mirrors, just simply the radius from the man to the sphere. I presume you are ok that they mark the path of the only constant in the universe--c
Now can we use the third animation and use both stick men and the blue sphere. I am interested in the propagation of the blue sphere.Both men were together at the moment of the event and propagation progressed independently of both men but the first--green man remained concentricaly centered on the sphere,
Start the animation and watch to the point where the red man receives the return reflection and determines he is the center of the blue sphere. If red man creates a marker event right then, can we see a red man assymetry to the blue sphere.
Yes, we can see that the red man is not in the center of the blue sphere but he cannot see that. He has exactly the same experience as the green man. The only difference between them is that the green man sees the red man moving to his left and the red man sees the green man moving to his right.
Reff said:
As a moving man, red man is progressing from left to right and is following a left to right track of a photon from his event which coincided with the green man. He is moving at .5c and so he will be half way along that c radius track.
He has a table, the surface of which is flat face to the direction of travel and we can simply indicate this by dropping a line from his head verticaly down and off the screen. This line representing the edge of the table moving with the red man.
Now go back to the original blue sphere event. It is adjacent to the edge of the table.
Now propagate the sphere slightly and move red man and his table. now scribe the path of a photon to what is now an intersecting line between the sphere and the table. Now propagate a little more and extend the radius line, it will intersect the sphere again. repeat the exercise in increments as many times as you wish. It is always the same photon on the end of the radius and on the surface of the table. During propagation and frame movement, that individual photon will complete a full table crossing of the moving frame table. Its speed is always the universal constant of c, like all the other photons on the spheres radius. Now consider the photon on the end of that one radius on the surface of the table is only in an intersecting state and while it moves at c on the radius just like any other radius in the sphere the intersection progress is less than c
I hope you can follow that.
I think what you are saying is that as we watch the progress of a photon moving "downward" from the red man's moving position, it will appear to us that it is traveling at c along a diagonal, and we could say that it represents a legitimate photon in the green man's experience but from the red man's point of view we would have to say that it is traveling much slower than c because it is taking so much longer to get down to the mirror below him. But remember, time is going slower for the red man so from his point of view when he calculates the speed of the photon (if he could possibly know where it was), then he would believe that it was actually traveling at c.
Reff said:
Do you use an animation programme.
I use a general purpose program (LabVIEW) that is not specific to animation so it is a lot of work for me to produce these animations. I then use a screen capture utility (CamStudio) to make an avi that I can upload to YouTube.
Reff said:
Your green man s tabletop crossing photon is not a table top intersecting photon so it crosses the table at c the absolute. Can you see there is no time dilation for him. Simply, a frame at c is fully time dilated-- there is no crossing photon. A table with your green man is fully at an absolute undilated time because his tabletop crossing photon must cross at c.
You might be able to relate this to my geometry.
Like your red man, any amount of frames creating a sphere from the green man will leave a concentric sphere based on the green man.
The green man must be inertial and in a time related state, so what would you call that state. I would call it absolute rest. Is there a faster clock than green mans anywhere.
I have presented these animations from the point of view of LET which assumes an absolute ether rest state. I have not talked about frames at all. I don't know why you keep talking about frames when you believe in an absolute rest. What I'm trying to point out to you is that even from the viewpoint of LET and a single absolute ether rest state in which is c is constant and only in which c is constant, as long as you believe that an inertially moving observer will also measure the round-trip speed of light to be c (like in the real world), which you say you do because you agreed that my animations illustrate how both men will think they are in the center of the expanding sphere of light, then you can follow the interpretation of LET which assumes the actual real existence of an absolute ether rest state. In LET, the moving observer experiences time dilation and length contraction along the direction of motion through the ether. LET affirms that the green man is really stationary in the ether and the red man is really moving through the ether but it also affirms that the red man experiences everything the same way the green man does. In other words, the red man has every reason to believe that he is the one that is stationary in the ether and that it is the green man who is moving through the ether and exeriencing time dilation and length contraction and whose photons are bouncing off his mirrors at different times and whose photons are slowed down in some cases and speeded up in others.

So the question is: how can the green man prove that he really is stationary in the ether, even if he is. How can he tell? How can the red man prove that he is moving in the ether, even if he is? If the red man wants to believe that he is stationary in the ether, even if he isn't, how could the green man prove that he is wrong? How could you prove that he is wrong?

Remember, I said that the only difference between what the two men are experiencing is which direction the other one is traveling. Do you believe that?
 
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  • #90
DaleSpam said:
Reff, how do you think things are in the red man's frame?

Hi DaleSpam
First thanks for the maths posting. I am a little confused re
There is a moving tube (A) whose worldline is:

and a stationary tube (B) whose worldline is:

There is the sphere of light when the ends of the tubes are together

I am thinking right now that your maths is impressive but I am not to sure we are understanding each other. The moving frame observer I am sure would believe he is the center of propagation. I am trying to suggest athough he believes this, he is not and using a little geometry I predict his time dilation within a scale drawing of a 20 cm sphere. If we use
ghwellsjr's neat animation-- the third one, green man and red man we see red mans blue sphere propagating around green man identical to green man and red man believing he is at the center of the sphere when the reflection returns. I am saying a marker event from red man is not centered on the green man. Now, am I to believe a sphere made up of the only constant in the universe c, ie any radius in the sphere, and thus its perfect symetry is superceded by red mans belief. Red man in 200mm at .999c is not at the center of the sphere All photons within the sphere move at c. He is .999 along one absolute--and constant radius
The one photon which can cross his tabletop is not crossing at c, in is intersecting at less than c. I hope you have seen that in my geometry.
The whole basis of the geometry is that the moving frame is not centered on propagation, which to me is a logical step to predict the crossing speed of the tabletop intersecting photon. The crossing speed is directly related to the frames time dilation and that works fine.
I don't need every frame to believe they are the center of propagation, to do so violates the only constant.
Re
Reff, how do you think things are in the red man's frame?
Y 09:47 AM
I have a feeling I would like to answer that but I am not quite sure what you want.
 
  • #91
ghwellsjr said:
Yes, we can see that the red man is not in the center of the blue sphere but he cannot see that. He has exactly the same experience as the green man. The only difference between them is that the green man sees the red man moving to his left and the red man sees the green man moving to his right.
Yes I absolutely, agree, that we can see the red man is NOT in the center of the blue sphere and as you say--"but he cannot see that" That is what it is all about, I use this assymetry for direct calculation of his frames time dilation. Who cares what green and red men think is happening when they are ignoring the big picture and experiencing an abberation


I think what you are saying is that as we watch the progress of a photon moving "downward" from the red man's moving position, it will appear to us that it is traveling at c along a diagonal, and we could say that it represents a legitimate photon in the green man's experience but from the red man's point of view we would have to say that it is traveling much slower than c because it is taking so much longer to get down to the mirror below him. But remember, time is going slower for the red man so from his point of view when he calculates the speed of the photon (if he could possibly know where it was), then he would believe that it was actually traveling at c.

Absolutely, I think you are beginning to understand the geometry, and yes the photon is taking longer to reach a mirror and yes he will measure c because he has no option but to do so. Every movement in red mans frame is directly in proportion to the crossing---- diagonal photon. No photon can cross faster because it would violate our only constant c. Try crossing one. Every single photon in red mans and green mans frames-- is moving radialy at c from the center of the blue sphere so who cares where any frame of any direction is within the sphere unless you wish to calculate its time dilation.


I use a general purpose program (LabVIEW) that is not specific to animation so it is a lot of work for me to produce these animations. I then use a screen capture utility (CamStudio) to make an avi that I can upload to YouTube.
Smart and neat.

I have presented these animations from the point of view of LET which assumes an absolute ether rest state. I have not talked about frames at all. I don't know why you keep talking about frames when you believe in an absolute rest. What I'm trying to point out to you is that even from the viewpoint of LET and a single absolute ether rest state in which is c is constant and only in which c is constant, as long as you believe that an inertially moving observer will also measure the round-trip speed of light to be c (like in the real world), which you say you do because you agreed that my animations illustrate how both men will think they are in the center of the expanding sphere of light, then you can follow the interpretation of LET which assumes the actual real existence of an absolute ether rest state. In LET, the moving observer experiences time dilation and length contraction along the direction of motion through the ether. LET affirms that the green man is really stationary in the ether and the red man is really moving through the ether but it also affirms that the red man experiences everything the same way the green man does. In other words, the red man has every reason to believe that he is the one that is stationary in the ether and that it is the green man who is moving through the ether and exeriencing time dilation and length contraction and whose photons are bouncing off his mirrors at different times and whose photons are slowed down in some cases and speeded up in others.

Yes, look I have a confusing ramble and use incorrect terminology on occasion which many quite rightly find confusing but on my side I have a raw unrefined view of relativity, not too bad at geometry and I worked it out myself and it works out fine. I was convinced on geometry alone and further so when a little maths also worked and even further so when it could be drawn precisely to scale.
I talk about frames as being a specific speed of an individual observer ie red mans and green mans as frames. and yes your green man is at absolute rest.
While I think about it-- green mans tabletop photon crosses at c and he can use any photon within his sphere to make a direct crossing of his table------ NO diagonal----NO intersection means no time dilation and thus an absolute time clock which will measure a non intersecting -- straight trajectory photon at c but at-- absolute rest . He will experience and believe the same as any other frame trying measuring c.


So the question is: how can the green man prove that he really is stationary in the ether, even if he is. How can he tell? How can the red man prove that he is moving in the ether, even if he is? If the red man wants to believe that he is stationary in the ether, even if he isn't, how could the green man prove that he is wrong? How could you prove that he is wrong?
Now there is a question to ponder but perhaps sometime in the future it may be done with clocks or interference patterns or sagnac or light shift --etc etc
I did read a while ago about "the impossibility of measuring the speed of light" mmmmmm
may be a message in that.



Remember, I said that the only difference between what the two men are experiencing is which direction the other one is traveling. Do you believe that
Yes I do believe that as long as it is said that they "believe" that too.
 
  • #92
Reff said:
I am thinking right now that your maths is impressive but I am not to sure we are understanding each other.
I am pretty sure that you are not understanding me, but after your posting the drawings I am confident that I am understanding you. Even if you cannot understand the math you can at least look at the equations in the different frames and see that they are essentially the same.

Reff said:
Now, am I to believe a sphere made up of the only constant in the universe c, ie any radius in the sphere, and thus its perfect symetry is superceded by red mans belief. Red man in 200mm at .999c is not at the center of the sphere
In his frame he IS at the center and green man is not.

So what makes green man's frame correct and red man's frame incorrect in your opinion? Simply because we chose to draw green man's frame? If so, then any frame is the absolute rest frame as long as we choose to draw it. Is that what you really want?

I think that the problem is that you don't even understand what "absolute rest" means. There are millions of ways to determine whether or not two things are moving relative to each other, and so far that is all any of your geometry has demonstrated. In order to experimentally determine if something is at absolute rest you need to perform an experiment where the identical experiment performed in different frames gives different results. That is simply not possible under the known laws of physics.
 
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  • #93
Reff said:
ghwellsjr said:
So the question is: how can the green man prove that he really is stationary in the ether, even if he is. How can he tell? How can the red man prove that he is moving in the ether, even if he is? If the red man wants to believe that he is stationary in the ether, even if he isn't, how could the green man prove that he is wrong? How could you prove that he is wrong?
Now there is a question to ponder but perhaps sometime in the future it may be done with clocks or interference patterns or sagnac or light shift --etc etc
I did read a while ago about "the impossibility of measuring the speed of light" mmmmmm
may be a message in that.
Reff--this is the future.

I'm sure your read that it's impossible to measure the one-way speed of light. That just means that it's impossible to measure a state of absolute ether rest. Or to put it another way, any measurement that either man makes will lead him to believe that he is the one at rest in the absolute ether and the other one is moving through it. It's only when each man realizes that the other man has the same experience that they begin to realize that neither one of them can make an exclusive claim about an absolute ether rest state.
Reff said:
ghwellsjr said:
Remember, I said that the only difference between what the two men are experiencing is which direction the other one is traveling. Do you believe that?
Yes I do believe that as long as it is said that they "believe" that too.
Assuming that they do, which do you believe you are, the green man or the red man?
 
  • #94
=ghwellsjr;3446671]Reff--this is the future.

Are you serious
 
  • #95
Reff, this is at least the second time you have mentioned the Sagnac effect as something that might identify an absolute ether rest state and those experiments were done a centure ago. The Sagnac effect is used in inertial guidance systems to measure rotational acceleration. Accelerations are absolute, not relative. This has nothing to do with identifying an absolute rest state. Both Special and General Relativity have passed every test that is thrown at them and they always pass with flying colors. How many more centuries do you think it will take before some experiment will prove them wrong?

But that's beside the point. You have been taking a different position in this thread, which is that right now, you know a way to prove that an absolute rest state exists, even if you cannot locate it. Your position has been that if photons travel at c in one frame of reference, those same photons cannot travel at c in another frame of reference moving with respect to the first one, correct?
 
  • #96
ghwellsjr said:
Is the purpose of your diagram to graphically determine the time dilation factor as a function of speed? Would this diagram, where I called the time dilation factor "age" work? At a speed of .8c the time dilation is .6:

attachment.php?attachmentid=32565&amp.png

I never noticed that the equation for time dilation factor was so... circular.
 
  • #97
Reff said:
I believe we have established that a sphere of photons from a zero time event is---Not frame dependent---
Now when I ask you where the right angle photon originated from in a moving frame, you then make it---- frame dependent---.

I believe you cannot have it both ways to suit.

Oh, it is both ways, exactly. The sphere is not frame dependent, but the angles ARE frame dependent. The angles are frame dependent even in Galilean relativity. If I throw an object off a truck, it will appear to be going at a different angle than you would see it if you were standing still.

ghwellsjr said:
By the way, I could have done similar animations for 0.999c but you don't have a screen large enough and with enough resolution for the animation to make any sense. And you wouldn't have the patience to watch those animations, as they take a very long time.

I have a flash demo that let's you set the speed up to .99c if that helps.

http://www.wiu.edu/users/jdd109/stuff/relativity/Circle.swf

and another one which sort of demonstrates the angle question:

http://www.wiu.edu/users/jdd109/stuff/relativity/gardner.swf

I just want to say to gh, though: I didn't realize that you had made those animations before you saw mine! (I didn't see that you had made similar animations until this afternoon.) It is a good thing when two people independently come up with the same results.
 
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  • #98
ghwellsjr said:
I have presented these animations from the point of view of LET which assumes an absolute ether rest state. I have not talked about frames at all.

On further thought, what are you saying here? I'm not entirely certain what the LET idea entails. Does LET assume an absolute ether rest state, or an observer dependent rest state? Or, regardless, don't your animations suggest observer dependence, rather than any absolute nature of the spacetime?

Or are you just saying that there is no detectable difference between the two?
 
  • #99
ghwellsjr said:
It's only when each man realizes that the other man has the same experience that they begin to realize that neither one of them can make an exclusive claim about an absolute ether rest state.

Assuming that they do, which do you believe you are, the green man or the red man?

Ahh, I see. You came back to it. How very dialectical of you!
 
  • #100
Both Special and General Relativity have passed every test that is thrown at them and they always pass with flying colors. How many more centuries do you think it will take before some experiment will prove them wrong?

Sorry I have been slow
Any theory should be able to withstand any amount of challenge and retain its integrity, no matter how long the theory is generaly acceptable, rather like the flat Earth society time v integrity, or the Earth being the center of all things, time v integrity or us being the only galaxy in the universe.
Are you suggesting time gives a theory integrity then I absolutely disagree.
I believe you are ignoring some of the facts here including some of the evolution of SR.
If we go back to the 20s when the formation of Lorentz was proposed, do we not find many pysicists hard at work trying to find a purely mechanical interpretation of SR laws
and in that process had many problems. Now I say that if a mechanical theory were introduced at the same time as Lorentz and the man himself ( Einstein) were to make an assessment of both--
which one would Einstein himself have chosen
During his consideration of two theories would he have debunked the mechanical by using elements of the Lorentz theory.--- I don't think so
Would Einstein have been impressed by the Lorentz theory formulated on " substracting from the aether its mechanical and from matter its electromagnetic qualities" as having any form of validity. ----I don't think so
Lorentz formulated a theory that cannot be challenged if we use the time v validity formula
Without using the Lorentz rabbit can you prove that absolute rest does not exist.
How about using the sort of logical thinking that Einstein would have used against a mechanical SR theory, to say one will never exist closes an open mind.
 
  • #101
DaleSpam said:
I am pretty sure that you are not understanding me, but after your posting the drawings I am confident that I am understanding you. Even if you cannot understand the math you can at least look at the equations in the different frames and see that they are essentially the same.

In his frame he IS at the center and green man is not.

So what makes green man's frame correct and red man's frame incorrect in your opinion? Simply because we chose to draw green man's frame? If so, then any frame is the absolute rest frame as long as we choose to draw it. Is that what you really want?

I think that the problem is that you don't even understand what "absolute rest" means. There are millions of ways to determine whether or not two things are moving relative to each other, and so far that is all any of your geometry has demonstrated. In order to experimentally determine if something is at absolute rest you need to perform an experiment where the identical experiment performed in different frames gives different results. That is simply not possible under the known laws of physics.
Hi DaleSpam
Sorry I have been slow to respond.
Yes I do see the belief of red and green men being at the center but just in a "belief" sense.
Please have a look at my non geometric post number 101.
I am pleased that you understand my geometry even if you do not agree. Can I just remind you of an address by Einstein himself in the 20s when he made the statement
"The aether must be in the nature of a solid body, because transverse waves are not possible in a fluid but only in a solid. Thus physicists were bound to arrive at the theory of a quasi ridgid luminiferous aether"
Now if you understand my geometry, you will be able to see from my point of view at least, that in that statement there is a fundamental mistake. I have mentioned this in a previous post. I believe you did not relate the geometry to it at that time but now you can see how it works.
Now the many physicists of that time were out to design a mechanical theory, influenced by that very transverse wave belief.
Without going back into explaining the geometry, you should now see how I believe transverse waves are formed.
If it were proved that absolute rest does exist would you drop Lorentz.
If Einstein had two papers to assess at the time of Lorentz and the mechanical theory worked fine, Lorentz would have been dropped.
 
  • #102
Reff said:
Sorry I have been slow
Any theory should be able to withstand any amount of challenge and retain its integrity, no matter how long the theory is generaly acceptable, rather like the flat Earth society time v integrity, or the Earth being the center of all things, time v integrity or us being the only galaxy in the universe.
Are you suggesting time gives a theory integrity then I absolutely disagree.
I believe you are ignoring some of the facts here including some of the evolution of SR.
If we go back to the 20s when the formation of Lorentz was proposed, do we not find many pysicists hard at work trying to find a purely mechanical interpretation of SR laws
and in that process had many problems. Now I say that if a mechanical theory were introduced at the same time as Lorentz and the man himself ( Einstein) were to make an assessment of both--
which one would Einstein himself have chosen
During his consideration of two theories would he have debunked the mechanical by using elements of the Lorentz theory.--- I don't think so
Would Einstein have been impressed by the Lorentz theory formulated on " substracting from the aether its mechanical and from matter its electromagnetic qualities" as having any form of validity. ----I don't think so
Lorentz formulated a theory that cannot be challenged if we use the time v validity formula
Without using the Lorentz rabbit can you prove that absolute rest does not exist.
How about using the sort of logical thinking that Einstein would have used against a mechanical SR theory, to say one will never exist closes an open mind.
Lorentz's Ether Theory was developed prior to Einstein's Special Relativity. The two theories are mutually compatible with each other. They make the same predictions and they use the same formulas and equations. It is not possible to prove one correct and the other incorrect. They stand or fall together. It is not possible to choose one over the other based on any measureable or observable criterion. You can neither prove nor disprove that an absolute rest exists. It is purely a philosophical choice. If one of the theories is correct, then the other one must also be correct. In fact, if the Theory of Special Relativity is correct, in the sense that it accurately describes reality, then that alone proves that it is impossible to prove that an absolute ether rest frame cannot exist. The reason is that any arbitrary Frame of Reference that you choose to select will have all the characteristics of an absolute ether rest state. On the other hand, if Lorentz Ether Theory is correct, in the sense that it accurately describes reality, then that alone proves that it is impossible to prove that an absolute ether rest state must exist. If any measurement could identify an absolute ether rest state, then both theories would have to be abandoned.

Einstein was well aware of his choice between LET and SR and his argument was that if there is no measurement that can identify an absolute ether rest state, then the concept is useless. It's a matter of choosing the simpler theory because if you want to claim that there exists an absolute ether rest state, then you should, for consistency's sake, identify one by edict and do all your mathematics in that one frame.
 
  • #103
Reff said:
Without using the Lorentz rabbit can you prove that absolute rest does not exist.

The point is, if Maxwell's equations are correct, (and by corollary, the wave equation,) and the Principle of Relativity is also correct, then the only way to resolve the two is by using the Lorentz Transformations. As far as I know, there is no other way.

If you want to discard the Principle of Relativity, or Maxwell's equations, it would also be appropriate for you to come up with some experiment where one of those two things is obviously broken.

As far as I can tell, you are not producing any such physical experiment but are instead producing a thought experiment where a priori you're assuming that one or the other is broken.

There are advantages and disadvantages of using thought experiments; the advantage is that you can illustrate whether an idea is self-consistent or not. The disadvantage is that it doesn't necessarily model reality.
 
  • #104
Hi J Doolin
You have come in cold on this one but you seem to be well versed and have some interest.

QUOTE]JDoolin;3449101]Oh, it is both ways, exactly. The sphere is not frame dependent, but the angles ARE frame dependent. The angles are frame dependent even in Galilean relativity. If I throw an object off a truck, it will appear to be going at a different angle than you would see it if you were standing still. [/QUOTE]

I do believe your statement here but I am a fan of absolute rest, so presuming you are willing to discus that effect --

For a while in your first animation could you drop the mirrors and just look at the symetry of propagation and the point of sphere generation. I am just interested in the sphere and that it can be concentricaly generated by a frame moving at any speed and any direction. The point which generated the sphere must be somewhere within the sphere. This is my not frame dependent. If all moving frame events are created concentricaly to that point concentric to the first event, will they propagate concentricaly, I think so.
Now if we look at photons generated within the sphere, ie radial from the event, right out to the edge of the sphere, then I absolutely agree that the radial lines formed by the track of the photons and their interface with a moving frame are also frame dependent.
If we go back to the propagating sphere and put in a frame of .999c and allow it to propagate 1km I believe contrary to Lorentz that the frame is no longer at the center of propagation, irrespective of the frame observers belief. The frame has moved 999mtrs along the trajectory of the photon heading in the same direction of the frame. This is where I understand Lorentz is saying the frame is at the center of propagation and thus frame dependent. I don't see this but yes the interface in photon angles is a very relevant frame dependent.
Your animation which moves up to .999c is great but it does not show what I need to know and that is, after say 1km of sphere propagation, and without mirrors, the .999c frame creates a second event to indicate that he is still at the center of the first sphere. so is he?
 
  • #105
if you want to claim that there exists an absolute ether rest state, then you should, for consistency's sake, identify one by edict and do all your mathematics in that one frame.
[/QUOTE]
Yes for sure, been there done that, the maths work fine. -- all based on that point between two opposite photons.
 

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