Discover the Tangential Velocity for the Wall of Death Amusement Park Ride

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The Wall of Death ride operates by spinning a vertical cylinder, allowing riders to remain against the wall due to friction when the floor drops away. The radius of the cylinder is 3.9 meters, and the coefficient of static friction is 0.35. To prevent riders from slipping, the necessary centripetal acceleration is calculated as 3.43 m/s², derived from the frictional force equating to the weight of the riders. The discussion emphasizes the relationship between centripetal force and normal reaction, guiding the calculation of minimum tangential velocity. Understanding these dynamics is crucial for ensuring rider safety on the attraction.
am08
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The Wall of Death in an amusement park is comprised of a vertical cylinder that can spin around the vertical axis. Riders stand against the wall of the spinning cylinder and the floor falls away leaving the riders held up by friction. The radius of the cylinder is 3.9 m and the coefficent of static friction between the rider and the wall is 0.35. Find the tangential velocity of the spinning wall necessary so that the riders do not slip down the wall.

Centripetal Acc = (.35*9.8) = 3.43 m/s^2

How do I apply that to find the tangential velocity?
 
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am08 said:
Centripetal Acc = (.35*9.8) = 3.43 m/s^2

How did you get this??

Centripetal force is the normal reaction N. The frictional force F must be equal to weight. You should know the relationship between F and N when static friction is max. Now write the correct eqn for minimum tangential velocity.
 

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