Did I Misuse the Parallel Axis Theorem for Polar Moment of Inertia?

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In summary, the article discusses the proper application of the Parallel Axis Theorem (PAT) in calculating the polar moment of inertia. It emphasizes that while the PAT can be used to find the moment of inertia about an axis parallel to one through the centroid, care must be taken to ensure that the correct distances and axes are used. Misapplication can lead to incorrect results, particularly in complex shapes. The article provides examples to illustrate correct usage and highlights common pitfalls to avoid.
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Usaid3112
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Homework Statement
the centroidal moment of inertia about the x axis for the area shown is 142.41 cm^4. Most nearly what is the centroidal polar moment of inertia. The answer is C. What confuses me is that the solution says that the Y axis passes through the Centroid of the shape so parallel axis theorem shouldn't be applicable. Clarifications would be appreciated.
Relevant Equations
Iyc= Iy + Ad^2
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The apparent correct answer given in the textbook is J=330 cm^4. I ended up using parallel axis theorem as I could not see how the Y axis passed through the centroid as the given y axis is completely towards the left side of the whole shape.My attempt at this question:-
 

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Usaid3112 said:
The apparent correct answer given in the textbook is J=330 cm^4. I ended up using parallel axis theorem as I could not see how the Y axis passed through the centroid as the given y axis is completely towards the left side of the whole shape.My attempt at this question:-
The centroidal moment of inertia "about the x-axis" is given to be IXC = 142.41 cm4. You can check that this is the moment of inertia about an axis parallel to the x-axis that passes through the centroid. So, it is not the moment of inertia about the x-axis as drawn in the figure.

The same applies to IYC. So, you would not use the parallel axis theorem in calculating IYC.

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