Does a Tire's Point of Contact Have Zero Tangential Acceleration?

AI Thread Summary
A tire's point of contact with the ground has zero velocity relative to the ground, and at that instant, its tangential acceleration is also zero. This occurs because the point transitions from negative to positive acceleration as it moves through the contact point. The tangential acceleration is not zero relative to the center of the wheel, but it is zero when considering the fixed coordinate system of the ground. The discussion clarifies that the acceleration changes magnitude but equals zero at the moment of contact. Understanding this concept helps resolve confusion about the motion of the tire's contact point.
elyons
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A car is moving foreword with a constant acceleration. I know the point of the tire in contact with the ground has a velocity of 0 (relative to the ground). Is the tangential acceleration at this point also zero? I came across an example problem in my text where this occurs and and it does not make sense to me conceptually. If someone could give me a brief explanation I would very much appreciate it. Thanks.
 
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What is the motion of the point of contact immediately before and immediately after it it makes contact?
 
So the acceleration hits zero because it is changing from negative to positive but has an identical magnitude on both side of the point of contact? So the point has a tangential acceleration relative to the center of the wheel just not to the ground?
 
elyons said:
So the acceleration hits zero because it is changing from negative to positive but has an identical magnitude on both side of the point of contact? So the point has a tangential acceleration relative to the center of the wheel just not to the ground?
What is changing from negative to positive?
 
The tangential acceleration in terms of a fixed coordinate system. The velocity is accelerated to 0 as a point on the tire approaches the point of contact on the ground and after it reaches the point it is accelerated positively to increase the velocity of that point again. So at the instant the point is in contact with the ground the acceleration is 0. Sorry if I am not explaining my question clearly but writing it out like this I think I have worked it out so this helped! Thanks.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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